p %2B x^2 %2B x*(p - 3)=0 – InterviewSolution

1.

p %2B x^2 %2B x*(p - 3)=0

Answer»

x²+(p-3)x+p=0a=1; b=p-3; c=p

Since the equation have equal roots D=0I.e b²-4ac=0

here,(p-3)²-4(1)(p)=0p²+9-6p-4p=0p²-10p+9=0Sum=-10; product=9number=-9,-1

p²-9p-p+9=0p(p-9)-(p-9)=0(p-1)(p-9)=0

p=9,1

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