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25 is the right answer

20x20=400 cm^2 is the right answer

the answer is 25 because5*5=25

25 is the right answer

the length of one side of the rectangle is x, then the side opposite and parallel to it also has a length of x. Since the perimeter of the rectangle is 20, then the other two sides have a measure of (20 - 2x), and each one has a measure of (20 - 2x)/2 = 10 - x.

The area of a rectangle = length x width = x(10 - x) = 10x - x²

The maximum area can be found by computing the derivative of the area formula

f(x) = 10x - x²

f'(x) = 10 - 2x

Find the critical points. Since f'(x) is defined for all real x, then the critical points occur where f'(x) = 0

10 - 2x = 0

10 = 2x

x = 5

So the other side = 10 - x = 10 - 5 = 5

The maximum area is 5 x 5 = 25 m²

A rectangle has a perimeter of 20m. Let x m be the length of one side. Find a formula for the area A of the rectangle in terms of x. Hence find the maximum area of ALet the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

25 is the answer yes

the correct answer is 25

perimeter of rectangle=2(l+b)2(l+b)=20(l+b)=10l+b=10area of rectangle =lblet us l=5 ,b=5l×b =5×5 =25the is 25 is correct answer.

25 is the best answer

25 is the right answer

perimeter of rectangle =2(l+b)2(l+b)=20(l+b)=10l+b=10area of rectangle =lblet us l=5 , b=5 l×b=5×5=25 25 is the right answer of this question

25 is the right answer of this question

perimeter of rectangle=2(l+b)20=2(l+b)10=l+b......1area of rectangle=l×blet us assume l=5&b=5area of rectangle=25

the correct answer is 25

25 will be the maximum area that can be formed

for maximum area length and width must be equal. so, length of each side = 5 cmarea = 25 sq.cm

25 is the right answer

25 is the right answer

25 is the right answer

25 is the right answer

25 is the right answer

The maximum area is 5×5=25m²is the best answer

25 is the best answer

the right answer is 25 because 5×5=25

25 is the correct answer

The correct answer is 25 because 5*5=25

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2L + 2B = 20L+B = 10

now, possible values of L And B are

L B Area = L*B9 1 98 2 167 3 216 4 245 5 25

and hence the maximum area of a rectangle having perimeter 20 cm is 25 cm².

25 is the correct answer

Perimeter of rectangle =2(l+b)

2(l+b)=20l+b=20/2l+b=10

If l=5 thenb=5

because breath =(l+b)-lb=(l+b)-lb=10-5b=5

Area=l×bArea=5×5Area=25m^2

20×20=400 cm = right answer

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A rectangle has a perimeter of 20m. Let x m be the length of one side. Find a formula for the area A of the rectangle in terms of x. Hence find the maximum area of ALet the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

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Correct answer is 25 because 5*5

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25 is the correct answer to this question .

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the maximum area of the rectangle is 36

in case of rectangle length is more than breadth so 2(l+b)=20then l=6,b=4then area is l*b=4×6=24

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The maximum area of the rectangle will be 24 sq units

the right answer will be 25 sq units.

2(l+b)=20l+b=10a=l*bmaximum=5*5=25cm2

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20×20=4000cm^2is the right answer

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Maximum Area=30metre square

25 is correct answer

Let the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

the perimeter of rectangle is2(l+b)=20(l+b)=10the area of rectangle=l×blet l=5 ,b=5=5×5=25

25 is the right answer

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25 is a right answer

400 cm. cm is the correct answer me

(15 "" "- +) Except 1 double is dissipated, then float in. That is, (5 2n + 1 + 1) and 14, must be taken.

400 is the correct answer

400 is the correct answer

25 is right answer asPerimeter of rect. = 2(L+B)Area of rect. = L*B

400 is the correct answer 400

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let l=x b =x

perimeter of rectangle = 2(l+b)

=20 = 2(x+x)10=2xx= 5

l=5,b =5area = l×b = 5×5 = 25 is the correct answer

25 is the maximum area 5*5=25

Let the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

25 m squer,, is most

Let the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10xmaximum area is 5*5 = 25 m^2

25 unit^2 is right answer

25 unit^2 is the answer

so sides can be, a) 8 and 2b) 9 and 1c) 5 and 5d) 4 and 6e) 3 and 7From this maximum area be formed from 4 that is 4*6=24

25 is correct answer.....

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20*20=400 cm^2 is the correct answer

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the right answer is 25 because 5*5=25

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2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

2(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^22(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^22(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^22(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^2

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

25cm is right answer

o400. is tha correct answer

20 × 20 = 400 as max perameter is 20 ,so both side can be 20 for max area

25 is correct and perfect answer

because 5×5=15

5 x 5 = 25 meter square is the correct answer

Please describe the question briefly

the maximum area is 5×5=25

Definition:Arectangleis a quadrilateral with all four angles right angles.

From this definition you can prove that the opposite sides are parallel and of the same lengths. A rectangle can be tall and thin, short and fat or all the sides can have the same length.

Definition: Asquareis a quadrilateral with all four angles right angles and all four sides of the same length.

So a square is a special kind of rectangle, it is one where all the sides have the same length. Thus every square is a rectangle because it is a quadrilateral with all four angles right angles. However not every rectangle is a square, to be a square its sides must have the same length.

so the maximum area the rectangle will be = 5*5

Definition:Arectangleis a quadrilateral with all four angles right angles.

From this definition you can prove that the opposite sides are parallel and of the same lengths. A rectangle can be tall and thin, short and fat or all the sides can have the same length.

Definition: Asquareis a quadrilateral with all four angles right angles and all four sides of the same length.

So a square is a special kind of rectangle, it is one where all the sides have the same length. Thus every square is a rectangle because it is a quadrilateral with all four angles right angles. However not every rectangle is a square, to be a square its sides must have the same length.

the reason given above is enough to understand that the required area will be 5*5cm square= 25 cm square

the maximum area of rectangle is 25 CM square

it is a square as all the sides are equal and angle given is 90°

Sum of roots = -(coefficient of X)/(coefficient of x²)= -(-b)/c= b/cPlease hit the like button if this helped you

class limit =57-52= 5

alpha and beta are the roots of ax² - bx + c = 0

alpha + beta = - ( x- coefficient ) / (x²-coefficient )

= - ( -b ) / a

= b / a

Like my answer if you find it useful!

7x-15y=2x+2y=3

(1)×1... 7x-15y=2(2)×7...7x+14y=21................................ 0-29y=-1929y=19y=19/29y=0.655x+2(0.655)=3x+1.310=3x=3-1.31=1.68

7x - 15y = 2......(1)x + 2y = 3.........(2) x = 3-2y

Put value of x from eq (2) in eq(1)7(3-2y) - 15y = 221 - 14y - 15y = 219y = 19y = 1

From eq(2)x = 3-2y = 3-2*1 = 3-2 = 1

Value of x = 1, y = 1

find the root find the root of the following quadratic equation by factorization method z square minus Z + 1 upon 4 equal to zero

find the roots of the following quadratic equation by factorization method z square minus Z + 1 upon 4 equal to zero

let the roots be X and yhence X=6ynowx+y=-b/a=14/k7y=14/kk=2/ynow X*y=c/a6y*y=8/2*y6y=4y=2/3hencek=2/2*3=3

Thanks

If x = 3 is root of equation (k+2)x^2 - kx + 6.Then, for x = 3 equation will be equal to 0

Put x = 3, we get(k+2)*9 - 3k + 6 = 09k + 18 - 3k + 6 = 06k = - 24k = - 24/6 = - 4

-2x^2 + 4x + 6 = 0x^2 - 2x - 3 = 0x^2 - 3x + x - 3 = 0x(x - 3) + 1(x - 3) = 0(x + 1)(x - 3) = 0x = - 1, 3

Roots of equation are - 1 and 3

2x(z-x-y) + 2y(z-y-x) = 2x(z-x-y) + 2y(z-x-y) = (2x+2y)(z-x-y) = 2(x+y)(z-x-y)

When a, b, c are in AP then 2b = a + c

So,

2(4k - 6) = 3k - 2 + k + 2

8k - 12 = 4k

8k - 4k = 12

4k = 12

k = 12/4

k = 3

2x+3y,ax+by2x+3y+ax+by=x(2+a)+y(3+b)

Rice and curry is a popular dish in the Southern Indian states of Andhra Pradesh, Telangana, Karnataka, Kerala, and Tamil Nadu, as well as in Sri Lanka and Bangladesh. Rice and curry dinner comprises the following: A large bowl of rice, most often boiled, but frequently fried.

what's the question here???

thanks

please give the answer of other questions also

First find slant height (l)now l^2=r^2+h^2hencel^2=3^2+4^2hencel=5cmHence CSA=2πrl=2*22/7*3*5=94.2cm^2

Let the slant height be l. Then, l² = r² + h²=> l = √(3²+4²)=> l = 5cm Curved surface area = πrl= 3.14*3*5= 47.1 cm²

Please hit the like button if this helped you

hit like if you find it useful

Option 4Let PQ touch the circle at the point R.

We know that tangents drawn from an external point to a circle are equal in length.

AB = AC = 5cm

AP +BP = AQ+ QC = 5cm

AP + PR = AQ + QR = 5cm…………(1)

[ BP = PR & QC = QR]

Now, perimeter of ∆ APQ = AP +PQ+AQ

= AP +RP+QR+AQ

= 5 + 5 [ from eq 1]

Perimeter of ∆ APQ= 10 cm

Let three consecutive terms of an AP are a-d, a, a+d

Given, Sum of three consecutive terms = 27Product of terms = 504

Then,a - d + a + a + d = 273a = 27a = 27/3 = 9

(a-d)*a*(a + d) = 504a(a^2 - d^2) = 5049(81 - d^2) = 50481 - d^2 = 56d^2 = 81 - 56 = 25d = 5

Terms are (9-5), 9, (9 + 5)= 4, 9, 14

Perimeter is sum of all sides

4+2+1+5=12cm

than you

thanks

1/x+y,1/2y,2/y+z are in A.P.

2/2y=(1/x+y)+(2/y+z)

1/y=y+z+x+y/(x+y)(y+z)

1/y=x+2y+z/xy+xz+y^2+yz

xy+xz+y^2+yz=y (x+2y+z)

xy+xz+y^2+yz=xy+2xz+yz

xz+y^2=2xz

y^2=2xz-xz

y^2=xz

so x,y,z are in G.P.

Development of male gametophyte starts in pollen grains, while still present in the microsporangium or pollen sac (precocious germination). Microspore undergoes only two mitotic divisions. First mitotic division leads to the formation of a vegetative cell and generative cell.

Vegetative cell is also called tube cell. The vegetative cell is bigger has abundant food reserve and large irregular shaped nucleus. These cells do not possess any cell wall, hence represented only by cell membranes.

A temporary callose wall is laid down between the two cells (Groska-Bry-Lass, 1967). The callose wall spreads between the generative cells and the intine to finally pinch it off. Soon, this callose wall dissolves and generative cell lies freely in the cytoplasm of vegetative cell.

area = length × breadth = 600 breadth = 25 length = 600/25 = 24 perimeter = 2(25+24) = 2×49 = 98cm

thanku 😊