Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

A convex mirror is used to form an image of a real object at a finite distance. The image (i) always lies between the pole and the focus (ii) is diminshed in size (iii) is erect (iv) is real

Answer»

I,II
ii,iii
iii,iv
I,ii,iii

Answer :D
2.

p-V plots for two gases during adiabatic processes are shown in the figure. Plots 1 and 2 should correspond respectively to

Answer»

(a) `H_e` and `O_2`
(b) `O_2` and `H_e`
(c) `H_e` and `A_r`
(d) `O_2` and `N_2`

Solution :In ADIABATIC process:
slope of p-V GRAPH, `(dp)/(DV)=-gammap/V`
`slope prop gamma` (with negative SIGN)
From the GIVEN graph,
`(slope)_2 gt (slope)_1`
`:.` `gamma_2 gt gamma_1`
Therefore, 1 should correspond to `O_2(gamma=1.4)` and 2 should correspond to `H_e(gamma=1.67)`.
Hence, the correct option is (b).
3.

What is the magnitude of angular velocity for a geosynchronous satellite.

Answer»

SOLUTION :W = `2pi/T` = `(2xx3.14)/(24xx60xx60)` = `7.3xx10^-5 RAD s^-1`
4.

If gamma_(R) , gamma_(A) and gamma_(V) represent the coefficient of real expansion of a liquid, coefficient of apparent expansion, n of the liquid and coefficient of cubical expansion of the material of the vessel respectively, then which of the following is/are correct?

Answer»

`gamma_(A)` is +ve
`gamma_(A)` is -ve
`gamma_(A)` is ZERO
`gamma_(A)` is NEVER -ve

Answer :A::B
5.

Two car travelling towards each other on a straith road at velocity 10 ms^(-1) and 12 ms^(-1) respectively. When they are 150 m apart, both the drivers apply their brakesand each car decelerates at 2 ms^(-2) until it stops. How far apart will they be when both of them come to a halt ?

Answer»

Solution :Let `x_(1)` and `x_(2)` be the distance travelled by the car before they stop under deceleration. From IIIRD EQUATION of motion
`V^(2)=u^(2)+2as`
`rArr 0=(10)^(2)-2xx2x_(1) rArr x_(1)=25 m`
and `0 = (12)^(2) - 2xx2x_(2) rArr x_(2)=36 m`
Total distance covered by the two CARS
`x_(1)+x_(2)=25+36=61 m`
Distance between the two cars when they stop
`=150-61=89 m`
6.

Whatextinguishes a fire most quickly?

Answer»

COLD WATER
BOILING water
HOT water
Ice

Answer :B
7.

Passage-I : A rod AB length 2m and mass 2kg is lying on a smooth horizontal x-y plane with its centre at origin O as shown in figure. An impulse J of magnitude 10Ns is applied perpendicular to AB at end A. If the rod is hinged at B and instead of impulse J, a point masses of 1 kg moving with a speed 10m/s collides at A and sticks to it, then find angular velocity of the rod just after the collision

Answer»

4 rad/s
3 rad/s
2 rad/s
1 rad/s

Answer :B
8.

Passage-I : A rod AB length 2m and mass 2kg is lying on a smooth horizontal x-y plane with its centre at origin O as shown in figure. An impulse J of magnitude 10Ns is applied perpendicular to AB at end A. Find the coordinates of point A of the rod after time t=pi//45 of the impact if the centre of mass of the rod is taken as origin at that time.

Answer»

`((SQRT(3))/(2)m,1/2m)`
`((sqrt(3))/(2)m,1m)`
`(3/4m,3/2m)`
NONE of these

ANSWER :A
9.

Passage-I : A rod AB length 2m and mass 2kg is lying on a smooth horizontal x-y plane with its centre at origin O as shown in figure. An impulse J of magnitude 10Ns is applied perpendicular to AB at end A. The distance of point P from the centre of the rod which is at rest just after the impact is

Answer»

1/4 m
1/2 m
1/3 m
2/3 m

Answer :C
10.

A block of mass m and a cylinder of mass 2m are released on a rough inclined plane, inclined at angle theta=45^(@) with the horizontal. The coefficient of friction for all the contact surface is 0.5 Find the accelerations of the block and the cylinder. Assume pure rolling 3g//xsqrt(2) where 'x' is

Answer»


ANSWER :5
11.

Discuss stationary waves in pipe and explain types of pipes.

Answer»

Solution :In air column inside pipe, stationary waves are produced due to REFLECTION of waves of definite frequency PIPES are of two types :
(1) The pipe which is opened from both ends is CALLED open pipe. E.g. : Flute.
(2) The pipe which is opened from one end and CLOSED from another end then it is called closed pipe. E.g.: Partially filled water in tube.
12.

What is meant by 'Mean positions of atoms' ?

Answer»

Solution :The interaction between the atoms, they POSITION themselves at a PARTICULAR interatomic DISTANCE. This position of atoms in this bound condition is called their MEAN positions.
13.

A 2kg body is dropped from height of lm onto a spring of spring constant 800 N/m as shown in the figure. A firctional force equivalent to 0.4 kg-wt acts on the body. The speed of the body just before striking the spring will be :

Answer»

1 m/s
2 m/s
3 m/s
4 m/s

ANSWER :D
14.

A coolie with load on his head is walking on a horizontal platform. What is work done ?

Answer»

SOLUTION :`W=Fs costheta=Fs COS90^(@)=ZERO .`
15.

Three identical point masses eachof m are placed at the corners of an equilateral triangle of side a choose The correct statement (s)

Answer»

The GRAVITATIONAL field intensity at centroid of the triangle is zero.
The gravitational POTENTIAL at centroid of the triangle is zero.
The gravitational fieldintensity at the mid point of any side is `(4GM)/(3a^(2))`
The potential energy of the system is `(3GM^(2))/(a )`

ANSWER :A::C::D
16.

Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e. F prop 1//r^(3), but still remaining a central force. Then

Answer»

Keplers LAW of areas STILL holds
Keplers law of PERIOD still holds
Keplers law of areas and period still HOLD
Neither the law of areas, nor the law of period still holds

ANSWER :D
17.

Find the time period of the oscillation of mass m in figure. What is the equivalent spring constant of the pair of springs in each case ?

Answer»

SOLUTION :`SQRT((m)/(k_1 + k_2))`
18.

Find the time period of the oscillation of mass m in figure. What is the equivalent spring constant of the pair of springs in each case ?

Answer»

SOLUTION :`2pisqrt(m/(k_1 + k_2)) `
19.

Velocity vector and acceleration vector in a uniform circulat motion are related as

Answer»

both in the same direction
perpendicular to each other
both in OPPOSITE direction
not RELATED to each other

Answer :B
20.

Explain spring ball model of elastic behaviour of solids.

Answer»

Solution :We know that in a solid each atom or molecule is surrounded by neighboring atoms or molecules.
These are bonded together by interatomic or intermolecular forces and stay in a stable equilibrium position.
When a solid is deformed, the atoms or molecules are displaced from their equilibrium positions causing a change in the interatomic distances.
When the deforming force is REMOVED the interatomic forces tend to drive them back to their ORIGINAL positions and the body regains its original SHAPE and size.
The restoring MECHANISM can be visualised by taking a model of spring-ball system as shown in figure. Here the balls represents atoms and spring represent interatomic forces. If you try to displace any ball from its equilibrium position, the spring system TRIES to restore the ball back to its original position.
Thus, elastic behaviour of solid can be explained in terms of microscopic nature of the solid.
21.

A suitcase is gently dropped on a conveyor belt moving at 3 m/s. If the coefficient of friction between the belt and the suitcase is 0.5. Find the displacement of suitcase relative to conveyor belt before the slipping between the two is stopped. (g = 10 m//s^(2))

Answer»

`2.7m`
`1.8m`
`0.9m`
`1.2m`

ANSWER :C
22.

In an experiment four quantities a,b,c and d are measured with percentage error 1% 2%, 3% and 4% respectively. Quantity P is calcualted as follows : P=(a^(3)b^(2))/(cd)% error in P is

Answer»


ANSWER :0.14
23.

The ratio of radii of two spheres is 1:2, when they are dropped in a viscous liquid the ratio of their terminal speed is

Answer»

`1:1`
`2:1`
`1:2`
`1:4`

ANSWER :D
24.

The banking angle for a curved road of radius 490 m for a vehicle moving at 35 ms^(-1) is

Answer»

`tan^(-1) ( 0.25 )`
` tan ^(-1) ( 0.35 )`
`tan^(-1) (1)`
`tan^(-1) ( 0.65 )`

SOLUTION :Here `, V= 35 ms^(-1), r- 490m`
` thereforetantheta= (v^2)/(rg ) = ((35 )^2)/( 490 xx 9.8) = 0.25`
` ortheta = tan^(-1) ( 0.25 )`
25.

Monoatomic, diatomic and triatomic gases whose initial volume and pressure are same, arecompressed till their volume becomes half the initial volume.

Answer»

If the compression is ADIABATIC then MONOATOMIC gas will have MAXIMUM final pressure.
If the compression is adiabatic then TRIATOMIC gas will have maximum final pressure.
If the compression is adiabatic then their final pressure will be same.
If the compression is ISOTHERMAL then their final pressure will be different.

Answer :A
26.

The range of attraction between molecules is of the order of

Answer»

`10^(-6)m`
`10^(-9)m`
`10^(-12)m`
`10^(-15)m`

ANSWER :B
27.

Find the time period of the oscillation of mass m in figure. What is the equivalent spring constant of the pair of springs in each case ?

Answer»

SOLUTION :`2PI SQRT((m(k_1 + k_2))/(k_1 k_2))`
28.

(A) : A cyclist leans inwards while taking a turn, while a man sitting in a car leans outwards on a curve . ( R) : Centripetal acceleration is acting towards the centre of the curve.

Answer»

Both (A) and ( R) are ture and ( R) is the correct EXPLANATION of (A)
Both (A) and ( R) are TRUE and ( R) is not the correct explanation of (A)
(A) is true but ( R) is false
Both (A) and ( R) are false

ANSWER :A
29.

A particle of mass 'm' is at rest the origin at time t =0. It is subjected to a force F(t) = F_(0)e^("bt")in the X-direction

Answer»

the velocity of mat t = 1/b is `F_0/(MB)(1-1/e)`
the velocity of mat t = 2/b is `F_0/(mb) (1- 1/e^2)`
the velocity of m at TIME t is `F_0/(mb)(1-e^(-"BT"))`
None of the above

Answer :A::B::C
30.

Two simple harmonic motions are represented by the equation y_1 = 3(sqrt(3) cos 3 pi t + sin 3 pi t) and y_2 = 6 sin (6 pi t + pi//6)

Answer»

The ratio `A_1//A_2` of their amplitude is 1/2
The ratio `A_1//A_2` of their MAXIMUM velocities is `1//2`
The ratio `v_1//v_2` of their maximum velocities is 1/2
The ratio `v_1//v_2` of their maximum velocities is 2

Answer :B::C
31.

In stretching a wire, the amount of work done per unit volume of the wire is

Answer»

STRESS `TIMES` STRAIN
`1/3 times stress times strai N`
`(stress)/(strai n)`
`1/2 times stress times strai n`

ANSWER :D
32.

A stone is projected vertically up from the ground with velocity 40ms^(-1). The interval of time between the two instants at which the stone is at a height of 60m above the ground is (g=10ms^(-2))

Answer»

4s
6s
8s
12s

Answer :A
33.

If the surface tension of solution of soap in wateris 35 dyenes/cm,calculate the work done to form an soap bubble of diameter 14 mm with that solution.

Answer»

Solution :SURFACE tension `S=35"dyne"CM^(-1)=0.035Nm^(-1)`
Radius of the bubble `(r)=(14mm)/2=7mm`
`=7XX10^(-3)m`
`W=A(S)=8pir^(2)SimpliesW=8xx22/7xx49xx10^(-6)xx0.035`
`W=4.312xx10^(-6)J`
34.

Torques of equal magnitude are applied to a hollow cylinder and a solid sphere , both having the same mass and radius . The cylinder is free to rotate about its standard axis of symmetry , and the sphere is free to rotate about an axis passing through its centre . Which of the two will acquire a greater angular speed after a given time .

Answer»

Solution :Let M and R be mass and radius of the hollow cylinder and the solid SPHERE , then
Moment of INERTIA of the hollow cylinder about its axis of SYMMETRY , `I_(1) = MR^(2)`
Moment of inertia of the solid sphere about its axis through its centre `I_(2) = (2)/(5) MR^(2)`
Torque `TAU = I alpha`
where `alpha` is angular acceleration .
`I_(1) alpha_(1) = I_(2) alpha_(2)`
`(alpha_(2))/(alpha_(1)) = (I_(1))/(I_(2)) = (MR^(2))/((2)/(5) MR^(2)) = (5)/(2)`
`alpha_(2) = 2.5 alpha_(1) or alpha_(2) gt alpha_(1)`
From `omega = omega_(0) + alpha t` , we find that for given `omega_(0)` and `t , omega_(2) gt omega_(1)` , angular speed of solid sphere will be greater than the angular speed of hollow cylinder .
35.

In pure rolling motion of a ring(a) it rotates about instantaneous point of contact of ring and ground(b) its centre of mass moves in translatory motion only(c ) its centre of mass will have translatory as well as rotatory motion

Answer»

only a is CORRECT
a and C are correct
a and B are correct
a, b and c are correct

ANSWER :C
36.

1 g steam at 100^(@)C is passed in to an insulating vessel having 1 g of ice at 0^(@)C. Find the equlibrium temperature of the mixture, neglecting heat capacity of the vessel.

Answer»

SOLUTION :Heat AVAILABLE on steam (changes from steam to water) = mL = `1xx540` = 540 cal
Heat gained by ice to CHANGE into water at `0^(@)C` and then rise its temperature to `100^(@)C`
`m_("ice")L_("ice")+M_("water")S_(w)DeltaT=1xx80+1xx1xx(100-0)=180cal`.
The above CALCULATIONS show that some part of steam will condense to change the ice into water at `100^(@)C`. Let .x. is the mass of steam condensed, then
`x xx540=180orx=180/540=1/3g`
Final contents of the mixture : ice = 0 g
water = `1+1/3=4/3g,"steam"=1-1/3=2/3g`.
Final temperature of the mixture = `100^(@)C`
37.

Which of the following statements can be explained byNewton's second law of motion ?

Answer»

to stop a heavy body (say truck), greater force is needed than to stop a light body (say motorcycle) in the same TIME if they are moving with same speed
for a body of given mass, the greater the speed, the greater the opposing force to stop the body in a particular time duration
to change the momentum of a body by given value, the force required is independent of time
the same force acting on TWO DIFFERENT bodies for same time causes the same change in momentum for the different bodies

Answer :A::B::D
38.

Which type of waves are used in electron microscope ?

Answer»

SOLUTION :To measure very SMALL distance (like size of molecule) `(10^(-8) m "to" 10^(-10) m)` vernier callipers or screw gauge can not be used. Optical microscope uses visible light. WAVELENGTH of visible light is of the order of `4000Å`to `7000Å(1Å=10^(-10)m)`
Light has wave nature. Hence to measure (RESOLVE) length equal to size of visible light optical microscope can be used.
But it can not be used to measure (resolve) dimension LESS than `10^(-10)` m.
39.

A swimmer can swim in still water at of 10ms^(-1). While crossing a river his average speed is 6ms^(-1). If he crosses the river in the shortest possible time, what is the speed of flow of water?

Answer»

`16ms^(-1)`
`4ms^(-1)`
`60ms^(-1)`
`8ms^(-1)`

SOLUTION :The resultant velocity of SWIMMER must be perpendicular to speed of water to cross the river in a shortest TIME
`:.v_(s)^(2)=v^(2)+v_(w)^(2)`
`v_(w)^(2)=v_(s)^(2)-v^(2)=100-36=64"":.V_(w)=8m//s`
40.

A bullet of mass 2 g travellingwith a velocity f 500 ms^(-1) is fired into a block of wood of mass 1kg suspended from a string of 1 m length. If the bullet penetrates the block of wood and comes out with a velocity of 100 ms^(-1), find the vertical height through which the block of wood will rise ("assuming the value ofg to be" 10ms^(-2)).

Answer»

Solution :LET the masses of the bullet and the block be .m. and .M. respectively. Let their velocities after the impact be v and V respectively. Let the INITIAL velocity of the bullet be .U..
According to the law of conservation of linear momentum. Mu = mv + MV
Here `m = 2 xx 10^(-3) KG`,
`u = 500 ms^(-1), v = 100 ms^(-1)`
`(2xx10^(-3))xx500=(2xx10^(-3))xx100+(1xxV)`
`V = 0.8 ms^(-1)`.
When the block rises to a height of .h., according to the law of conservation of energy.
`(M + m)gh=(1)/(2)(M+m)V^(2)`
`i.e., h = (1)/(2) (V^(2))/(g) = ((0.8)^(2))/(2xx10)=0.032m`
41.

Heat of 20 K cal is supplied to the system and8400 J of external work is done on the system so that its volume decreases at constant pressure. The change in internal enrgy (J = 4200 J/kcal)

Answer»

`9.24xx10^(4)J`
`7.56xx10^(4)J`
`8.4xx10^(4)J`
`10.5xx10^(4)J`

ANSWER :A
42.

A man carried a load of 50 kg through a height of 40 m in 25s. If the power of the man is 1568 watt, find his mass.

Answer»


ANSWER :50 KG
43.

Explain why a horse cannot pull a cart and run in empty space.

Answer»

Solution :While trying to pull a cart, a horses PUSHES the ground backwards with a CERTAIN force at an angle. The ground offers an equal reaction in the opposite direction on the feet of the horse. The forward COMPONENT of this reaction is responsible for the motion of the cart. In empty space, there is no reaction and HENCE a horse can not pull the cart and run.
44.

The driver of a three-wheeler moving with a speed of 36 km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0 s just in time to save the child. If the mass of the three wheeler is 400 kg and the mass of the driver is 65 kg, the average retarding force on the vehicle is

Answer»

1000 N
1162 N
4650 N
465 N

Answer :B
45.

A person is standing on a platform rotating with an angular speed w, with stretched hands carrying equal masses each of m. Now he releases the masses such that they fall on the platform. The new angular velocity of platform would be:

Answer»

W
`w//2`
2W
`(2w//3)`

ANSWER :A
46.

Draw and explain the v to tgraphs for uniformly accelerated motion.

Answer»

Solution :Velocity-time graph for MOTION with CONSTANT acceleration are as following:

An object is moving in a POSITIVE direction with a positive acceleration, then graph (a) is obtained
An object is moving in positive direction with a negative acceleration, then graph (b) is obtained.
An object is moving in negative direction with a negative acceleration, then graph (c) is obtained.
An object is moving in positive direction till time `t_(1)` and then turning back and moving with the same negative acceleration. This is shown in graph (d).
An interesting feature of a velocity-time graph for any moving object is that the area under the CURVE represents the displacement over a GIVEN time interval.
47.

A system undergoes a cyclic process in whichit absorbs Q_(1)heat and gives out Q_(2)heat. The efficiency of the process is etaand the work done is W. Which of the following is false

Answer»

`W= Q_(1)-Q_(2)`
`eta=(W)/(Q_(1))`
`((1)/(eta))^(gamma-1)`
`eta=1-(Q_(2))/(Q_(1))`

Answer :C
48.

water of a river is striking the pillar of a bridge.Is work being done in this?

Answer»

SOLUTION :No,because there is no DISPLACEMENT
49.

What is the pressure in an ocean at a depth of 1000 m, if the density of water is1.024xx 10^(3)(kg)/m^(3) . Atmospheric pressure P. = 1.01 xx 10^(5)Pa.

Answer»

Solution :Total pressure=Atmospheric pressure +Pressure exerted by SEA WATER
`"" = P-0 +hdg`
` ""= 1.01 xx 10 ^(5) +1000 xx 1.024 xx 10 ^(3) xx 9.8`
` "" = 1.01 xx 10 ^(7)Pa.`
50.

what is normal stress ?

Answer»

Solution :When the deforming force acts everywhere on the surface of the body NORMALLY so that change in VOLUME of the body OCCURES without change in SHAPE stress is called normall stress .