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12. A scooter was bought at 7 42,000. Its valuedepreciated at the rate of 8% per annum.Find its value after one year. |
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Answer» Principal (P) =₹ 42,000,Rate of Interest (R) = 8%, Time(n)=1 years Amount (A) =P(1-R/100)^n [Value depreciated] ER. RAVI KUMAR ROY A= 42000(1-8/100)¹ A=42000(1-2/25) A= (42000×23)/25 A= 1680× 23 A= ₹ 38640 Hence, the value of the scooter after one year = ₹ 38640. deprociation=42000×8/(100) =3360rs.value after one year=42000-3360=38640 rs. answee 38640 is the correct answer of the given question |
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