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asI a anis are the newes of the polynomial 27 + 7yts,write the value of atpaß.[CBSG 20107

Answer»

2y^2+7y+5let alpha = p , bita = qsum of zeros = -b/a p+q= -7/2product of zeros= C/a pq= 5/2p+q+pq= -7/2+5/2= -7+5/2= -2/2=-1

2y^2+7y+5; let alpha=a; bita=k; sum of zero = -b/a; k+a=-7/2; ka=5/2; k+a+ka =-7/2+5/2=-2/2=-1

2y^2+7y+5let alpha = p , bita = qsum of zeros = -b/ap+q= -7/2product of zeros= C/apar= 5/2pq= 5/2p+q+par=-7/2+5/2=-7+5/2=-2/2=-1



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