1.

If x-p+ and y p-, then the2,,2value of x"-2x y ty" is

Answer»

x^4−2x^2y^2+y^4

=(x^2−y^2)^2

=[(x+y)(x−y)]^2

=[(p+1/p+p−1/p)(p+1/p−p−1/p)]^2=[(2p)(2/p)]^2

=4p^2/4p^2

=16


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