Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

t. Without actually berparming the longdivision , state Thether the followingwational numbene well bave a terminatihdecimol expansion on a non- tenminatingsepeating decimal expansion:3105383125x

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for non terminating answer =1

2.

Aman whoseweight is 90kgs weighs 15 kg on the moon, what will be the weight of a manwhose weight is 60 kg?

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90kg(earth) = 15kg (moon)60kg (earth) = xkg in mooncross multiplication90x=60×1590x=900x=900/90=10therefore the weight of the man whose weight is 60 kg in earth with B 10 kgs in Moon

thank u

3.

Mr.andMrs.Ahujaweighx kg and y kg respectively. They both take a dieting courseat the end of which Mr. Ahuja loses 5 kg and weighs as much as his wife weighed betorethe course. Mrs Ahuja loses 4 kg and weighs th of whatthe course. Form two equations in r and y and solve.er husband weighed before

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For x :- x-5kg=yx=y+5for y :- y-4kg=7/8xy-4=7/8(x=y+5) y-4=7y+35/88 (y-4)=7y+358y-32=7y+358y-7y=35+32y=67kg ( Mrs. Ahuja's weight )

again for x:- x=y+5x=(y=65)+5x=67+5x=72kg (Mr. Ahuja's weight)

4.

4. 4 part of a bucket is filled with water andweighs 22-28 kg. But when 4 part is filled, it weighs 36kg. What would be the weight when part of it isfilled with water.76

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Weight of bucket when completely filled with water= weight when bucket 1/4 filled + weight when bucket 3/4 filled= 22.28 + 36= 58.28 kg

Therefore When bucket 6/7 filled with water weight of bucket= (6/7)*58.28= 49.95 kg

5.

fand के pumbey - ए£ di9%e G the _swj‘Yod of B>4 Lk

Answer»

Explanation:When we try to simplify a square root, we look for perfect square factors.

Do this by testing perfect squares until you number whose square if greater that 529 (for example 252=625)

So we test 22=4. Clearly 4 is not a factor of 529 (nor is any other even number.

Test 32=9 which is not a factor. Skip 42 because it is even.

Obviously 52=25 is not a factor. Skip 62.

Keep going . . .

232=529 so we're finished.

√529=23

6.

4. A woman weighs 59.350 kg. She reducesher weight 9.870 kg. What will 1.05 kg beher reduced weight?.......... kg

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(81)-3/2

81 is the video in the right answer

7.

21. What is a "Memorandurandum Revaluation Account"2 State when such an account is prepared

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Ans :- Memorandum Revaluation Account is when new assets and liabilities are added to the new balance sheet in the older form of assets and liabilities. In this the value of the assets and liabilities are unchanged but the effect is given through the capital account of the partner.

Memorandum Revaluation Account is made at the time of initiation and retirement of a firm. The purpose of this account is to:

(i) Record the change in the value of assets and liabilities of the firm.

(ii) End the changes that occurredearlier.

8.

e the following by using tie piii2

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9.

suuncCapacityltiecymiderters30. The volume & CSAof a cylinder are 1650 cm3 & 660 em2 resp. Find the radius & hcylinder.

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10.

Maths question - Bave that4 b,c2- Then abe='1

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11.

what is consinment account

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12.

of the two.month. Find the ratio of(ii) his income and expenditure%)(iii) Mr Sahai's income to the total income5, Rohit earns15300 and saves乏1224 per m) his income and savingsai) his expenditure and savings.e ratio of the numh

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I know you don't know

13.

5.The ratio of the income to the expenditure of a family is 7:6. Find the saving, if the income is1400.

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14.

The ratio of the expenditure to the savings of a family is 7:3. Find the income if the expenditure isexpenditure to the savings of a farmily is7:3. Find he income if the enpehditur is6300

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15.

The following data gives the distribution of total monthly household expenditurefamilies of a village. Find the modal monthly expenditure of the families. Also, find themean monthly expenditureof200SO,Expenditurein rupees)Number of families 24 4033 28 30 2216 71000- 1500- 2000 2500- 3000- 3500- 4000- 4500-1500 2000 2500 3000 3500 4000 4500 5000tata uise tracher-student ratio in higher secondary

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16.

llage.Finducxpenditurethemodalmonthlyexpenditure of the families. Also, fineofan monthly expenditure:Expenditure (in )1000-15001500-20002000-25002500-30003000-35003500-40004000-4500Number of families2440283016

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17.

(ill) Mr Sahai's income to the total income of the two.15300 and saves1224 per month. Find(i) his inco5. Rohit earns(1) his income and savings(ii) his expenditure and savings.

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18.

Theorem 10.10 : If a line segment joining two points subtends equal angles atwo other points lying on the same side of the line containing the line segment,the four points lie on a circle (i.e. they are concyclic).

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Do u have a short answer

19.

Prove that the line of centres of two intersecting cireles subtends equal angles at ütwo points of intersectionI.

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20.

Prove ttwo points of intersection.hat the line of centres of two intersecting circles subtends equal angles at

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21.

il ा 4W GRS N R~¼ W e e

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5/10=1/2=15/30=25/50=25/50

22.

८८. नष्टY, 8b006 =y + 30y, _o न हक लि S ८००४ A PO Y e (N W

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23.

<ty 1S gcteiled l stomdow fonAol 14,8 1 and adtunfyt s sl ol slancloryWl 424 . Fnd A pdebillyW valug ofy Axy s e s

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There can be on the whole 16 ways in which the numbers can be chosen

1,1 ; 1,2 ; 1,3 ; 1,44,1;4,2;4,3;4,49,1;9,2;9,3;9,416,1;16,2;16,3;16,4

Total possible outcomes 16

The product will be greater than 16 only in the cases4,49,2;9,3;9,416,1;16,2;16,3;16,4

That is in 8 cases

Probability= no of favourable outcomes/total number of outcomes

=8/16

=1/2

=0.5

Like my answer if you find it useful!

24.

5. The cost of video game is twice the cost of teddy bear. Write a linear equation in twvariables to represent this statement,

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Let the cost of video game be xcost of teddy bear be yIt is given that cost of video game is twice the cost of teddy bearThat is x=2yx-2y=0There x-2y =0 is the linear equation in two variables

25.

a Which conb) Which colour is least liked by peopc) Which colours are equally liked?f the cost of s kg of apples is 500, then what will be the cost of 21 kg of applIf the selling price of a video game is 800 and profit is 200 then find the cothe duration

Answer»

The cost of 21 kg of apple is 2100 as one kg of apple will cost 500 / 5 = 100 Rs.

the cost of 21 kg apple is 2100 as one kg

26.

(35) 0.20= -0.25 +0.15+0.60 =1==Self Assessment She(b) 63. I1. The value of x, if 2x + 2x + 2x = 192 is(a) 5(c) 6(d) of these2. The value of F +(0.0001)1/2 – (1000)-2/3 is(b) à(d) 0

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answer1.(c)6 answer 2.(a)1/2

1.c2.a are the right answers

27.

how many cm^2=square units in a graph if 1 unit =5 small boxes

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Depends on how many boxes is 1 cm.

if 5 small boxes =1cm

Then one square cm unit is 25 boxes.Because one cm is 5 boxes.So cm square is 5*5=25 boxes

28.

eno ce m such questions.The magnetic susceptibility of diamagnetic substance is(a) small and positive(c) smal and negative(b) large and positive(d) large and negagive

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In this case, themagneticfield in thematerialis strengthened by the induced magnetization. Alternatively, if χ isnegative, thematerialisdiamagnetic. ... Generally, nonmagneticmaterialsare said to be para- ordiamagneticbecause they do not possess permanent magnetization without externalmagneticfield.

Ans-c

29.

The decimal notation of 10 kg 2 dag 6 g is(a) 10.260 kg(c) 10.026 kg(b) 10.206 kg(d) 10.006 kg

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10kg2dag6g = 10.206kg

30.

1.35 dag into g

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: 1 dag = 10 g1.35 dag =1.35×10 =13.5 g

31.

een wanted to make a temporary shelter for her car, by making a box-like structurewith tarpaulin that covers all the four sides and the top of the car (with the front faceasà flap which can be rolled up). Assuming that the stitching margins are very smalland therefore negligible, how much tarpaulin would be required to make the shelter ofheight 2.5 m, with base dimensions 4 m x 3 m?

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32.

t. A square piece of cardboard with sides 25 cm has a small square of side 2.5 cm cut outfrom each corner. The remaining flaps are turned so as to make a box 2.5 cm deep.Find:(a) volume of the box(b) outer surface area of the box

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thanx bro was that too easy

33.

How many small cubes of edge 10 cm can be put in a cubical box of side 80 cm?

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34.

If one requires to insert some small boxes ia big box, what she/he is expected to calculateAlso, explain the method to calculate,

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They have to calculate the volume of each box. For cube, Suppose side of cube has length =aThen, Volume = a^3For cuboid, Volume =length *breadth*height

35.

COLA.CO A cosecA - 1S OSA cosec A+1

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36.

Area(ADEF) 196 cm2 and DE 7 cm, then find AB.

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Ar(ABC)/ar(DEF)=(AB)^2/(DE)^2100/196=AB^2/7^210/14=AB/770=14ABAB=70/14AB=5

37.

orithm to find the HCF of196 and 38220

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196=2*2*7*738220=2*2*3*5*7*7*13so H.C.F.=2*2*7*7=196

38.

EXERCISE 1.1hm to find the HCFC(ii) 196 and 38220

Answer»

Hcf=195196*195=38220By Euclid s division lemma, a=bq+r, o<r<bso, a=38220,b=196,q=195,r=0Hcf=196.

39.

b) 84 dag into dg

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84 dag = 8400 dg (Decigram)

40.

. Find the area of a rectangular plot, one side of which is 48 m and its diagonal is 50 m.

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41.

find the area of a rectangular plot, one side of which is 48 m. and its diagonal is 50 m.

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42.

Find the area of a rectangular plot one side of which is 48 m and its diagonal50 m.ABCG is a right triangle. Therefore

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43.

find the area of a rectangular plot, one side of which is 48 m and it's diagonal is 50 with rectangle diagram

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44.

19. yn Mussoorie, tre was 4°C on Monday and then it droppeu Utemperature of Mussoorie on Tuesday?6 C on Tuesday. What was the

Answer»

The temperature will be

= 4-6 = -2°C

45.

-r.u n, breadth = 18 m (11) length = 2.3 m, DreadFind the area of a rectangular plot, one side of which is 48 m and its diagonal is 50 nm.

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46.

c Saive the followingSunidhi looked at her ticket which read the time 1750 hit by the 12-hour clock?aurs. whEx. SSo

Answer»

In 24 hour clock system, after 12pm the time displayed is 13,14,15..Hence 1750 will be 5:50pm

47.

increased to 130 osa17, A garden has 2000 trees, 12% of these trees are mango trees, 18% are lemon trees and rest 70% areorange trees. Find the number of orange and lemon trees in total249

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48.

5.In an orchard, there are 1863 coconut trees, 1077 mango trees, 978 tamarindtrees and 169 orange trees. How many trees are there in all in the orchard?

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Total number of trees =1863+1077+978+169=4087

total number of trees 1863 +1077+978+169=4087

Total number of tree 🌴= 1863+1077+978+169=4087 is answer already correct ☑️☑️☑️

49.

7. In an orchard, of the trees are guava trees, are banana trees and the rest are mangotes. If there are 117 mango trees in the orchard, how many trees in all are there

Answer»

216 is the correct answer of the given question

216 is the correct answer of the given question

50.

EXAMPLE3 Show that the segment joining the mid-points of a pairparallelogram, divides it into two equal parallelograms.

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