-q^2 %2B p^2*x^2 %2B x*(p^2 - q^2)=0

1.	-q^2 %2B p^2x^2 %2B x(p^2 - q^2)=0
Answer» x=q^2/p^2x=-1 is correct answer. p^2x^2+(p^2-q^2)x-q^2=0, b^2-4ac=(q^2-p^2)^2-4(p^2)(-q)^2=q^4-p^4-2p^2p^2+4 p^2q^2=(p^2+q^2)^2, x=-b+-VD/2a =-(p^2-q^2)+(p^2+q^2)/2p^2= x=2q^2/2p^2 or -2p^2/2p2; x=q^2/p^2 or -1

-q^2 %2B p^2x^2 %2B x(p^2 - q^2)=0

Answer»

x=q^2/p^2x=-1 is correct answer.

p^2x^2+(p^2-q^2)x-q^2=0, b^2-4ac=(q^2-p^2)^2-4(p^2)(-q)^2=q^4-p^4-2p^2p^2+4 p^2q^2=(p^2+q^2)^2, x=-b+-VD/2a =-(p^2-q^2)+(p^2+q^2)/2p^2= x=2q^2/2p^2 or -2p^2/2p2; x=q^2/p^2 or -1

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-q^2 %2B p^2*x^2 %2B x*(p^2 - q^2)=0

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-q^2 %2B p^2x^2 %2B x(p^2 - q^2)=0