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The line through (4, 3) and (-6, 0) intersects the line 5x + y = 0. Find the angleof intersection. |
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Answer» line passing through (4,3) and (-6,0)(y-0)=(0-3)/(-6-4)*(x+6)y=3(x+6)/1010y=3x+183x-10y=-185x+y=0 so y=-5x3x-10(-5x)=183x+50x=18so 53x=18so x=18/53so y=-90/53so intersection point(18/53,-90/53) Bro it was asked to calculate the angle of their intersection and not the point.. |
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