(c) Find the value of"K" for which x - 3 is a solution of the quadrati

1.	(c) Find the value of"K" for which x - 3 is a solution of the quadratic equation (k+2)2-ks.Thus find the other root of the equation. (4)
Answer» If x = 3 is root of equation (k+2)x^2 - kx + 6.Then, for x = 3 equation will be equal to 0 Put x = 3, we get(k+2)*9 - 3k + 6 = 09k + 18 - 3k + 6 = 06k = - 24k = - 24/6 = - 4 -2x^2 + 4x + 6 = 0x^2 - 2x - 3 = 0x^2 - 3x + x - 3 = 0x(x - 3) + 1(x - 3) = 0(x + 1)(x - 3) = 0x = - 1, 3 Roots of equation are - 1 and 3

(c) Find the value of"K" for which x - 3 is a solution of the quadratic equation (k+2)2-ks.Thus find the other root of the equation. (4)

Answer»

If x = 3 is root of equation (k+2)x^2 - kx + 6.Then, for x = 3 equation will be equal to 0

Put x = 3, we get(k+2)*9 - 3k + 6 = 09k + 18 - 3k + 6 = 06k = - 24k = - 24/6 = - 4

-2x^2 + 4x + 6 = 0x^2 - 2x - 3 = 0x^2 - 3x + x - 3 = 0x(x - 3) + 1(x - 3) = 0(x + 1)(x - 3) = 0x = - 1, 3

Roots of equation are - 1 and 3