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sec xdxcosec2x |
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Answer» ∫(sec^2x/cosec^2x)dx∫(1/cos^2x)/(1/sin^2x)dx ∫(1/cos^2xsinx) . (sin^2x/1)dx ∫tan^2x dx ∫(sec^2x-1) dx tanx - x + c Like my answer if you find it useful |
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