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Suppose number is x 3x - 10 = 35 3x = 35 + 10 3x = 45 x = 45 / 3 x = 15

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सबसे पहले इसका उलटा मान लेते हैं; यानि मान लेते हैं कि √3 एक परिमेय संख्या है।ऐसी संख्या के लिये a और b दो ऐसी संख्या होंगी जहाँ b ≠ 0 तथा a और b कोप्राइम होंगे, ताकि;√3 = a/bया, b√3 = a

दोनों तरफ का वर्ग करने पर यह समीकरण मिलता है;3b2= a2इसका मतलब है कि a23 से डिविजिबल होगा और इसलिये a भी 3 से डिविजिबल होगा।लेकिन यह हमारी पहले के मान का विरोधी है कि a और b कोप्राइम हैं, क्योंकि हमें 3 के रूप में a और b का कम से कम एक कॉमन फैक्टर मिल गया है।यह हमारे पहले मानी हुई संभावना कि b√3 प्रमेय संख्या है का भी विरोधाभाषी है।इसलिए एक b√3 अप्रमेय संख्या है सिद्ध हुआ

cosC=2cos^2(C/2)-1

so, a(1+cosC)/2+c(1+cosA)/2=3b/2

a+acosC+c+ccosA=3b

a+c+(acosC+ccosA)=3b

Using By projection formula:(acosC+ccosA)=b

a+c+b=3b

a+c=2b

This shows that a,b,c are in A.P.

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let the number be x6 + 3x = 333x = 33-63x = 27x = 9

Lee your number be xTherefore for first case 2x +4 =18and for second case x+11=18Now substrate them We get x-7=0Therefore x=7

Let the number be xTherefore we get in first case the equation as2x +4 =18which gives x = 7and for second case we get equation asx+11 = 18x = 7

Thank yrr

Sinx(1+ Tanx)+ Cosx(1+ Cotx)=Secx+ cosecx;; (Sinx+ SinzTanx)+ ( Cosx+ Cosx+ CosxCotx)=Sinx^2/ Coax/ Cosx^2/SinX= Sinx^2+ cosx^2/CosxSinx=1/cos x + 1/ Sinx= Secx + cosecx

cosB= a²+c²_b²/ 2ac

and , cosC= a²+b²-c²/ 2ab

therefore, a(bcosC – c cosB)

= a(b(a²+b²-c²/ 2ab) –c( a² +c²_b²/ 2ac)

=a[a²+b²-c²/ 2a - a² +c²_b²/ 2a]

=a[a²+b²-c²– (a² +c²_b²)] /2a

=a^2+b²-c²–a^2–c²+b²/2

=2b² – 2c² / 2

= b²– c²

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Ex0lanation : lim x-> 0 sinax/sinbx if we put x = 0 then we will get 0/0 form so using L'hospital rule lim x->0 acosax/bcosbx = acos0/bcos0 = a/b

Solution : a/b

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( cosecA- SinA)(SecA- CosA) sinA=( 1/ sinA- SinA)(1/ cosa- cosA)sinA=(1- SinA^2/ SinA )(1- cosA^2/cosA) SinA=( cosA^2)/ Sin A + sinA^2/ cosA( sinA)= ( cosA^2+ SinA^2)/ sinAcosA( sinA^2) =sinA/ cosA=TanA

zerobecause tan45 is 1log1=0and summation of log is multiplaction of values so answer is zero

-23+10= -13 it's your answer

Let x be added to 10 that gives -13So,x + 10 = -13x = -13 - 10 = -23The number is -23

Principal value branch of Cos^-1 is [ 0 , π]

We know that , Cos ( 2π + θ)= cosθ

Cos^-1 ( Cos13π/6) = Cos^-1[ Cos ( 2π + π/6 ) ]

Cos^-1 ( Cos π/6 )

=π/6

5 sin 30° +3tan 45°=5(1/2)+3(1)=5/2+3=11/2

total outcomes of die=6(p)no.greater than 3 on die =3/6=1/2so answer is 1/2

have you written the question correctly?

n is even or odd?get back to me quick

the picture is uncomplete .I not understand the picture.

1

2

it is a wrong answer

thanks

1. x² +X -20=0=> x² +5x -4x -20=0=> x(X+5)-4(X+5)=0=> (x-4)(X+5)=0=> X = 4, -5.

4. 9y² -12y +2 = 0=> y ={ +12±[(-12)² -4(9)(2)]½ }/2(9)=> y = [ 12± 6√2 ] / 18=> y = (2/3) ± (√2/3)

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Given ;Side of a cube = a = 7cmRadius of a hemisphere = 5.2/2 = 2.6 cm

= Total surface area of a solid= L.S.A of cube + Bottom side area + C.S.A of hemisphere= 4a^2 + a^2 + 2πr^2= 5a^2 + 2πr^2

= (5×7×7) + 2×(22/7)×2.6×2.6= 245 + 42.49= 287.49 sq. cm

the answer is=12-8+1.5=3.5

(-11)+6=-2+(-3)-5=-5so it is proof

after solving we get-11+6= -2+-3=-5=-5

[-2+(-9)]+6=(-2)+[(-9)+6][-2-9]+6=(-2)+[-3]-11+6=(-2-3)-5=(-5) hence proved.

how to calculate √n-√n-1

I have rationalized each term

+√n+√n-1 how to cancelled this plx show the solution

2(9×2)+(5×3)=36+15=51

can u explain me

5x3 how u got

this is the better one dikhsha

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thanks

i)

(sin30+tan45-cosec60)/(cos60+cot45-sec30)

=>(1/2+1-2/√3)/(1/2+1-2/√3)

=>(3/2-2/√3)/(3/2-2/√3)

=>(3√3-4/2√3)²

=>(3√3-4)^2/(4*3)

=>(27+16-24√3)/12

=>(43-24√3)/12

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To prove:√2+√7 is irrationalProof:Let is assume that √2+√7 is rational

Thus√2 +√7 = a/b (where a and b are co-prime)

√7 = a/b -√2

Squaring both sides

a²/b² - 2√2a/b + 2 = 7a²/b² - 5 = 2√2a/b

(a² - 5b²) / 2ab =√2

√2 is an irrational number .

This contradicts the fact that√2 is irrational .

So , our assumption is wrong.Hence , √2 +√7 is irrational

answer is is d answer is 3600

he cover distance 720m.

answer is option B plz like

720 metre is right answer

720 is right answer 720 is right answer

option B is the correct answer

answer is the d 3600

perimeter of square garden=(4×side)sq.units=(4×60)sq.m=240sq.m

the answer is b becoz perimeter of square is 4a means 4times of 60 then the answer is 240 and then multiply it with 3 bcoz he walked 3 times around the garden then the answer will be 720

4250 sahi he na please batsna