81279 + Interview Questions in Mathematics QA in Mathematics

1.	. Divakaran deposited a sum of 6250 in the Allahabad Bankfor year, compoundedhalf-yearly at 8% per annum, Fnd the compound interest he gets.
Answer»

Discussion

2.	The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number isreduced by 1& the third is increased by 1, we obtain three consecutive terms of a G.P., find thenumbers4.
Answer»

Discussion

3.	of three consecutive terms of an AP is 21 and the sum of the5 The sumis 165. Find these terms.squares of these terms
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Discussion

4.	Hence the requnehe sum of three consecutive terms of an A.P. is 12. The product drst and third terms is three times the second term. Find out the terms
Answer» suppose three terms are a-d,a,a+d sum is 12 so a-d+a+a+d = 12 3a = 12 a = 4 product of first and third term is three times the second term (4-d)(4+d) = 3a = 3×4 = 12 16 - dd = 12 dd = 4 d = 2 or -2 so.numbers are 2,4,6 thanks for answering

4.

Hence the requnehe sum of three consecutive terms of an A.P. is 12. The product drst and third terms is three times the second term. Find out the terms

Answer»

suppose three terms are a-d,a,a+d sum is 12 so a-d+a+a+d = 12 3a = 12 a = 4 product of first and third term is three times the second term (4-d)(4+d) = 3a = 3×4 = 12 16 - d*d = 12 d*d = 4 d = 2 or -2 so.numbers are 2,4,6

thanks for answering

Discussion

5.	J. The sum of three consecutive terms of an A.P. is 21. If the sum ofthe squares of these terms be 165, find these terms.
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Discussion

6.	also in AP.The sum of three consecutive terms of an A.P. is 21. If the sthe squares of these terms be 165, find these terms.he
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Discussion

7.	The sum of three consecutive terms inA.P. is 54, and the product of twoextremes is 275. Find the terms.
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Discussion

8.	8. After 200 which number is first perfect square:dh 21
Answer» Square of 14 is 196and square of 15 is 225 So first perfect square after 200 is 225

8.

8. After 200 which number is first perfect square:dh 21

Answer»

Square of 14 is 196and square of 15 is 225

So first perfect square after 200 is 225

Discussion

9.	8. After 200 which number is first perfect square:(o) 210 ) 215(a) 225(b) 201(d) 215
Answer» 225 is the perfect square (15)²

Discussion

10.	Page NoDateOn dividingthe guoti entreecHoel2remaind enondco ee-2-2and-2 aty
Answer»

Discussion

11.	% per annum. What amount will he get on maturity?1 year, compourDivakaran deposited a sum of 6250 in the Allahabad Bank for 1 yearhalf-yearly at 8% per annum. Find the compound interest he gets.
Answer»

Discussion

12.	\|\|13 A sum of money amounted to Rs 1416 in 5 years at 9% per annum. Find the sum.2
Answer» Let the sum be x ATQ,ptr/100+x=1416 [x59.5)/100]+x=1416 47.5x+100x=141600x= 960

12.

||13 A sum of money amounted to Rs 1416 in 5 years at 9% per annum. Find the sum.2

Answer»

Let the sum be x

ATQ,p*t*r/100+x=1416

[x*5*9.5)/100]+x=1416

47.5x+100x=141600x= 960

Discussion

13.	3, 0००५3 एज्तग सीकर. ०२९; Ands 2%, lob ond SO50 अर एस 51, 1१ \| उ०पथी00औ,बंद
Answer» 398−7=391436−11=425540−13=527Hence the required number divides 391, 425 and 527 exactly391= 17×23425=17×25527=17×31Hence GCF of 391, 425 and 527 is 17and the required number is 17

Discussion

14.	23,How much will " 25,600 amount to in one year at 12is compounded half yearly.% per annum, when the interest2
Answer»

Discussion

15.	हि NPT SRR eanety. \| CSERV अधिक. कि: अंगs APaR. ofpa-pg ond [&." ¥e e e eHepnRod \|2
Answer»

Discussion

16.	Find the compound interest on 12,000 at rate of interest of 12% for one year, if the interestis being compounded half-yearly
Answer» Amount = p(1+r/100)^2n = 12000(1+12/100)² = 12000112112/100100 = 12112*112/10 = 15052.8 rupees Compound interest = 15052.8-12000 = Rs. 3052.8

16.

Find the compound interest on 12,000 at rate of interest of 12% for one year, if the interestis being compounded half-yearly

Answer»

Amount = p(1+r/100)^2n

= 12000(1+12/100)²

= 12000*112*112/100*100

= 12*112*112/10

= 15052.8 rupees

Compound interest = 15052.8-12000

= Rs. 3052.8

Discussion

17.	26. If ab tc, prove that the points (а, аг), (b, b2), (c, c-) can never be collinear
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Discussion

18.	(i) How many integers can you find between 3and 4?
Answer» There are no integers, i.e. whole numbers, between 3 and 4, or between 4 and 3. 3 and 4 ke bich me o integers h 0 integers between 3 and 4 like plz support 😊😊

18.

(i) How many integers can you find between 3and 4?

Answer»

There are no integers, i.e. whole numbers, between 3 and 4, or between 4 and 3.

3 and 4 ke bich me o integers h

0 integers between 3 and 4 like plz support 😊😊

Discussion

19.	9. Find how many integers between 200 and-500 are divisible by 8.
Answer»

Discussion

20.	9. Findhow many integers between 200 and 500 are divisible by 8.
Answer» 200, 208, 216........... 496 a = 200 d = 8 L = 500 => a +(n-1)d = 496 => 200 + (n-1)8 = 496 => (n-1)8 = 296 => n-1 = 37 => n = 38 No. of integer between 200 and 500 that is divisible by 8 is 38

20.

9. Findhow many integers between 200 and 500 are divisible by 8.

Answer»

200, 208, 216........... 496

a = 200

d = 8

L = 500

=> a +(n-1)d = 496

=> 200 + (n-1)8 = 496

=> (n-1)8 = 296

=> n-1 = 37

=> n = 38

No. of integer between 200 and 500 that is divisible by 8 is 38

Discussion

21.	Get the seeds of the followintripod equation if possitle inaPerfect way200 - 6x + 9 = o
Answer» 2x2-6x+9/2=0 One solution was found : x = 3/2 = 1.500 1.5 is the right answer 2x2-6x+9/2=0 one solution was found: x=3/2=1.500answer 1.50 is the correct answer

21.

Get the seeds of the followintripod equation if possitle inaPerfect way200 - 6x + 9 = o

Answer»

2x2-6x+9/2=0

One solution was found :

x = 3/2 = 1.500

1.5 is the right answer

2x2-6x+9/2=0 one solution was found: x=3/2=1.500answer

1.50 is the correct answer

Discussion

22.	2. A scooter was bought at 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year.
Answer» thank you

Discussion

23.	. The area of a rectangular park is 456 m2 and its length is 24 m. Find the breadth of the park and the costof fencing it at the rate of 8.50 per metre.0. A playground measures 300 m u 1T
Answer»

Discussion

24.	12. A scooter was bought at 42,000. It's value depreciated at the rate of 8% per annum. Find its value after one year.
Answer»

Discussion

25.	12. A scooter was bought at42,000. Its valuedepreciated at the rate of 8% per annumFind its value after one year.
Answer»

Discussion

26.	12./ Al scooter was bought at t 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one ye
Answer»

Discussion

27.	A scooter was bought at Rs 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year12.
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Discussion

28.	12. A scooter was bought at 7 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year.
Answer» Principal (P) =₹ 42,000,Rate of Interest (R) = 8%, Time(n)=1 years Amount (A) =P(1-R/100)^n [Value depreciated] ER. RAVI KUMAR ROY A= 42000(1-8/100)¹ A=42000(1-2/25) A= (42000×23)/25 A= 1680× 23 A= ₹ 38640 Hence, the value of the scooter after one year = ₹ 38640. deprociation=42000×8/(100) =3360rs.value after one year=42000-3360=38640 rs. answee 38640 is the correct answer of the given question

28.

12. A scooter was bought at 7 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year.

Answer»

Principal (P) =₹ 42,000,Rate of Interest (R) = 8%, Time(n)=1 years

Amount (A) =P(1-R/100)^n

[Value depreciated]

ER. RAVI KUMAR ROY

A= 42000(1-8/100)¹

A=42000(1-2/25)

A= (42000×23)/25

A= 1680× 23

A= ₹ 38640

Hence, the value of the scooter after one year = ₹ 38640.

deprociation=42000×8/(100) =3360rs.value after one year=42000-3360=38640 rs. answee

38640 is the correct answer of the given question

Discussion

29.	-) lfx=2 ond x-3 are roots of the equation 3x2-22t-o, find the value of a and b. (15/2,9)
Answer» Given : 2 & 3 are the roots of the equation, 3x² - 2kx + 2m = 0. _____________________________________________________________ To Find : The value of k & m _____________________________________________________________ If x = 2, We get, ⇒ 3x² - 2kx + 2m = 0 ⇒ 3(2)² - 2k(2) + 2m = 0 ⇒ 3(4) - 4k + 2m = 0. ⇒ 12 - 4k + 2m = 0 ⇒ -4k + 2m = -12 ⇒ 2k - m = 6 ....(i) __________________ If x = 3, Then, ⇒ 3x² - 2kx + 2m = 0 ⇒ 3(3)² - 2k(3) + 2m = 0 ⇒ 3(9) - 6k + 2m = 0 ⇒ 27 - 6k + 2m = 0 ⇒ -6k + 2m = -27 ⇒ 3k - m = 13. 5..(ii) ____________________ Subtracting equation (i) from (ii), We get, ⇒ (3k - m) - (2k - m) = 13.5 - 6 ⇒ 3k - m - 2k + m = 7.5 ⇒ ∴ k = 7.5 _______________________ Substituting value of x in (i), We get, ⇒ 2k - m = 6 ⇒ 2(7.5) - m = 6 ⇒ 15 - m = 6 ⇒ -m = 6 - 15 ⇒ -m = -9 ⇒ ∴ m = 9 thankyou... thankyou

29.

-) lfx=2 ond x-3 are roots of the equation 3x2-22t-o, find the value of a and b. (15/2,9)

Answer»

Given :

2 & 3 are the roots of the equation, 3x² - 2kx + 2m = 0.

_____________________________________________________________

To Find :

The value of k & m

_____________________________________________________________

If x = 2,

We get,

⇒ 3x² - 2kx + 2m = 0

⇒ 3(2)² - 2k(2) + 2m = 0

⇒ 3(4) - 4k + 2m = 0.

⇒ 12 - 4k + 2m = 0

⇒ -4k + 2m = -12

⇒ 2k - m = 6 ....(i)

__________________

If x = 3,

Then,

⇒ 3x² - 2kx + 2m = 0

⇒ 3(3)² - 2k(3) + 2m = 0

⇒ 3(9) - 6k + 2m = 0

⇒ 27 - 6k + 2m = 0

⇒ -6k + 2m = -27

⇒ 3k - m = 13. 5..(ii)

____________________

Subtracting equation (i) from (ii),

We get,

⇒ (3k - m) - (2k - m) = 13.5 - 6

⇒ 3k - m - 2k + m = 7.5

⇒ ∴ k = 7.5

_______________________

Substituting value of x in (i),

We get,

⇒ 2k - m = 6

⇒ 2(7.5) - m = 6

⇒ 15 - m = 6

⇒ -m = 6 - 15

⇒ -m = -9

⇒ ∴ m = 9

thankyou...

thankyou

Discussion

30.	eat 26.lf α and β are the zeroes of the quadratic polynomial f(x)-x-px + q , prove that .-2CBSE 201
Answer»

Discussion

31.	The volume of a hemisphere is 2425 1/2cm3 . Find its curved surface areaCBSE 2012.
Answer»

Discussion

32.	21. If ab # 0, prove that the points (a, a2), (b, b2), (0,0) are never collinearCBSE 201)
Answer»

Discussion

33.	A playground measures 300 m * 170 m. Find the cost of planting grass on this at the rate of ₹80 per hectare ?
Answer» To find the cost of planting grass we have to find area of the field so Area of field =l×b=300×170=51000 squareNow convert into hectareIt will be 51000/10000As 1 hectare=10000m sqSo area field =5.1 hectare sqNow cost = 5.1 x0.80 p=0.408 p

Discussion

34.	A playground measures 300 m x 170 m. Find the cost ofat the rate of 80 per hectare.plantinggrassonthis
Answer» To find the cost of planting grass we have to find area of the field so Area of field =l×b=300×170=51000square now convert into hectare it will be 51000/10000as 1 hectare=10000m^2so area field =5.1 hectare sqnow cost = 5.1 x0.80 p=0.408 p

34.

A playground measures 300 m x 170 m. Find the cost ofat the rate of 80 per hectare.plantinggrassonthis

Answer»

To find the cost of planting grass we have to find area of the field so

Area of field =l×b=300×170=51000square

now convert into hectare

it will be 51000/10000as 1 hectare=10000m^2so area field =5.1 hectare sqnow cost = 5.1 x0.80 p=0.408 p

Discussion

35.	If the m term of an A. P. is and tithen show that its)tterm isLTS30/1/2[PT.О.
Answer» given that, mth term=1/n and nth term=1/m.then ,let a and d be the first term and the common difference of the A.P.so a+(m-1)d=1/n...........(1) and a+(n-1)d=1/m...........(2).subtracting equation (1) by (2) we get,md-d-nd+d=1/n-1/m=>d(m-n)=m-n/mn=>d=1/mn. again if we put this value in equation (1) or (2) we get, a=1/mn.then, let A be the mnth term of the APa+(mn-1)d=1/mn+1+(-1/mn)=1 hence proved.

Discussion

36.	the weight of 7 containers is 224kg. find weight of 11 containers.
Answer» for this find weight of one containerhence 224/7=32kghenceweight of 11 containers is 11*32=352kg

Discussion

37.	\sqrt { 3 } \times \sqrt [ 5 ] { 12 } \times \sqrt [ 10 ] { 54 }
Answer» The value of the entire equation is 4.24 plz solve this your answer is not right

37.

\sqrt { 3 } \times \sqrt [ 5 ] { 12 } \times \sqrt [ 10 ] { 54 }

Answer»

The value of the entire equation is 4.24

plz solve this

your answer is not right

Discussion

38.	5. The time t, of a complete oscillation of a simple pendulum of length l is given by t2Ďwhere g is gravitational constant. Find the approximate percentage of error in t when thepercentage of error in / is 1 %.
Answer»

Discussion

39.	12. A scooter was bought at *42,000. lts valuedepreciated at the rate of 8% per annum.Find its value after one year.
Answer» okay thanks

Discussion

40.	If a bulb is rated 6W, 12V, what is the resistance of each bulb?
Answer» power=V×V/R 6=12×12/R R=12×12/6 R=12×2 =24ohms

40.

If a bulb is rated 6W, 12V, what is the resistance of each bulb?

Answer»

power=V×V/R

6=12×12/R

R=12×12/6

R=12×2

=24ohms

Discussion

41.	Ans.Q.31. If the radius of the sphere is measured as 9cm with an error 0-03 em thenNCERT)find the approximate error in calculating its surface area.
Answer»

Discussion

42.	5.y2 + y-132278. z2-12z +2711. x2-8x - 6514. x2-3x - 541212.15Questions
Answer»

Discussion

43.	If x2 +27, then x-
Answer» We know(x- 1/x) ^2 = x^2 + 1/x^2 - 2 Given, x^2 + 1/x^2 = 27 (x- 1/x) ^2 = 27 - 2(x- 1/x) ^2 = 25 Then, value of(x- 1/x) = 5

43.

If x2 +27, then x-

Answer»

We know(x- 1/x) ^2 = x^2 + 1/x^2 - 2

Given, x^2 + 1/x^2 = 27

(x- 1/x) ^2 = 27 - 2(x- 1/x) ^2 = 25

Then, value of(x- 1/x) = 5

Discussion

44.	a bar graph on water use in our daily life
Answer» thanks both of you what is on horizontal line what is on vertical line

44.

a bar graph on water use in our daily life

Answer»

thanks both of you

what is on horizontal line

what is on vertical line

Discussion

45.	4x In a square shaped park, whose side measures 28 m, a rectangular pond is located at there with dimensions 32 m and 22 m. The area of the park excluding the pond is
Answer» 58 sq.m is the area of the park excluding the pond

Discussion

46.	(vii) of an houll126Find the area of a square park whose side is 15 - ml If he r
Answer»

Discussion

47.	Find the area of a square park whoseperimeter is 320m.
Answer» Perimeter of sqaure is 4× side4× side = 320 mside = 80 m Area of square = side² = (80)² = 6400 m²

47.

Find the area of a square park whoseperimeter is 320m.

Answer»

Perimeter of sqaure is 4× side4× side = 320 mside = 80 m

Area of square = side² = (80)² = 6400 m²

Discussion

48.	Expand using formula: (y + 3)^2
Answer» (y+3)² = y² + 3² + 6y = y² + 9 + 6y

Discussion

49.	Solve2-4 x+1=0 by using formula.
Answer»

Discussion

50.	Quadratic Equations and Expressions15. If α. β are tne roots of the quadratic equation x2-5x +k-0, then the value of 'k' suchthat α-β 1 is
Answer»

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

. Divakaran deposited a sum of 6250 in the Allahabad Bankfor year, compoundedhalf-yearly at 8% per annum, Fnd the compound interest he gets.

The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number isreduced by 1&amp; the third is increased by 1, we obtain three consecutive terms of a G.P., find thenumbers4.

of three consecutive terms of an AP is 21 and the sum of the5 The sumis 165. Find these terms.squares of these terms

Hence the requnehe sum of three consecutive terms of an A.P. is 12. The product drst and third terms is three times the second term. Find out the terms

J. The sum of three consecutive terms of an A.P. is 21. If the sum ofthe squares of these terms be 165, find these terms.

also in AP.The sum of three consecutive terms of an A.P. is 21. If the sthe squares of these terms be 165, find these terms.he

The sum of three consecutive terms inA.P. is 54, and the product of twoextremes is 275. Find the terms.

8. After 200 which number is first perfect square:dh 21

8. After 200 which number is first perfect square:(o) 210 ) 215(a) 225(b) 201(d) 215

Page NoDateOn dividingthe guoti entreecHoel2remaind enondco ee-2-2and-2 aty

% per annum. What amount will he get on maturity?1 year, compourDivakaran deposited a sum of 6250 in the Allahabad Bank for 1 yearhalf-yearly at 8% per annum. Find the compound interest he gets.

||13 A sum of money amounted to Rs 1416 in 5 years at 9% per annum. Find the sum.2

3, 0००५3 एज्तग सीकर. ०२९; Ands 2%, lob ond SO50 अर एस 51, 1१ | उ०पथी00औ,बंद

23,How much will " 25,600 amount to in one year at 12is compounded half yearly.% per annum, when the interest2

हि NPT SRR eanety. | CSERV अधिक. कि: अंगs APaR. ofpa-pg ond [&amp;." ¥e e e eHepnRod |2

Find the compound interest on 12,000 at rate of interest of 12% for one year, if the interestis being compounded half-yearly

26. If ab tc, prove that the points (а, аг), (b, b2), (c, c-) can never be collinear

(i) How many integers can you find between 3and 4?

9. Find how many integers between 200 and-500 are divisible by 8.

9. Findhow many integers between 200 and 500 are divisible by 8.

Get the seeds of the followintripod equation if possitle inaPerfect way200 - 6x + 9 = o

2. A scooter was bought at 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year.

. The area of a rectangular park is 456 m2 and its length is 24 m. Find the breadth of the park and the costof fencing it at the rate of 8.50 per metre.0. A playground measures 300 m u 1T

12. A scooter was bought at 42,000. It's value depreciated at the rate of 8% per annum. Find its value after one year.

12. A scooter was bought at42,000. Its valuedepreciated at the rate of 8% per annumFind its value after one year.

12./ Al scooter was bought at t 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one ye

A scooter was bought at Rs 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year12.

12. A scooter was bought at 7 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year.

-) lfx=2 ond x-3 are roots of the equation 3x2-22t-o, find the value of a and b. (15/2,9)

eat 26.lf α and β are the zeroes of the quadratic polynomial f(x)-x-px + q , prove that .-2CBSE 201

The volume of a hemisphere is 2425 1/2cm3 . Find its curved surface areaCBSE 2012.

21. If ab # 0, prove that the points (a, a2), (b, b2), (0,0) are never collinearCBSE 201)

A playground measures 300 m * 170 m. Find the cost of planting grass on this at the rate of ₹80 per hectare ?

A playground measures 300 m x 170 m. Find the cost ofat the rate of 80 per hectare.plantinggrassonthis

If the m term of an A. P. is and tithen show that its)tterm isLTS30/1/2[PT.О.

the weight of 7 containers is 224kg. find weight of 11 containers.

\sqrt { 3 } \times \sqrt [ 5 ] { 12 } \times \sqrt [ 10 ] { 54 }

5. The time t, of a complete oscillation of a simple pendulum of length l is given by t2Ďwhere g is gravitational constant. Find the approximate percentage of error in t when thepercentage of error in / is 1 %.

12. A scooter was bought at *42,000. lts valuedepreciated at the rate of 8% per annum.Find its value after one year.

If a bulb is rated 6W, 12V, what is the resistance of each bulb?

Ans.Q.31. If the radius of the sphere is measured as 9cm with an error 0-03 em thenNCERT)find the approximate error in calculating its surface area.

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If x2 +27, then x-

a bar graph on water use in our daily life

4x In a square shaped park, whose side measures 28 m, a rectangular pond is located at there with dimensions 32 m and 22 m. The area of the park excluding the pond is

(vii) of an houll126Find the area of a square park whose side is 15 - ml If he r

Find the area of a square park whoseperimeter is 320m.

Expand using formula: (y + 3)^2

Solve2-4 x+1=0 by using formula.

Quadratic Equations and Expressions15. If α. β are tne roots of the quadratic equation x2-5x +k-0, then the value of 'k' suchthat α-β 1 is

The sum of three numbers which are consecutive terms of an A.P. is 21. If the second number isreduced by 1& the third is increased by 1, we obtain three consecutive terms of a G.P., find thenumbers4.

हि NPT SRR eanety. | CSERV अधिक. कि: अंगs APaR. ofpa-pg ond [&." ¥e e e eHepnRod |2

5. The time t, of a complete oscillation of a simple pendulum of length l is given by t2Ďwhere g is gravitational constant. Find the approximate percentage of error in t when thepercentage of error in / is 1 %.