25 is the right answer

20x20=400 cm^2 is the right answer

the answer is 25 because5*5=25

25 is the right answer

the length of one side of the rectangle is x, then the side opposite and parallel to it also has a length of x. Since the perimeter of the rectangle is 20, then the other two sides have a measure of (20 - 2x), and each one has a measure of (20 - 2x)/2 = 10 - x.

The area of a rectangle = length x width = x(10 - x) = 10x - x²

The maximum area can be found by computing the derivative of the area formula

f(x) = 10x - x²

f'(x) = 10 - 2x

Find the critical points. Since f'(x) is defined for all real x, then the critical points occur where f'(x) = 0

10 - 2x = 0

10 = 2x

x = 5

So the other side = 10 - x = 10 - 5 = 5

The maximum area is 5 x 5 = 25 m²

A rectangle has a perimeter of 20m. Let x m be the length of one side. Find a formula for the area A of the rectangle in terms of x. Hence find the maximum area of ALet the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

25 is the answer yes

the correct answer is 25

perimeter of rectangle=2(l+b)2(l+b)=20(l+b)=10l+b=10area of rectangle =lblet us l=5 ,b=5l×b =5×5 =25the is 25 is correct answer.

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perimeter of rectangle =2(l+b)2(l+b)=20(l+b)=10l+b=10area of rectangle =lblet us l=5 , b=5 l×b=5×5=25 25 is the right answer of this question

25 is the right answer of this question

perimeter of rectangle=2(l+b)20=2(l+b)10=l+b......1area of rectangle=l×blet us assume l=5&b=5area of rectangle=25

the correct answer is 25

25 will be the maximum area that can be formed

for maximum area length and width must be equal. so, length of each side = 5 cmarea = 25 sq.cm

25 is the right answer

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The maximum area is 5×5=25m²is the best answer

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the right answer is 25 because 5×5=25

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2L + 2B = 20L+B = 10

now, possible values of L And B are

L B Area = L*B9 1 98 2 167 3 216 4 245 5 25

and hence the maximum area of a rectangle having perimeter 20 cm is 25 cm².

25 is the correct answer

Perimeter of rectangle =2(l+b)

2(l+b)=20l+b=20/2l+b=10

If l=5 thenb=5

because breath =(l+b)-lb=(l+b)-lb=10-5b=5

Area=l×bArea=5×5Area=25m^2

20×20=400 cm = right answer

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A rectangle has a perimeter of 20m. Let x m be the length of one side. Find a formula for the area A of the rectangle in terms of x. Hence find the maximum area of ALet the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

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Correct answer is 25 because 5*5

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the maximum area of the rectangle is 36

in case of rectangle length is more than breadth so 2(l+b)=20then l=6,b=4then area is l*b=4×6=24

I solved this and knew that 25 is right

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The maximum area of the rectangle will be 24 sq units

the right answer will be 25 sq units.

2(l+b)=20l+b=10a=l*bmaximum=5*5=25cm2

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20×20=4000cm^2is the right answer

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Maximum Area=30metre square

25 is correct answer

Let the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

the perimeter of rectangle is2(l+b)=20(l+b)=10the area of rectangle=l×blet l=5 ,b=5=5×5=25

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(15 "" "- +) Except 1 double is dissipated, then float in. That is, (5 2n + 1 + 1) and 14, must be taken.

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25 is right answer asPerimeter of rect. = 2(L+B)Area of rect. = L*B

400 is the correct answer 400

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let l=x b =x

perimeter of rectangle = 2(l+b)

=20 = 2(x+x)10=2xx= 5

l=5,b =5area = l×b = 5×5 = 25 is the correct answer

25 is the maximum area 5*5=25

Let the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

25 m squer,, is most

Let the other side of the rectangle be x. Then,

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10xmaximum area is 5*5 = 25 m^2

25 unit^2 is right answer

25 unit^2 is the answer

so sides can be, a) 8 and 2b) 9 and 1c) 5 and 5d) 4 and 6e) 3 and 7From this maximum area be formed from 4 that is 4*6=24

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20*20=400 cm^2 is the correct answer

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the right answer is 25 because 5*5=25

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2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

2(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^22(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^22(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^22(x+y) = 20x+y = 10y = 10 - x (we express the other side in terms of x)A = x(10-x) = -x^2 +10xA will be maximized when the rectangle has equal sides, a square. Remember that every square is also a rectangle.maximum area is 5*5 = 25 m^2

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

2(x+y) = 20

x+y = 10

y = 10 - x (we express the other side in terms of x)

A = x(10-x) = -x^2 +10x

A will be maximized when the rectangle has equal sides, hence a square. Remember that every square is also a rectangle.

maximum area is 5*5 = 25 m^2

25cm is right answer

o400. is tha correct answer

20 × 20 = 400 as max perameter is 20 ,so both side can be 20 for max area

25 is correct and perfect answer

because 5×5=15

5 x 5 = 25 meter square is the correct answer

Please describe the question briefly

the maximum area is 5×5=25

Definition:Arectangleis a quadrilateral with all four angles right angles.

From this definition you can prove that the opposite sides are parallel and of the same lengths. A rectangle can be tall and thin, short and fat or all the sides can have the same length.

Definition: Asquareis a quadrilateral with all four angles right angles and all four sides of the same length.

So a square is a special kind of rectangle, it is one where all the sides have the same length. Thus every square is a rectangle because it is a quadrilateral with all four angles right angles. However not every rectangle is a square, to be a square its sides must have the same length.

so the maximum area the rectangle will be = 5*5

Definition:Arectangleis a quadrilateral with all four angles right angles.

From this definition you can prove that the opposite sides are parallel and of the same lengths. A rectangle can be tall and thin, short and fat or all the sides can have the same length.

Definition: Asquareis a quadrilateral with all four angles right angles and all four sides of the same length.

So a square is a special kind of rectangle, it is one where all the sides have the same length. Thus every square is a rectangle because it is a quadrilateral with all four angles right angles. However not every rectangle is a square, to be a square its sides must have the same length.

the reason given above is enough to understand that the required area will be 5*5cm square= 25 cm square

the maximum area of rectangle is 25 CM square