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-) lfx=2 ond x-3 are roots of the equation 3x2-22t-o, find the value of a and b. (15/2,9) |
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Answer» Given : 2 & 3 are the roots of the equation, 3x² - 2kx + 2m = 0. _____________________________________________________________ To Find : The value of k & m _____________________________________________________________ If x = 2, We get, ⇒ 3x² - 2kx + 2m = 0 ⇒ 3(2)² - 2k(2) + 2m = 0 ⇒ 3(4) - 4k + 2m = 0. ⇒ 12 - 4k + 2m = 0 ⇒ -4k + 2m = -12 ⇒ 2k - m = 6 ....(i) __________________ If x = 3, Then, ⇒ 3x² - 2kx + 2m = 0 ⇒ 3(3)² - 2k(3) + 2m = 0 ⇒ 3(9) - 6k + 2m = 0 ⇒ 27 - 6k + 2m = 0 ⇒ -6k + 2m = -27 ⇒ 3k - m = 13. 5..(ii) ____________________ Subtracting equation (i) from (ii), We get, ⇒ (3k - m) - (2k - m) = 13.5 - 6 ⇒ 3k - m - 2k + m = 7.5 ⇒ ∴ k = 7.5 _______________________ Substituting value of x in (i), We get, ⇒ 2k - m = 6 ⇒ 2(7.5) - m = 6 ⇒ 15 - m = 6 ⇒ -m = 6 - 15 ⇒ -m = -9 ⇒ ∴ m = 9 thankyou... thankyou |
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