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Find the compound interest on 12,000 at rate of interest of 12% for one year, if the interestis being compounded half-yearly |
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Answer» Amount = p(1+r/100)^2n = 12000(1+12/100)² = 12000*112*112/100*100 = 12*112*112/10 = 15052.8 rupees Compound interest = 15052.8-12000 = Rs. 3052.8 |
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