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\left. \begin array l \operatorname cos 45 ^ \circ \\ \operatorname sec 30 ^ \circ %2B \operatorname cosec 60 ^ \circ \\ \frac \operatorname sin 30 ^ \circ %2B \operatorname tan 45 ^ \circ - \operatorname cosec 60 ^ \circ \operatorname cot 45 ^ \circ %2B \operatorname cos 60 ^ \circ - \operatorname sec 30 ^ \circ \end array \right. |
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Answer» i) (sin30+tan45-cosec60)/(cos60+cot45-sec30) =>(1/2+1-2/√3)/(1/2+1-2/√3) =>(3/2-2/√3)/(3/2-2/√3) =>(3√3-4/2√3)² =>(3√3-4)^2/(4*3) =>(27+16-24√3)/12 =>(43-24√3)/12 Like my answer if you find it useful! |
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