1.

12. A scooter was bought at 7 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year.

Answer»

Principal (P) =₹ 42,000,Rate of Interest (R) = 8%, Time(n)=1 years

Amount (A) =P(1-R/100)^n

[Value depreciated]

ER. RAVI KUMAR ROY

A= 42000(1-8/100)¹

A=42000(1-2/25)

A= (42000×23)/25

A= 1680× 23

A= ₹ 38640

Hence, the value of the scooter after one year = ₹ 38640.

deprociation=42000×8/(100) =3360rs.value after one year=42000-3360=38640 rs. answee

38640 is the correct answer of the given question



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