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11x+2/3x=411x+2=12x12x-11x=2x=2

add -5/65/6+(-5/6)=5/6-5/6=0

full ans

Let the three terms be a/r,ar and a

When we take the product of three terms the common ratio gets cancelled

a/r*a*ar=a³=(-1)^3=-1

a=-1

sum of three terms is 13/12

a+a/r+ar=13/12

-1-1/r-r=13/12

-1/r-r=13/12+1

-1/r-r=25/12

(r-9)(r-16)=0

r=9 or r=16

the terms for r=9

-1,-9,-1/9

for r=16

-1,-16,-1/16

in a digital display which digit can display all 10 digit from 0 to 9

nine is a digit which can display all digits from 0 to 9

thanks

65% of 750hence 65/100*750=487.5now 2/5th of 487.5it is 2/5*487.5=195

1.for every line l and every point P not lying on it there exists a unique line m which passes through point P and is parallel to l2.two distinct intersecting lines cannot be parallel to the same line

line passing through (4,3) and (-6,0)(y-0)=(0-3)/(-6-4)*(x+6)y=3(x+6)/1010y=3x+183x-10y=-185x+y=0 so y=-5x3x-10(-5x)=183x+50x=18so 53x=18so x=18/53so y=-90/53so intersection point(18/53,-90/53)

Bro it was asked to calculate the angle of their intersection and not the point..

let ( x1 , y1 ) = A( 2 , 0 ) ,

( x2 , y2 ) = B ( 0 , 2/9 ) ;

mid point of joining of A and B = ( x1+ x2 /2 , y1 + y2 /2 )( 1 , p/ 3 )= ( 0 + 2 /2 , 0 + 2/9 / 2 )= ( 1 , 1/9 )p/3 = 1/9

[∵ If ( a , b ) = ( c , d ) then a = c and b = d ]

p = 1/3 --- ( 1 )

according to the problem given ,

put ( -1 , 3p ) in the equation 5x + 3y + 2 =05 ( -1 ) + 3× ( 3p ) + 2 = 0-5 + 3× 3 ( 1/3 ) + 2 =0 [ from ( 1 ) ]-5 + 3 + 2 =00 = 0 [ true ]Therefore ,

5x + 3y + 2 =0 line passes through thepoint ( -1 , 3p ) .

the number is ; = 30-16= 14

Let the number be x3/4x-2/5x=14(15x-8x)/20=147x/20=147x=14×20x=280/7x=40

1. positive. sin(x) is positive from 0 to 180 degree.2. 11 * 180 / 9 = 220 degrees. cos(x) is negative in the range(90, 270). therefore, answer is negative.

but answer is possitive

(ii) would also be positive as there is a conjugate sign.

not answer

5upon 7

5by7-13by11this is right

If one of the zero is reciprocal of the other,let one zero beαother zero will be 1/α

Product of roots = c/a⇒α× 1/α = 6a/(a²+9)⇒ 1 = 6a/(a²+9)⇒ a² + 9 = 6a⇒ a² - 6a + 9 = 0⇒ a² - 3a - 3a + 9= 0⇒ a(a-3) -3(a-3) = 0⇒ (a-3)(a-3) = 0⇒ (a-3)²= 0⇒ a = 3

Value of a is 3.

Thanks punam .I wish to send another question

Let present age of ram and raju be x and y respectively.x + y = 31.......(1)Three year ago,(x-3) = 4×(y - 3)x - 3 = 4y - 12x - 4y = -9.......(2)

Eq(1) - Eq(2)5y = 40y = 8So, x = 31 - 8 = 23

In expression formi) x + y

ii) x + 8

iii) 2/5 of x = 2x/5

thank you

(-8)^-1 x X =(-6)^-1; -1/8 × X = -1/6: X=8/6=4/3

(-8)^-x = 12^-1; -1/8 X= 1/12; 12/-8=X=3/-4

8*(-1)=-8

8+(-8)=8-8=0

therefore 8*(-1) =-8 is additive inverse of 8

cos–1(cos x) = x

Provided x ϵ [0,π] ≈ [0,3.14]

And in our equation x is 4 which does not lie in the above range.

We know cos[2nπ – x] = cos[x]

∴ cos(2nπ – 12) = cos(12)

Here n = 2.

Also 4π–12 belongs in [0,π]

∴ cos–1(cos 12) = 4π–12

This is the formula. A and B can be found for its implementation.

x²- 64 is the correct answer of the given question

the answer is x square -64

x square-64 is the answer

X square- 64 is the correct answer

Total number of students = 35Let number of boys = nThen number of girls = 2n/5

Givenn + 2n/5 = 357n/5 = 35n = 35*5/7n = 5*5 = 25

Number of girls = 2*25/5= 50/5 = 10

Explanation : Suppose number is n n/2 = x n = 2x Thrice of a number 3n = 3*2x = 6x

Answer : 6x

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kis class m ho

please crop the question and then send it again

3/4 is the right answer......

-33/8÷(-11/2)-33/8×(-2/11)3/4

109/15 - 42/5 this is your answer

17/15 is the correct answer of the given question

15 is right answer of this question. please like my answer

15 is the answer of the question

15 is the correct answer of the given question

15 is the right answer