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Yes it is a quadratic equationHere a= 1b= 0C= 2Please like the solution 👍 ✔️👍

x/3 +1=5/3 => x=5/3x3-1x3 = 5-3=2y-2/3 = 1/3 => y = 1/3+2/3 =3/3=1

ans . x=2, y=1

Answer: 60 degree

Step-by-step explanation:

by angle sum property of quadrilateral:

∠P+∠Q+∠T+∠O=360°

90°+90°+∠T+120=360°

300°+ ∠T +360°

∠T +360°-300°

∠T =60 °

Correct Answer is (B) 30°

4x^2+27+3k^2; sum =-b/c=-27/4; k^2=9; k=3

denote the smaller number by n

thus the numbers are, n = 26 and n+1=27

Thnk u.. 😁

Myopia:Near-sightedness : A person with Myopia can see nearby objects clearly1)A person with myopia cannot see faraway objects clearly.2)The far point for the myopic eye is nearer than infinityOccurs due to1)Excessive curvature of the eye lens2)Elongation of eyeball3)The image of a distance object is formed in front of the retina and not on the retinaDefected is corrected by using Concave lenses such that the lens will bring the image back on to the retina.

It is assumed that the efficiency of men is higher by the factor 15/12 than that of women.) The question :How many days would be needed by 6 men and 10 women can be reduced to the question How many days would be needed by 6 + 10x(12/15) = 6+8 = 14 men, if the same work can be done in 21 days by 12 men?The answer isX = 21x(12/14) = 18 days.

I don't understand so please send me again clearly

Assuming they are working 8 hrs a day.Total hrs they work6 days × 8 hrs per day × 8 women = 384 hrsEarnings per hr = 2880/384=7.5 per hr.

15 women working for 5 days will ern5 days × 8 hrs per day × 15 women = 600 hrsThen 600 hrs × 7.5 = ₹4500.

Ans :- Near-sightedness, also known as short-sightednessand myopia, is an eye disorder where light focuses in front of, instead of on, the retina. Severe near-sightedness increases the risk of retinal detachment, cataracts, and glaucoma.

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for AP2(3k+3) = 2k+ 1 +5k-16k +6 = 7k k = 6

1 + 2 cosθsinθwe know 1 = sin²θ+ cos²θsin²θ+ cos²θ+ 2cosθsinθUse a² + b² + 2ab = (a+b)²so we get (sinθ+ cosθ)²

thanks

Here we know that 12 men=15 women from first statement

So 4 men=5 women

Now, as 15 women can do the work in 20 days, 1 woman can do the work in 15*20=300 days

Now we are asked how much time will 4 menand5 women take to complete the work

Here we can take 4 men = 5 women and can find the time taken by 5+5=10 women to complete the work

We know that 1 woman can complete the work in 300 days, so 10 women will complete the work in 300/10=30 days

So the answer is 30 days

24/9 is the correct answer of the following question

24/9 is answer to your question

4π r^2.

Far-sightedness, also known ashyperopia, is a condition of theeyein which light is focused behind, instead of on, theretina.This results in close objects appearingblurry, while far objects may appear normal

4(3k+2)-3(2k-1)+1=012k+8-6k+3+1=06k=-12k=-2

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4(3k+2)-3(2k-1)+1=012k+8-6k+3+1=012=-6k12/6=-k2=-kk=-2

4x–3y+1=04(3k+2)–3(2k–1)=012k+8–6k+3+1=06k+12=06k=–12k=–12÷6k=–2

k = -2 is the right answer

(i) -3/4 = -6/8 (Multiply numerator and denominator with 2)(ii) -3/4 = -24/32 (Multiply numerator and denominator with 8)(iii) -3/4 = -45/60 (Multiply numerator and denominator with 15)

AC + b y squared 2 minus b c plus minus a wire is required to buy AC divide by bc and ac nextbit BC and BC divide by sorry it is

1 man do 1/22 job per day 2 woman do 1/22 job per day 3 boys do 1/22 job per day so 1man, 1 woman, 1 boy

1/22 + 1/44 +1/66 job per day so (6 + 3 + 2)/132 = 1/t where t is the time taken now 132/11 = 12 = t

The same piece of work will be done in 12 days by one man, one woman, one boy.

Examples

Carbon dioxide.

Water.

Naphthalene.

2y^2+7y+5let alpha = p , bita = qsum of zeros = -b/a p+q= -7/2product of zeros= C/a pq= 5/2p+q+pq= -7/2+5/2= -7+5/2= -2/2=-1

2y^2+7y+5; let alpha=a; bita=k; sum of zero = -b/a; k+a=-7/2; ka=5/2; k+a+ka =-7/2+5/2=-2/2=-1

2y^2+7y+5let alpha = p , bita = qsum of zeros = -b/ap+q= -7/2product of zeros= C/apar= 5/2pq= 5/2p+q+par=-7/2+5/2=-7+5/2=-2/2=-1

two number lines placed at 90° to each other making for quadrants. Meeting at 0,0.

face value of 6 is 6 and place value of 6 is 6000

Thanks alot

(ax + by)^2= a^2x^2+b^2y^2+2(ax)( by); ( ax - by)^2= a^2x^2+b^2y^2-2(ax)( by); ( ax+by)^2-( ax - by)^2 = a^2x^2+b^2x^2+2abxy-a^2x^2-b^2x^2+2axby=4axby=4abxy

D(x,y)=(-1,2)then AD=√[(5+1)²+(1-2)²]=≥AD=√37 units