1.

\int \operatorname { sec } x ( \operatorname { sec } x + \operatorname { tan } x ) d x

Answer»

Multiply secx in bracket

=int. sec^2x+secx.tanx

=tanx+c+ int. sinx dx /cos^2

Take cosx=t

Then after differentiating-

>-sinxdx=dt put it in above equation

=tanx + int. 1 dt/t^2

=tanx+c+(-1/t)+b

=tanx-1/cosx + C

(Where b,c C are constant)



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