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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
sarvanam Kise kehte hain?????? |
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Answer» Apologies.We currently provide solutions in English only and we suggest you do the same while posting. A pronoun is called a sarvanam. But note that we only provide solutions in English currently so try to avoid posting questions about other languages. Thank you. ex of sarvanam:- yeh kamra hamara hai. woh pustak meri hai.hope its helpful to you. |
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| 2. |
11. मीना १५ जितने के लिए बैंक गई। उसने सभी से है 5) तश्श १ }) के नोट देने के लिए कहा। मीना ने5ो न किये। ता कि उसने 50 और है।। के कितने कितने लोट प्राप्त किये। [VR।।।fa fa |
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Answer» kiki do you love me shsshhdusjnsusjsgwiahssh X= 10 is the correct answer of the given question |
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| 3. |
write the unit digit in square root of 729 |
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| 4. |
81. The unit digit of a two digit number is 5 andtimes the sum of the digits is thesevenitself. Find the climbicenumber |
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| 5. |
13.14.Write the section formula.Express 100 as the Prime factors. |
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Answer» 13)hit like if you find it useful 14)100=2×2×5×5 hit like if you find it useful |
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| 6. |
If ∆ABC~∆POR, ar (AABC)/ar (APQR) =9/4cm and PQ=8 cm, then find the value of AB |
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Answer» Ar(∆ABC)/ar∆PQR =9/4AB^2/PQ^2=9/4AB^2/64=9/4AB^2=64×9)/4=16×9=144AB=√144=12cm. |
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| 7. |
diagonalsACb Fig. 9.25,aBand BD of quadrilateralrect at O such that OB = OD,8 CD, then show that:ar(DOC) ar (AOB)ar(DCB)-ar(ACB)DAIICB or ABCD is a parallelogram.r: From D and B, draw perpendiculars to AC.]D) DACB or ABCD is a parallelogramHintFig. 9.25 |
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| 8. |
10. Two plots of land have the same perimeter. One is a square of side 64 m and the other isarectangle of length 70 m. Find the breadth of the rectangular plot. Which plot has hegreater area and by how much? |
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| 9. |
A piece of wire is bent in the shape of a rectangle when length and width are 35 cm and 20 cm respectively. It is opened and rebent to form a circular ring. What is the diameter of the ring? |
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Answer» Perimeter of rectangle=2(l+b)=2(35+20)=2*55=110perimeter of rectangle will be equal to Circumference of circle =2π r110=2*22/7*r110*7/44=r=17.5then diameter will be 17.5*2= 35 cm |
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| 10. |
1o. Two plots of land have the same perimeter. One is a square of side 64 m and the otherrectangle of length 70 m. Find the breadth of the rectangular plot. Which plot hasgreater area and by how much? |
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| 11. |
SeQ2. Fill in the blanksthousandai Ierarbubi 10million12 millionscrorelakhhundred thousandd. 29 million 2 |
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Answer» 1crore =100thousand.10million is one crore.12 crore is 12 million2 million is 20000 hundred 1crore =100thousand 1 million =10crore 12million =1200lakhs2million=20hundred thousand 1 crore = 100 thousand10 million is one crore12 crore is 1200 lakhs2 million is 20000 hundred thousands 1 crore = 100 thousand 10 million = 1 crore12 crore = 1200 lakhs2 million = 20000 hundred thousand 100 thousand10 crore1200 lakhs20 hundred thousand |
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| 12. |
10. Two plots of land have the same perimeter. One is a square of side 64 m and the other is arectangle of length 70 m. Find the breadth of the rectangular plot. Which plot has thegreater area and by how much? |
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Answer» thanks |
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| 13. |
What will be unit digit of the square of 81? |
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Answer» 1 will be in the unit place.The square of any number with the digit 1 in its unit place will have 1 in the unit place after squaring. |
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| 14. |
12. If a number of which the half is greater than E th of the numiber by 15 then the number isa) 50b) 40c) 80d) none of these. |
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Answer» Explanation : Suppose number is x so x/2 = x/5 + 15 x/2 - x/5 = 15 (5x-2x)/10 = 15 3x = 150 x = 50 Solution : Number is 50. If you find this answer helpful then like it |
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| 15. |
fA : B-: 3 : 4 and B : C-8:9, then A : C Ä°s :(b) 3: 2(c) 2 3 |
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Answer» A:B=3:4A=3x, B=4x B:C=8:9B=8y, C=9y B=4x=8yx=2y A:C=3x:9y3x/9y=3(2y)/9y=2y/3y A:C=2:3 Option c is correct |
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| 16. |
ः यदि ( Ly —'3—2)——(—5 —l) e y T FA |
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Answer» Given, (x/3 + 1, y - 2/3) = (5/3,1/3) Then,(x/3 + 1) = 5/3x/3 = 5/3 - 1x/3 = 2/3x = 2 (y - 2/3) = 1/3 y = 1/3 + 2/3 y = 3/3 = 1 |
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| 17. |
i gé) बहुपद 22 - 2% - 3 के शून्यक हैं--कद o 9 Fa Y -~ |
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Answer» x^2-3x+x-3=0 x(x-3)+1(x-3)=0 (x+1)(x-3)=0 x=-1x=3 |
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| 18. |
(3) 11.334)9.43Tqq(2) 2.0(4) 2.4426, 2,5, 6, 8, 9 Feritfa re TRT -(3) 1.31 |
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Answer» thanks |
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| 19. |
7) Section formula. |
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| 20. |
SECTION-A1. Use prime factorization method to find the HCF of 300 and 1000. |
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| 21. |
The point R divides the line segment AB, whose A(-4,0) and B(0,6) are suchthat . AR =-AB8.4 |
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Answer» (-1,9/2) are the coordintes of R |
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| 22. |
3. Fill in the blanks:-(a) A square has ...... sides and 4.(b) In a rectangle its opposite sides are(c) The angle whose degree measure line between 0° and 90° is called an(d)The measure of the amount of space occupied by a solid is called its |
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Answer» a) 4 sides and 4 angle sb) congruentsc) acute angle a)4 sides 4 angles b) congruents c)acute angle d)area a) four, corners varea b) equal c) acute angle d) |
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| 23. |
find the dimensions of a rectangle piece of land if it's length is 4m more then 2times it's width and perimeter 32 |
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Answer» length = 2w+4 width = w perimeter = 2w + 2(2w+4) = 32 6w = 24 w = 4m length = 8+4 = 12m |
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| 24. |
48 From the top of a tower h metre high, the angles of depression of two objects, whichare in the line with the foot of the tower are α and β (p>a) . Find the distance betweenthe two objects. |
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| 25. |
. Two plots of land have the same perimeter. One is a square of side 64 m and the other isarectangle of length 70 m. Find the breadth of the rectangular plot. Which plot has thegreater area and by how much? |
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| 26. |
16. In 337337, the unit digit is occupied |
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Answer» It will be 7 only as cyclicity of 7 is 5 so divide 337 by 5we will get 1 as remainder 7^1= 7 |
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| 27. |
Two plots of land have the same perimeter. One is a square of side 64 m and the other Isarectangle of length 70 m. Find the breadth of the rectangular plot. Which plot has thgreater area and by how much'? |
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| 28. |
(iv)Find the maximum sum of A.P. 100+97+94+91 +....the following arith |
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| 29. |
. Point R (h, k) divides a line segment between the axes in the ratio 1: 2. Finequation of the line. |
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| 30. |
How many terms of the AP, 2, 4, 6, 2, 10,are needed to yet sum 2h |
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Answer» Sum=(n/2)[2(2)+(n-1)2]210=(n/2)[2(2)+(n-1)2]420=n(4-2+2n)210=n(1+n)n²+n-210=0n²+15n-14n-210=0n(n+15)-14(n+15)=0(n+15)(n-14)=0n=14,-15So n=14 |
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| 31. |
Fig. 7.17AD and BC are equal perpendiculars to a linesegment AB (see Fig. 7.18). Show that CD bisectsAB13 |
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| 32. |
Fig. 6.30In Fig. 6.31, if Poll ST, 2 POR= 110° andZRST- 130°, find ZQRS.Hint : Draw a line parallel to ST through 110point R.]130°R. |
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Answer» rong |
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| 33. |
2, 3, 4) on the planeFind the coordinates foot of perpendicular drawn from point (r". (2 i + j +3k) = 26 |
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| 34. |
. P and Q are the points with co-ordinates (2, -1) and (-3, 4), find the co-ordinates of thepoint R such that PR is of PQ. (Hint: Required point, R is (0,1); Use Section formula)TOTO |
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| 35. |
p %2B x^2 %2B x*(p - 3)=0 |
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Answer» x²+(p-3)x+p=0a=1; b=p-3; c=p Since the equation have equal roots D=0I.e b²-4ac=0 here,(p-3)²-4(1)(p)=0p²+9-6p-4p=0p²-10p+9=0Sum=-10; product=9number=-9,-1 p²-9p-p+9=0p(p-9)-(p-9)=0(p-1)(p-9)=0 p=9,1 |
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| 36. |
2. Find the value of ks, for which point P .2) is the mid-point of thetlime segment joining thepoints Q(-5,4) and R(-1,0). |
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| 37. |
2. Find the value of k, for which point P ( ,2) is the mid-point of thesline segment joining thepoints Q(-5,4) and R(-1,0). |
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Answer» tq |
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| 38. |
hich point Pĺ2)is the mid-point of the line segment Kining thepoints Q(-5.4) and R(-1,0). |
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| 39. |
2. Find the value of k, for which point P( 2) is the mid-point of the'ime segment joining thepoints Q(-5,4) and R(-1,0). |
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Answer» take k = a |
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| 40. |
Fig, 7.173. AD and BC are equal perpendiculars to a linesegment AB (see Fig. 7.18). Show that CD bisectsAB. |
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| 41. |
30. The arithmetic mean of 100 ob-servations is 24. 6 is added toeach of the observations and,then each of them is multipliedby 2.5. Find the new arith-metic mean. |
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Answer» The arithmetic mean = Sum of all observations/Number of observations Hence, sum of all observations = 24*100 = 2400 Now, 6 is added to each of the observations, so the sum would be 2400 + 100*6 = 3000 And then, each of them is multiplied by 2.5. So, the new sum of all observations = 3000*2.5 =7500 Hence mean - 7500/100 = 75 |
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| 42. |
Two plots of land hrectangle of length 70 m. Find the breadth of the rectangular plot. Which plot has tgreater area and by how much?10.ave the same perimeter. One is a square of side 64 m and the other is a |
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| 43. |
EXAMPLE 15. Find four numbers in G.P. in which the third term is greater thanh: lirst by 9 and the second term is greater than the fourth by 18. INCERT |
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| 44. |
and B together can do a piece of work in 6 days and B alone can do thework in 9 days. In how many days can A alone complete the work?8. Acan finish the wor |
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Answer» B does work /day = 1/9 let A finish the work in x days means A does work/day = 1/x since they finish the work together in 6 days (A + B)’s work/day =1/6 1/9 +1/x = 1/6 1/x = 3/54=1/18 x = 18 |
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| 45. |
a can complete a work in 10 days . a and b can do it in 5 days . in which days b can complete alone |
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Answer» he will complete it in 10 days |
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| 46. |
Fig. 7.173. AD and BC are equal perpendiculars to a linesegment AB (see Fig. 7.18). Show that CD bisectsAB. |
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Answer» by aas aod congruent bocthus ao =bo |
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| 47. |
\begin{array} { l } { \text { If } p \cot \theta = q , \text { examine whether } } \\ { \frac { p \sin \theta - q \cos \theta } { p \sin \theta + q \cos \theta } = \frac { p ^ { 2 } - q ^ { 2 } } { p ^ { 2 } + q ^ { 2 } } } \end{array} |
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Answer» what's the value of (a/p) in ans which one you give me? |
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| 48. |
Fig.731ABC is a triangle in which altitudes BE and CF tosides AC and AB are equal (see Fig. 7.32). Showthat4.(i) ΔΑΒΕ ΔACF(i) AB-AC, i.e., ÁBC is an isosceles triangle.Fig. 7.32 |
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Answer» Thanks |
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| 49. |
-q^2 %2B p^2*x^2 %2B x*(p^2 - q^2)=0 |
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Answer» x=q^2/p^2x=-1 is correct answer. p^2x^2+(p^2-q^2)x-q^2=0, b^2-4ac=(q^2-p^2)^2-4(p^2)(-q)^2=q^4-p^4-2p^2p^2+4 p^2q^2=(p^2+q^2)^2, x=-b+-VD/2a =-(p^2-q^2)+(p^2+q^2)/2p^2= x=2q^2/2p^2 or -2p^2/2p2; x=q^2/p^2 or -1 |
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| 50. |
3 p ^ { 2 } - 2 q ^ { 2 } \text { from } 9 p ^ { 2 } - 6 q ^ { 2 } |
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