Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
10. Find */ orr, / PQR = 100° SR Te S At AN RAR O |
| Answer» | |
| 2. |
6. Find the general solution of Cos3x=cOSX |
| Answer» | |
| 3. |
Find the general solution of the equation2 |
|
Answer» cos x = - 1/2 Then,cos x = - cos (pi/3)= cos (pi - pi/3)= cos (2pi/3) We know that range of general value of cos^-1 is (0, pi) andcos (2pi/3) = - 1/2 |
|
| 4. |
Find thu Panpan which aim plorr |
| Answer» | |
| 5. |
19. Prove that: 4(sin1 30°+ cos 609)-+ cos4 60°liug 5 cm From a noint P 13 cm away from its centro(sin2 60cos2 45)+12cos 45°) + |
|
Answer» 4(sin^4 30 + cos^4 60) - 2/3(sin^2 60 - cos^2 45) + 1/2 tan^2 60 = 4[(1/2)^4 + (1/2)^4] - 2/3[(sqrt(3)/2)^2 - (1/sqrt(2))^2] + 1/2[sqrt(3)^2] = 4(1/16 + 1/16) - 2/3(3/4 - 1/2) + 1/2*(3) = 8/16 - 2/3(1/4) + 3/2 = 1/2 - 1/6 + 3/2 = 2 - 1/6 = 11/6 = 1 5/6 |
|
| 6. |
AABC, thproduced if necessary) at E. Prove that AD-e perpendicular AD from A to the bisector BD of the ZABC meets the base BCDE.InORR prove that. APRS is isosceles. |
|
Answer» ∠ABD =∠EBD = m(∠B) /2∠ADB =∠EDB = 90°Hence the two triangle are similar.Since, DB is a common side between the two triangles, other sides are also equal. so AD = DE. |
|
| 7. |
13. If the mean of the following data is 18.75. Find the value of p.&;: 10 15 p 25 30Fi: 5 10 7 8 2 |
| Answer» | |
| 8. |
i.ii. p2-13 p-3025. Rahulper annumAlso, find the interest paid by him.borrowed Rs 10,24,000 from a bank for one year. Of the bank charges Interest of 5%compounded half-yearly. What amount willi he have to pay after the given time period ,r nf the second polynomial |
| Answer» | |
| 9. |
13. Find the value of 'P' is mean of the following distribution is 30.Observation Frequency1215161410462 |
|
Answer» thank u |
|
| 10. |
v*x^2 %2B x*(-sqrt(5) %2B 3) - 3*sqrt(5)=0 |
|
Answer» answer |
|
| 11. |
( v i ) \sqrt { \frac { 22 } { 7 } } |
|
Answer» =>√π= √3.14 = 1.77 |
|
| 12. |
( a %2B 1 ) x ^ 2 - \frac 3 5 x = 11 , \text where a = - 1 |
|
Answer» when a = -1, ( - 1 + 1) x² - 3x/5 = 11 -3x/5 = 11 x = -55/3 |
|
| 13. |
-2 %2B (-11)*(-5) |
|
Answer» -11 × (-5) - 18 ÷ 955 - 2 53 thank you so much |
|
| 14. |
Hre i a figure ofa playground Find the area of the playgrouĎĺ |
|
Answer» area of field = area of trapezium = 1/2*(h)*(a+b) |
|
| 15. |
(-3/11)^(x %2B 5)/(-3/11)^(-3*x %2B 3)=((-3)/11)^(-2*(x %2B 4))*((-3)/11)^(2*x - 5) |
|
Answer» (-3/11)^x+5 ÷ (-3/11)^-3x+3 =(-3/11)^2x-5 * (-3/11)^-2(x+4) (-3/11)^[x+5-3x+3] = (-3/11)^[2x -5-2x-8] 8 - 2x = - 13 2x = 21 x = 21/2 = 10.5 10.5. |
|
| 16. |
0.5 - 11 %2B 11^4/11^3 %2B 11^2 |
| Answer» | |
| 17. |
(i*v)*(-sqrt(2)/2 %2B (2/3)*sqrt(7) %2B 6*sqrt(11)) - sqrt(11) %2B sqrt(7)/3 %2B (3/2)*sqrt(2) |
| Answer» | |
| 18. |
2/3 %2B (-11)/5 %2B 3/5 %2B 7/3 |
|
Answer» 7/5 is the right answer. 7/ 5 is the right answet 7/5 is the right answer 7/5 is correct answer of following question 7/5 is correct answer 7/5 is the right answer 7/5 is the correct answer of the given question 3/5+7/3-11/5+2/3; 3(3)+7(5)-11(3)+2(5)/15; 9+35-33+10/15=19+2/15=21/15=7/5 |
|
| 19. |
-y %2B 11*(text*(a*(d*n))) %2B 3*x - y - 11 |
| Answer» | |
| 20. |
2*(m %2B 3) - 4=3*(m %2B 7) %2B 11 |
|
Answer» 2(m+3)-4=3(m+7)+11=2m+6-4=3m+21+11;3m-2m=6-4-21-11,;m=-2-32=-34 30 is the correct answer of the given question |
|
| 21. |
(-8)/3 - 1/4 %2B (-11)/6 %2B 3/8 - 3 |
|
Answer» -8/3 + - 1/4 + - 11/6 + 3/8 - 3 = - 8/3 - 1/4 - 11/6 + 3/8 - 3 = (-64 - 6 - 44 + 9)/24 - 3 = (-114 + 9)/24 - 3 = - 105/24 - 3 = (-105 - 72)/24 = - 177/4 |
|
| 22. |
(-7)/3 %2B (-2)/5 %2B (-11)/6 %2B 3/10 |
| Answer» | |
| 23. |
hourăr_A bag contains 5 ăed and .3gseenble-fawhat is the pededeuat gettiny |
|
Answer» total number of marble is 3+5. probability of getting green marble= no. of green marble ÷ total number of marble i.e. 3/8 total no. of marbles in bag = 5+3= 8 no. of green marbles = 3 probability of getting green marble = 3/8 |
|
| 24. |
| ŕ¤ŕ¤ž %/0/ o \EU G 316 |
|
Answer» (81)^1/4 - 8*(216)^1/3= (3)^4/4 - 8*(6)^3/3= (3) - 8*6= 3 - 48= - 45 |
|
| 25. |
Side Cinem)eu efenhre a97 |
|
Answer» If the figure is square then side = 7cm and perimeter = 28 cm pls explain it is only for a square that you can find out perimeter and sides from the area itself because area is the square of sides which are equal. in this case , let side be a=> a²= 49 => a = √49 => a= 7 units and perimeter of square = 4a = 4(7) = 28units |
|
| 26. |
Uog e+ Tug(105 EUIf ** + xy + yot = a', then findb |
|
Answer» y^x(X/y*dy/dx+logy)+x^y(y/X+logxdy/dx)+x^x(1+logx)=0dy/dx(xy^y-1+x^ylogx)=-x^x(1+logx)-y^xlogy-x^y-1ydy/dx=-x^x(1+logx)+y^xlogy+x^y-1y/xy^x-1+x^ylogx |
|
| 27. |
x+y =5 And 2x-3y -4 =0 |
|
Answer» 2x + 2y - 2x + 3y = 10 - 45y = 6y = 6/5And, x + 6/5 = 5 5x + 6 = 25 5x = 19 x = 19/5 X=19/5Y=16/5is the best answer x+y=5 ×22x-3y=4 ×1 2x+2y=102x-3y=4 5y=14y=14/5x = 5 - 14/5 = 11/5 x=19/5y=16/5 is the correct answer x=19:5 And y=16:5 is the correct answer x=19/5,y=6/5 is the correct x = 19/5 , y = 6/5 This is the solution . |
|
| 28. |
6. Give two rational numbers lying between 0.232332333233332 ... and0.212112111211112. |
| Answer» | |
| 29. |
4x+3y-4=0 ; 6x=8-5y |
|
Answer» 4x + 3y = 4......(1)6x +5y = 8.......(2) Multiply eq(1) by 3 and eq(2) by 2 12x + 9y = 12.....(3)12x + 10y = 16....(4) Sub eq(4) from eq(3)y = 16 - 12 = 4 Now put value of y in eq(1)4x + 3*4 = 4x = (4 - 12)/4x = - 8/4 = - 2 |
|
| 30. |
6. Give two rational numbers lying between 0.232332333233332... and0.212112111211112. |
| Answer» | |
| 31. |
0.212112111211112.Give two rational numbers lying between 0.515115111511115... and 0.5353353335 |
| Answer» | |
| 32. |
7. Give two rational numbers lying between 0.515115111511115... and 0.5353353335 ... |
| Answer» | |
| 33. |
14,t4. Construct a triangle ABC in which AB4 cm.BC 5.3 em and CB 70° Also, draw theperpendicular bisector of AC |
|
Answer» ans completely show nhi ho raha |
|
| 34. |
Example -4Find the equation of perpendicular bisector of the line joining the points (1, 1) and(2, 3), |
| Answer» | |
| 35. |
InA ABC,ADis the perpendicular bisector of BCABC,AD is the perpendicular bisector of BCseeFig, 7.30). Show that Δ ABC is an isoscelestriangle in which AB AC. |
| Answer» | |
| 36. |
Prove that the perpendicular bisector of a chord of a circle always passesthrough the centre.4. |
|
Answer» AB is the chord of a circle. Join AC and BD.CD perpendicular toAB such that.angle CDA=AngleCDB=90°Also as CD is the perpendicular bisector of AB so AD = DBCD = CD (Using reflexive property)Thereforetriangle CDAand triangle CDBare congruent triangles.Then, CA = CBSince the center of the circle is the only point within the circle that has points on the circumference equal distance from it.Hence, C is the center of the circle. |
|
| 37. |
Find the equation of the perpendicular bisector of the straight line segment joining thepoints (3, 4) and (-1, 2). |
|
Answer» mam /sir. Not understanding for me. So please tell me easily. TO FIND: The equation of perpendicular bisector of line segment joining points (3,4) and (-1, 2) The end points of the line segment are A(3,4) and B(−1,2)Hence the midpoint of the line AB is ((3−1)/2,(4+2)/2)=(1,3)Now the slope of the line ism1=(2−4)/(−1−3)=−2/−4=1/2Hence the slope of the perpendicular will bem2=−1/(1/2)=−2∴ Equation of the line passing through (1,3) and slope -2 is(y−3)=−2(x−1)(i.e., ) (y−3)=−2x+2⇒2x+y=5Hence the required equation of the line is 2x+y=5 Important formulae Ok mam ok .I understood |
|
| 38. |
3. The perpendicular bisector of the line segment joining the points A(1, 5) and B(4, 6) cuts the y-axis at |
| Answer» | |
| 39. |
The coordinates of a point on x-axis whichlies on the perpendicular bisector of theline segment joining the points (7, 6) and(-3, 4) are |
| Answer» | |
| 40. |
. The line 2x-3y- 4 =0 is the perpendicular bisector ofthe line AB and the co-ordinates of A are(- 3, 1). Find the co-ordinates of B |
| Answer» | |
| 41. |
(d) starts at 5 and makes of a revolution, clockwise?(Which direction will you face if you start facing |
|
Answer» which quest |
|
| 42. |
yAmoure consists of 45%sand, 36효% gravel and rest ccmem. Find the weight of1257mixture which contains 125,kg wt of sand Alsq determine the weight of mixture thal willcontain 4 kg wt of cemeu |
| Answer» | |
| 43. |
In a certain concrete mixture, the ratio ofcement to sand is 1:5. How many bagsof cement would be used with 200 bagsof sand? |
|
Answer» ratio of cement and sand is 1:5bags of sand =200let bags of cement is x1/5=x/200x=4040bags of cement |
|
| 44. |
>HR 1 CILINE Jug!11 Ram Kumar mixes cement with sand for some repair work to be carried out in his house. Heused 3 kg of cement and - kg more of sand than cement. In all, he needs 10 kg of the mixture.Does he have enough mixture? If yes, how much more does he have? If no, how much moredoes he need? |
| Answer» | |
| 45. |
area or the quadrilateral ABeFind all zeroes of the polynomial (2x- 9(2 + V3) and (2 -3).+ 5x3x 1) if two of its zeroes are(24 9-9x |
| Answer» | |
| 46. |
e f_S_’-)fw‘ EXTERNEy LR : |
|
Answer» x(x + 5) = x² + x + 32 x² + 5x = x² + x + 32 4x = 32 x = 8 |
|
| 47. |
Q.5. Iffix) = 5x2-4x + 5, findf(1) +N-1) +fW). |
|
Answer» f(1) = 5-4+5 = 6 f(0) = 0-0+5 = 5 f(-1) = 5+4+5 = 14 f(1)+f(-1)+f(0)=6+5+14=25 |
|
| 48. |
8. For a set A, A x A contains 16 elements andtwo of its elements are (1, 3) and (C0, 2). Findthe elements of A. |
| Answer» | |
| 49. |
20. If abe = 1, prove that |
|
Answer» 1 is the correct answer of the given question |
|
| 50. |
146)sbe -1, then thevale of sdlec1. abe2. 143 |
|
Answer» abc=1 ⟹c=1/ab 1/(1+a+1/b)+1/(1+b+1/c)+1/(1+c+1/a) =1/(1+a+1/b)+1/(1+b+ab)+1/(1+1/ab+1/a) =b/(1+b+ab)+1/(1+b+ab)+ab/(1+b+ab) =1+b+ab/(1+b+ab) =1 hai |
|