lim sinax / sinbxx-0 – InterviewSolution

1.

lim sinax / sinbxx-0

Answer»

Ex0lanation : lim x-> 0 sinax/sinbx if we put x = 0 then we will get 0/0 form so using L'hospital rule lim x->0 acosax/bcosbx = acos0/bcos0 = a/b

Solution : a/b

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