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AABC, thproduced if necessary) at E. Prove that AD-e perpendicular AD from A to the bisector BD of the ZABC meets the base BCDE.InORR prove that. APRS is isosceles. |
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Answer» ∠ABD =∠EBD = m(∠B) /2∠ADB =∠EDB = 90°Hence the two triangle are similar.Since, DB is a common side between the two triangles, other sides are also equal. so AD = DE. |
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