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How many terms of the AP, 2, 4, 6, 2, 10,are needed to yet sum 2h |
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Answer» Sum=(n/2)[2(2)+(n-1)2]210=(n/2)[2(2)+(n-1)2]420=n(4-2+2n)210=n(1+n)n²+n-210=0n²+15n-14n-210=0n(n+15)-14(n+15)=0(n+15)(n-14)=0n=14,-15So n=14 |
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