1 g steam at 100^(@)C is passed in to an insulating vessel having 1 g of ice at 0^(@)C. Find the equlibrium temperature of the mixture, neglecting heat capacity of the vessel.

1 g steam at 100^(@)C is passed in to an insulating vessel having 1 g

1.	1 g steam at 100^(@)C is passed in to an insulating vessel having 1 g of ice at 0^(@)C. Find the equlibrium temperature of the mixture, neglecting heat capacity of the vessel.
Answer» SOLUTION :Heat AVAILABLE on steam (changes from steam to water) = mL = `1xx540` = 540 cal Heat gained by ice to CHANGE into water at `0^(@)C` and then rise its temperature to `100^(@)C` `m_("ice")L_("ice")+M_("water")S_(w)DeltaT=1xx80+1xx1xx(100-0)=180cal`. The above CALCULATIONS show that some part of steam will condense to change the ice into water at `100^(@)C`. Let .x. is the mass of steam condensed, then `x xx540=180orx=180/540=1/3g` Final contents of the mixture : ice = 0 g water = `1+1/3=4/3g,"steam"=1-1/3=2/3g`. Final temperature of the mixture = `100^(@)C`