Saved Bookmarks
| 1. |
\int \operatorname { sec } x ( \operatorname { sec } x + \operatorname { tan } x ) d x |
|
Answer» Multiply secx in bracket =int. sec^2x+secx.tanx =tanx+c+ int. sinx dx /cos^2 Take cosx=t Then after differentiating- >-sinxdx=dt put it in above equation =tanx + int. 1 dt/t^2 =tanx+c+(-1/t)+b =tanx-1/cosx + C (Where b,c C are constant) |
|