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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The following numnhers are obviously not perfect squares. Live vea.(0) 1057(v) 64000(ii) 23453(vi) 89722ili) 7928(vii) 222000 (vii) 505050(iv) 222222 |
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Answer» These numbers unit digit is not the ones of a perfect square. A perfect suqare unit digit ends in 0,4,5,6,9 only |
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| 2. |
( i v ) \cdot \operatorname { tan } ( 45 ^ { \circ } + \theta ) + \operatorname { tan } ( 45 ^ { \circ } - \theta ) = 2 \operatorname { sec } 22 |
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| 3. |
One glass holds 250 ml of juice. How much juice will be there in 9glasses? |
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Answer» 1 glass =250 ml9 glasses=250*9=2250ml |
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| 4. |
9.Asum of money lent out at simple interest doubled itself in 20years. In how many years willit treble itself? |
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Answer» Let the sum of money be XSI=Amount-PrincipalIn this case, Simple Interest is = X SI=P*R*T/100X=X*R*20/100100x/20x=R5%=R Now the X is tripled,In this case SI=3x-x=2x SI=P*R*T/1002x=X*5*T/1002x/X=T*1/202*20=T40=T So it will take 40 years to make the sum of money tripled. |
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| 5. |
Jr. Prove that VS.is irrational. |
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| 6. |
1.Find value ofr , if 2x+ 39 |
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Answer» 2x+3=92x=6x=6/2=3 |
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| 7. |
24.Find the square root of 5 +12 i |
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Answer» Let √(5 – 12i) = x + iy Squaring both sides, we get 5 – 12i = x^2+ 2ixy +(iy)^2= x^2– y^2+ 2xyi. Comparing real and imaginary parts , we get 5 = x^2– y^2———– (1) and xy = – 6 ———— (2) Squaring (1), we get 25 = (x^2– y^2)^2= (x^2+ y^2)^2– 4x^2y^2 ⇒25 = (x^2+ y^2)^2– 4(– 6)^2 ⇒(x^2+ y^2)^2= 169 ⇒ x^2+ y^2= 13 ———- (3) Adding (1) and (3) we get 2x^2= 18=> x = ± 3. Subtracting (1) from (3) we get 2y^2= 8=> y = ± 2. Therefore, √(5 – 12i) = 3 + 2i or, 3 – 2i or, – 3 + 2i or, – 3 – 2i. As imaginary part of 5 – 12i is negative, the square root is ±(3 – 2i) thankyou bhai par samjh ni aara hindi mai send kr do |
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| 8. |
24.Find the square root of 5+12 i |
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Answer» Let √(5 – 12i) = x + iy Squaring both sides, we get 5 – 12i = x^2+ 2ixy +(iy)^2= x^2– y^2+ 2xyi. Comparing real and imaginary parts , we get 5 = x^2– y^2———– (1) and xy = – 6 ———— (2) Squaring (1), we get 25 = (x^2– y^2)^2= (x^2+ y^2)^2– 4x^2y^2 ⇒25 = (x^2+ y^2)^2– 4(– 6)^2 ⇒(x^2+ y^2)^2= 169 ⇒ x^2+ y^2= 13 ———- (3) Adding (1) and (3) we get 2x^2= 18=> x = ± 3. Subtracting (1) from (3) we get 2y^2= 8=> y = ± 2. Therefore, √(5 – 12i) = 3 + 2i or, 3 – 2i or, – 3 + 2i or, – 3 – 2i. As imaginary part of 5 – 12i is negative, the square root is ±(3 – 2i) |
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| 9. |
I. Short Answer Questions1. Which period of Indian history is known as the Gandhian era and why?gle evalved by Mahatma Gandhi as pa |
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Answer» The 1920 to 1947period of Indian history is knownas the 'Gandhian era', and for a good reason. During this time, Mahatma Gnadhi dominated theIndianNational Congress, which in turn was at the forefront of theIndianfreedom struggle please like the solution 👍 ✔️ |
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| 10. |
·Find the time in which a sum of money gets doubled at the interest rate of 8% per annum. |
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| 11. |
5५ 2०ली +an (8 +A) era |
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Answer» Given thatm/n= sin( theeta+2alpha)/ sin theetam+n/m-n= sin( theeta+2alpha)+sin theeta/sin( theeta+2alpha)-sin theeta good satisfied with answer |
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| 12. |
If 378y8 is a multiple of 3, where y is a digit,then find the value/values of y |
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Answer» so, the no 378y8 should be divisible by 3 for that sum of the digit is = 3+7+8+y+8 = 26+y should by divisible by 3.. rhe possible values od y are ,1,4,7 |
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| 13. |
1. Find the time in which a sum of money gets doubled at the interest rate of 8% per annum.e of interest In what time will |
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Answer» A = 2P I = P I = PRN/100 P = P×8×N/100 N = 100/8 = 12.5 Years If you find this answer helpful then like it. |
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| 14. |
-29*y %2B y^3 - 2*y^2 - 42 |
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| 15. |
पद लाा 2 — e%L ला / कट AL anea o) Wy |
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| 16. |
7 .Prove that sin® - 2sin’0e WY no.2¢05°6 - ८०58 |
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Answer» (sinθ- 2 sin^3θ)/(2cos^3θ-cosθ) =sinθ(1-2sin^2θ)/cosθ(2cos^2 θ-1) = sin θ [1- 2(1- cos^2 θ)/cos θ(2cos ^2 θ -1) = sin θ [1-2+ 2cos ^2 θ]/ cos θ (2 cos^2θ -1) = sin θ(2cos^2 θ -1)/ cos θ(2 cos ^2θ-1) = sin θ/ cos θ = tanθ Like my answer if you find it useful! |
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| 17. |
o Use the distributivity of multiplication over addition and simplify. |
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| 18. |
Using distributivity, findGICO |
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Answer» [8/15(-7/18+-11/18)]; [8/15(-18/18)]=[8/15(-1)]=-8/15 Correct Ans of this question = - 8/15 -8/15 is the following question answer [8/15(-7/18+-11/18)][8/15(-18/18)][8/15(-1)]=-8/15hope it helps Correct Ans = - 8/15 -8/15 is the right answer the correct answer is -8/15 of the following question -8/15 is the right answer -8/15 is the right answer -8/15 is the correct answer |
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| 19. |
9. Using distributivity, find5 12 |
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Answer» {7/5 * (-3/12)}+{7/5 * 5/12}7/5{-3/12+5/12}7/5 * 2/127/5*1/67/30 |
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| 20. |
जी शक . :(0 jr=1 iy 4=5m L=t ) =2= |
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| 21. |
eFie 27 ASODE s a pentagon A line ougho AC mots DCodaced at F. Show |
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| 22. |
2 Jr 378y8 is a multiple of 3, where y is a digitthen find the value/values of y. |
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Answer» sum of digits 37y8=3+7+y+8=18+yfor it to be a multiple of 3 the summof digits should be a multiple of 3hence18+y to be a multiplevalue of y0-18+0=18 divisible3,6,9 |
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| 23. |
y, Mohan and Zaid can do a work in 12 days, 15 days and 20 days respectiveltively. Ifalthe three work at it together and they are paid Rshem and in how many Gays, these will surpleteMaths Companion - |
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Answer» part 1 of soln part 2 of soln |
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| 24. |
44. A can do a piece of work in 12 days while Balone can15 days. With the help of they can finish it in 5 daythey are paid 960 for the whole work how much moneygets? |
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Answer» IF A, B and C work together, they will finish job in = ABC/( AB+BC+CA) =5 Substitute A=12, B=15. Therefore, C= 4 A, B & C compete works in 12, 15 & 4 days respectively, if they work alone. C(4 days) is three times more efficient then A ( 12 days). B ( 15 days) is 3/5 times efficient than A ( 12 days). If X is the efficiency of A. Then Eff. of A + Eff. of B + Eff. of C = 960X+(3/5)X + 3X = 960X= 208.7 A gets Rs 208.7B gets Rs 125.22 C gets Rs 626.7. |
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| 25. |
17. Seg PM is a median of APQR. If PQ40,PR42 and PM29, find QR.Solution:404229 |
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Answer» IF YOU FIND THIS SOLUTION HELPFUL, PLEASE LIKE IT. |
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| 26. |
d. of these20. If the selling price of an article is 3/5 of its cost price. Find the lb. 16,500c. Rs 10,500a. 205b. 2590ะก. 35%d. 40%21. If the selling nrice nf nn |
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Answer» selling price - cost price = • profit • loss•total cost price• total selling price |
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| 27. |
18 Vidya and Pratap went for a picnic. Their mother gave them awater bottle that contained 5 litres of water. Vidya consumed 2/5of the water.Pratap consumed the remaining water.(i) How much water did Vidya Drink?(ii) What fraction of the total quantity of water did Pratap drink |
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| 28. |
Ex. 8.10ndthe equation of line with slope passing throughthe point (1,- 2). |
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| 29. |
When you use distributivity, yousplit a product as a sum orducts |
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| 30. |
REt. Find the nature of the ducts of 34?_2n+2=0of the real mots exist. Find them. |
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| 31. |
ConstructatrianglePOR in which QR 6cm, 40-60° and PR-PQ-2cm.HI |
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| 32. |
4, A worker is paid? 1110 for 6 days. If his total wages during a month are? 4625, for howmany days did he work? |
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| 33. |
Construct&POR if PQ = 5 cm, mZPQR = 105° and m<QRP-40。(Hint: Recall angle-sum property of a triangle) |
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| 34. |
a worker is paid rs 1110 for 6 days . lf his total wages during a month are rs 4625 for how many days did he work |
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| 35. |
In Δ POR, P=80°,LQ=60° and the bisectors of40 and ZR meet at S, find :) ZORP (ii) ZQSR.80°5. C |
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| 36. |
. Seg PM is a median ofA POR. If PO 40, PR 42 and PM 29, find QR. |
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| 37. |
162 +122202 ?(B) 2(D) 53 |
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Answer» Option (c) Option (c) |
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| 38. |
at rate per annum willbeing compounded annually?R 640 amount to 774. 40 in 2 years, when interest is |
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| 39. |
If 17 litres of edible oil costs Rs. 1674.50. Find the price of 5 litres. |
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| 40. |
Page No.Datemorn |
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| 41. |
(a) 9(b) luOn a particular day, the rain fall recorded in a terrace 6 m long and 5 m board is 15cm. The quantity of water collected in the terrace is(a) 300 litres(b) 450 litres(c) 3000 litres(d) 4500 litres |
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| 42. |
covered?A Out of a class of 150, one-third opted for Sanskrit, two-fifth opted for Hindi andrest opted for French. Find how many opted for French? 15 |
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Answer» Total number of students in class = 150 Number of students opted for sanskrit = 150/3 = 50 Number of students opted for Hindi = 2*150/5 = 60 Then,Number of students opted for French = 150 - 50 - 60 = 40 |
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| 43. |
The Fibonacci sequence is defined by1=al = a2 and an -an-1+4.2, n > 2.Find forn 1,2,3,4.sn+1 |
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| 44. |
nd ns fuctors |
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| 45. |
e .Grs. Find fho mudforidâof fla bt sgmat jonisg lix pornt:(6༎) 6 the OOSRR L |
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Answer» Mid point :{(0+6)/2 , (0+12)/2}=> (3,6) The midpoint of the line segment joining the point (6,12) & (0,0) by solving through section formula is (3,6). |
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| 46. |
द्रव जल्द हि विदा Jenr 7 Q DX KRWg; हा BT DGTes v/ 1L, GGदल दा नी एक आर € का 93 =,R L T A GRS B |
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| 47. |
15. In the given figure, side BC of AABCis produced to D. If ACD=1280and LABC 43°, find ZBAC andLACB43°128° |
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| 48. |
2.Express each of the following decimals in the rational forn(1) 0.5 0.57 (m) 0.729 fiv) 12.28 |
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Answer» Gilbert bell McCombs Jeri KTN KVM Tu to go hi a) 9/10b) 57/100c) 729/1000d) 1228/100 |
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| 49. |
2/3 of a class opted for sports and the rest opted for music. If there were 48 studentsin the class, how many students opted for music? |
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Answer» 2/3*48=students of sports=2*16=32 studentshence for music=48-32=16 Thanks |
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| 50. |
hird proportiona1:The numbers (25-x), 34, (59-x) and 102 are in proportion. Find the value ofx. |
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Answer» these 4 are in proportion so34/(25-x)=102/(59-x)2006-34x=2550-102x68x=544so.x=8 |
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