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After cross multipication18x-24= 10x8x= 24x = 3

afTer cross Multiplication18x-24=10x8x=24x=24/8=3 hope this will help you like my answer and make it best answer

8-6=2 so this is the answer for numerator

18x-24=10x18x-10x=24

X=3........ans

18x - 24 = 10x18x - 10x = 248x = 24x = 3 is the answer

After cross multiplication 18x-24=10x18x-10x=248x=24x=24/8=3

cross multiplication18x-24= 10x8x = 24 x= 3

after cross Multiplecation18x-24=10x8x=24x=3

3(6x-8)

18x-24=10x8x=24x=3

I = ∫ sec x dx = ∫ ( 1 / cos x ) dx = ∫ [ 1 / sin ( π/2 + x ) ] dx

.. = ∫ { 1 / [ 2. sin( π/4 + x/2). cos( π/4 + x/2) ] } dx

Dividing top and bottom by [ 2. cos² (π/4 + x/2) ],

I = ∫ [ (1/2)· sec² (π/4 + x/2) / tan ( π/4 + x/2 ) ] dx

ƒ'/ƒ = ln | tan ( π/4 + x/2) | + C ........... Ans.

Note : This can also be deduced from the first formula

∫ sec x dx = ln | sec x + tan x | + C

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(x-1)([(x+1)²+1]-1(x+1-1)+1(1-x-1))=0

(x-1)([x²+2x+1+1]-x+1(1+x+1))=0

(x-1)([x²+2x+2]-x+(2+x)=0

(x-1)(x²+2x+2-x+2+x)=0

(x-1)(x²+2x+4)=0

x=1,x= -2±√4-16/2x=-1±12i

5x=2x+73x=7x=7/3

5x=8+3x2x=8x=4

I cannot understanding this

I understand tq

total measure is 3604x+7x+15x+10x=36036x°=360° X=360/36X=10°

smallest angle 4x=4*10=40°and largest angle 10x=10*10=100°

and how to find largest angle

the angle of quadrilateral are 7x 4x 15x and 10x find smallest and largest angle of quadrilateral

Addictive inverse of a/b is -a/b

(i) (p+5)²=p²+10p+25

wrong answer

integrte

write any number which is non terminating and non repeating but numbers must be lying between 2.3 and 2.5 so here we can write here infinite rational number. just write any number like 2.312311231112.....or 2.414414441..

Using the valuessin30=1/2sin45=1/√2cos60=1/2cos30=√3/2cosec90=1cot90=0sin60=√3/2tan30=1/√3Now put these value1-1/4/1+1/2*(1/4+3/4/1-0)÷(√3/2*1/•3)=3/4/3/2*(4/4/1)÷(1/2)=1/2*1÷1/2=1

∫(sec^2x/cosec^2x)dx​∫(1/cos​​^2x)/(1/sin^2x)dx

∫(1/cos​^2xsinx) . (sin^2x/1)dx

∫tan^2x dx

∫(sec^2x-1) dx

tanx - x + c

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Inconsistent means no solutionso5/l= 3/m= 7/9l/m= 5/3

If it has equal roots the , D=0from this equation ,a=(3k+1) b= 2(k+1) c= k+1atq,D=b^2 -4ac0= 4(k^2 + 1 + 2k) - 4(3k+1)(k+1)0= -8k(k +1)k=0 k=-1

distance between (11,-2) and (4,-3)=root((4-11)^2+(-3+2)^2)=root(49+1)=root(50)

distance between (11,-2) and (6,-3)=root((6-11)^2+(-3+2)^2)=root(25+1)=root(26)

Let the two numbers be a and b.Then, b=3a, b-a= 26=> 3a-a = 26=> 2a=26=> a= 13b= 3a = 3(13) = 39.

-5,-1,3,7,... common difference = -1+5 = 4

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Multiply secx in bracket

=int. sec^2x+secx.tanx

=tanx+c+ int. sinx dx /cos^2

Take cosx=t

Then after differentiating-

>-sinxdx=dt put it in above equation

=tanx + int. 1 dt/t^2

=tanx+c+(-1/t)+b

=tanx-1/cosx + C

(Where b,c C are constant)

out of these given four fractions no two are equivalent.so this can't be calculated

Ans :-. x^2 - 3 = 0

x^2 - (√3)^2 = 0

(x - √3)(x + √3) = 0

x = +√3 , -√3

(a+b)^3=a^3+b^3+3ab(a+b)27/8x^3+1+9/2x(3/2x+1)thanks

27/8x^3+27/4x^2+9/2x+1

LHS = cos(3π/2 + x).cos(2π+x)[cot(3π/2 -x) + cot(2π+ x) ]

we know, cos(3π/2 + x) = sinx cos(2π+x) = cosx cot(3π/2 -x) = tanx cot(2π+x) = cotx, use this here,

= sinx.cosx[tanx + cotx ]= sinx.cosx [sinx/cosx + cosx/sinx]= sinx.cosx[(sin²x + cos²x]/sinx.cosx = (sin²x + cos²x ) = 1 = RHS

Answer: D) 10Given :(1,1)tx-3y-7=0Substituting the pointst(1)-3(1)-7=0t-10=0t=10Like if you find it useful

2x - 5y = 16 ......(1)3x + 4y = 1 ........(2)

Adding eliminating y by4 × eq(2) + 5 × eq(2)

8x - 20y = 6415x + 20y = 5gives23x = 69x = 69/23 = 3x = 3

So, 2×3 - 5y = 165y = 10y = -10/5 = -2y = -2

Two equivalent versions of Euclids fifth postulate are:(i) For every line l and for every point P not lying on l, there exists a unique line mpassing through P and parallel to l(ii) Two distinct intersecting lines cannot be parallel to the same line.

When a + b + c = 0then , a³ + b³ + c³ = 3abc .....(1)

Now divide (1) by abc

a³ + b³ + c³ = 3abc ------------------ -------- abc abc

a² b² c²----- + ----- + ------ = 3 bc ac ab