The sum of first three terms of a geometric sequence is 12he common ra

1.	The sum of first three terms of a geometric sequence is 12he common ratio and the terms.13and their producton We may take the firit ts of the geometric sequence asa, ar-
Answer» Let the three terms be a/r,ar and a When we take the product of three terms the common ratio gets cancelled a/raar=a³=(-1)^3=-1 a=-1 sum of three terms is 13/12 a+a/r+ar=13/12 -1-1/r-r=13/12 -1/r-r=13/12+1 -1/r-r=25/12 (r-9)(r-16)=0 r=9 or r=16 the terms for r=9 -1,-9,-1/9 for r=16 -1,-16,-1/16

The sum of first three terms of a geometric sequence is 12he common ratio and the terms.13and their producton We may take the firit ts of the geometric sequence asa, ar-

Answer»

Let the three terms be a/r,ar and a

When we take the product of three terms the common ratio gets cancelled

a/r*a*ar=a³=(-1)^3=-1

a=-1

sum of three terms is 13/12

a+a/r+ar=13/12

-1-1/r-r=13/12

-1/r-r=13/12+1

-1/r-r=25/12

(r-9)(r-16)=0

r=9 or r=16

the terms for r=9

-1,-9,-1/9

for r=16

-1,-16,-1/16