Ceaver A-SinAX Sec A-CoA) 2 Amand – InterviewSolution

1.	Ceaver A-SinAX Sec A-CoA) 2 Amand
Answer» ( cosecA- SinA)(SecA- CosA) sinA=( 1/ sinA- SinA)(1/ cosa- cosA)sinA=(1- SinA^2/ SinA )(1- cosA^2/cosA) SinA=( cosA^2)/ Sin A + sinA^2/ cosA( sinA)= ( cosA^2+ SinA^2)/ sinAcosA( sinA^2) =sinA/ cosA=TanA

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