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for 1 year = 365 daysfor 25 weeks = 175 days salary for 1day = 390000/ 365 = 1068.4for 25 weeks = 1068.4× 175 = 186970therefore salary for 25 weeks is Rs 186970

1 year=52 weeks1week=750025week=187500

390000÷52=7500×25=187500

186970 is the correct answer.

avg temperature is. = (38.5+41.2+46.2+31.4+37.2)/5 = 38.9

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tq

Yearly ₹390000weekly 390000÷52. as 1 year has 52 weeksweekly 750025 weeks 7500×25187500 this is the correct answer

Plz accepted as best

the correct answer is 187500 of the following

Arun earning in 25 weeks=187500

187500 is the correct answer of the given question

187500 is the best answer

yearly =390000; 39000÷52=7500 weeks; 7500× 25 weeks=187500

yearly 390000weekly 390000÷52 1/52weekly 750025 weeks 7500×25So, correct answer is 187500

correct answer is 187500

Arun earns ₹ 3,90,000 per year.there are 52 weeks in 1 yearso he in 1 week = 3,90,000/52 = ₹ 7,500therefore his earning for 25 weeks = 7,500 × 25= ₹ 1,87,500

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I) is the correct answer

Given a geometric sequence with the first term a1 and the common ratio r

The nth (or general) term is given by:an = a1⋅r^(n−1).

Let p be the divisor b the dividend and q be the some integer Using Euclid division algorithm we obtain p = 3q+r where r ≤ 0 , 1 , 2Hence possible value for r are - 0 , 1 ,2

Any odd positive integer is in the form of 4p + 1 or 4p+ 3 for some integer p.Let n = 4p+ 1,(n^2– 1) = (4p + 1)^2– 1 = 16p2+ 8p + 1 = 16p^2+ 8p = 8p (2p + 1)⇒ (n^2– 1) is divisible by 8.(n^2– 1) = (4p + 3)^2– 1 = 16p^2+ 24p + 9 – 1 = 16p^2+ 24p + 8 = 8(2p^2+ 3p + 1)⇒ n^2– 1 is divisible by 8.Therefore, n^2– 1 is divisible by 8 if n is an odd positive integer.

kuch samajh nhi aa rha bewakoof gadhe

this is a funny question

what is your question ?

By rationalization2-√2)(2-√2)/(4-2) = (2-√2)^2/2 = (4+2-4√2)/2 = (6-4√2)/2 = 3-2√2a= 3 b= -2

A|~|x=(1, 3, 5, 6, 7, 8, 9, ), A|~|A=(1, 3, 5,6)

A cup fai =( )A cup A=(0,2,4)

null set 0,2,4 is the correct answer

1) null set2) 0,2,4

dist=√(x2-x1)^2+(y2-y1)^2 =√{(1)-(-5)^2+(3-6)^2 =√(1+5)^2+(-3)^2 =√36+9 =√45 =√3*3*5 =3√5 unit

How didAbdulKalam earn hisfirst wages?

During the Second World War, the newspaperswerebundled and thrown out ofamoving train. Abdul Kalam earned hisfirst wages by helpinghiscousin, who distributed newspapers in Rameswaram, to catch these bundles.

Sn= n^2 +2nS1=1^2 + 2×1= 1+2=3S2= 2^2 + 2×2 = 4+4=8a1=3 ,a2= 8-3=5S3= 3^2 + 2x3= 9+ 6=15a3=S3-S2=15-8=7AP = 3,5,7......with common difference= 2

Let the numbers be 3a , 3a+1 , 3a+2 , 3a+3, 3a+4 .....etc

so, if 3a is divisible , so, remainder of 3a+1 is 1

similarly for 3a+2 is 2 and for 3a+3 = 3(a+1) is 0

so, possible remainder are 0,1,2

y at the last it directly become 11 cm

Let the radius of the hemisphere = r units

Radius of the cone = radius of the hemisphere

height of the cone = radius of the hemisphere

h = r ----( 1 )

Therefore ,

Required

maximum volume of the cone = ( 1/3 ) πr²h

V = ( 1/3 ) × π × r² × r

= ( 1/3 ) × πr³ cubic units

1) It will take 100 years for 1st one

it will take 100 year at 4% rate

take 100 year at the rate 4%

it take 100 years at the rate of 4℅

100 year at the rate 4%

it will take 100 year at the rate of 4%

I think I will take 100year at 4%rate

100 take year at the rat 4% is the right answer

100 tak year 4%is the correct a5

Option a is correctUr ans is 4%

option a 4% is the right answer

It will take 100 years for 1st one

it will be 6000*[1+5/100]×[1+10/100]6000*105/100*110/1006930

∠ADO=35°OA⊥DAOB⊥DBInΔAODandΔBOD OD=ODOA=OB[radiusofsamecircle]∠OAD=∠OBD=90°ΔAOD≅ΔBOD[RHS]∠AOD=∠BODInrt.ΔAOD∠AOD=90°−∠ADO=90°−35°=>∠AOD=55°∠AOB=∠AOD+∠BOD=>AOB=2∠AOD=>∠AOB=2×550=110°

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We have to convert the given word problem into

algebraic equation.

Let the number = x

One fourth of the number = ( 1/4 ) × x = x / 4

Succeeding number of x = ( x + 1 )

One fifth of the above number = ( 1/5 ) × ( x + 1 )= ( x + 1 ) / 5

According to the problem ,

One fourhth of a number exceeds one fifth of its

succeeding number by 3.

x / 4 - ( x + 1 ) /5 = 3

LCM ( 4 , 5 ) = 4 × 5 = 20

[ 5x - 4 ( x + 1 ) ] / 20 = 3

5x - 4x - 4 = 3 × 20

x - 4 = 60

x = 60 + 4

x = 64

Therefore ,

Required number = x = 64

Ans :- a number denoting relative position in a sequence, such as first, second, thirdSometimes shortened to:ordinal. logicmathsa measure of not only the size of a set but also the order of its elements.

Grameen Bank founded by Professor Muhammad Yunus

3x+2x=15x65x=90x=90/5x=18

x^4−2x^2y^2+y^4

=(x^2−y^2)^2

=[(x+y)(x−y)]^2

=[(p+1/p+p−1/p)(p+1/p−p−1/p)]^2=[(2p)(2/p)]^2

=4p^2/4p^2

=16

Greekmathematician Archimedesis widely considered by many to be the "father of mathematics." He is regarded as one of the leading scientists in classical antiquity and is credited with designing numerous innovative machines, including the screw pump and siege engines.

Formerly East Pakistan, Bangladesh came into being only in 1971, when the two parts of Pakistan split after a bitter war which drew in neighbouring India. Bangladesh spent 15 years under military rule and, although democracy was restored in 1990, the political scene remains volatile

The two countries share many cultural ties. In particular, Bangladesh and the east Indian state of West Bengal are Bengali-speaking. Bangladesh has a high commission in New Delhi with consulates in Mumbai and Kolkata. India has a high commission in Dhaka with a consulate in Chittagong.

Let age of Baichang = x yearsThen age of Baichang father= x + 29Age of Baichang grandfather= x + 29 + 26= x + 55

As per given conditionx + (x + 29) + (x + 55) = 1353x + 84 = 1353x = 51x = 51/3 = 17

Therefore,Age of Baichang = x = 17 yearsAge of Baichang father = x + 29 = 17 + 29 = 46 yearsAge of Baichang grandfather = x + 55 = 17 + 55 = 72 years

Platyhelminthes, are an obsolete phylum of pseudocoelomate.

seasponges, have one germ layer.

Metameric segmentation is absent in platyhelminthes, Echinodermata, Mollusca

Allcoelenterates areaquatic, mostly marine. The bodyform isradially symmetrical, diploblastic and does not havea coelom.

Hence, option (a) is correct.

7)73m50cm(70m50cm 7o ×3 × 100=300 +50cm

350-- 35 ××0 0 ×

the difference between two land posts is =10m 50cm

cos60=1/2sec30=2/√3Tan45=1sin30=1/2 cos30=√3/2Hence5*1/4+4*4/3-1/1/4+3/4=5/4+16/3-1/1=15+64/12-1=79/11