1.

3k+2 and y=2k-1 is a solution of the equation 4x - 3y +1=0find the value of k.

Answer»

4(3k+2)-3(2k-1)+1=012k+8-6k+3+1=06k=-12k=-2

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4(3k+2)-3(2k-1)+1=012k+8-6k+3+1=012=-6k12/6=-k2=-kk=-2

4x–3y+1=04(3k+2)–3(2k–1)=012k+8–6k+3+1=06k+12=06k=–12k=–12÷6k=–2

k = -2 is the right answer



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