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146)sbe -1, then thevale of sdlec1. abe2. 143 |
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Answer» abc=1 ⟹c=1/ab 1/(1+a+1/b)+1/(1+b+1/c)+1/(1+c+1/a) =1/(1+a+1/b)+1/(1+b+ab)+1/(1+1/ab+1/a) =b/(1+b+ab)+1/(1+b+ab)+ab/(1+b+ab) =1+b+ab/(1+b+ab) =1 hai |
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