1.

The banking angle for a curved road of radius 490 m for a vehicle moving at 35 ms^(-1) is

Answer»

`tan^(-1) ( 0.25 )`
` tan ^(-1) ( 0.35 )`
`tan^(-1) (1)`
`tan^(-1) ( 0.65 )`

SOLUTION :Here `, V= 35 ms^(-1), r- 490m`
` thereforetantheta= (v^2)/(rg ) = ((35 )^2)/( 490 xx 9.8) = 0.25`
` ortheta = tan^(-1) ( 0.25 )`


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