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Hence the requnehe sum of three consecutive terms of an A.P. is 12. The product drst and third terms is three times the second term. Find out the terms |
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Answer» suppose three terms are a-d,a,a+d sum is 12 so a-d+a+a+d = 12 3a = 12 a = 4 product of first and third term is three times the second term (4-d)(4+d) = 3a = 3×4 = 12 16 - d*d = 12 d*d = 4 d = 2 or -2 so.numbers are 2,4,6 thanks for answering |
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