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Find the equation of the perpendicular bisector of the straight line segment joining thepoints (3, 4) and (-1, 2). |
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Answer» mam /sir. Not understanding for me. So please tell me easily. TO FIND: The equation of perpendicular bisector of line segment joining points (3,4) and (-1, 2) The end points of the line segment are A(3,4) and B(−1,2)Hence the midpoint of the line AB is ((3−1)/2,(4+2)/2)=(1,3)Now the slope of the line ism1=(2−4)/(−1−3)=−2/−4=1/2Hence the slope of the perpendicular will bem2=−1/(1/2)=−2∴ Equation of the line passing through (1,3) and slope -2 is(y−3)=−2(x−1)(i.e., ) (y−3)=−2x+2⇒2x+y=5Hence the required equation of the line is 2x+y=5 Important formulae Ok mam ok .I understood |
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