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. . 1-sin?30° _ _c0s?60°+co0s?30°(ix) 1+sin?45° % c0sec?90°—cot290°R+ (sin 60° tan 30°) |
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Answer» Using the valuessin30=1/2sin45=1/√2cos60=1/2cos30=√3/2cosec90=1cot90=0sin60=√3/2tan30=1/√3Now put these value1-1/4/1+1/2*(1/4+3/4/1-0)÷(√3/2*1/•3)=3/4/3/2*(4/4/1)÷(1/2)=1/2*1÷1/2=1 |
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