Saved Bookmarks
| 1. |
In an Đ.Đ. sum ofthree consecutive terms is 27and their productis 504 , findthe terms.(Assume that three consecutive terms in A.P. are a -d,a, a + d.) |
|
Answer» Let three consecutive terms of an AP are a-d, a, a+d Given, Sum of three consecutive terms = 27Product of terms = 504 Then,a - d + a + a + d = 273a = 27a = 27/3 = 9 (a-d)*a*(a + d) = 504a(a^2 - d^2) = 5049(81 - d^2) = 50481 - d^2 = 56d^2 = 81 - 56 = 25d = 5 Terms are (9-5), 9, (9 + 5)= 4, 9, 14 |
|