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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
\left. \begin{array} { l l } { \frac { 1 } { 2 ( 2 x + 3 y ) } + \frac { 12 } { 7 ( 3 x - 2 y ) } = \frac { 1 } { 2 } , } & { \frac { 7 } { ( 2 x + 3 y ) } + \frac { 4 } { ( 3 x - 2 y ) } = 2 } \\ { \text { where } ( 2 x + 3 y ) \neq 0 \text { and } ( 3 x - 2 y ) \neq 0 } \end{array} \right. |
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| 2. |
e= 60 (WIS + X + oGP SO0 °, |
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Answer» please like my answer if you find it useful |
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| 3. |
a an Earthquake,the Government gave 2.50,95,650 to 5 villages damagedthe disaster. How much money did each village get?, Karma spentt25,96,700for the higher education of his two sons How mchoney did he spent on each? |
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Answer» 2596700/2 = Rs. 1298350 |
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| 4. |
18 | हाईस्कूल गणित (कक्षा - 10)20, fo= &, वृत्त 7077 ' का केन्द्र 0 हो, तो ८7207 की माप ज्ञात कीजिए। |
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Answer» गणित हिन्दी में लिखने के लिए |
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| 5. |
9It e SO0शहद&5 g us |
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Answer» sin 8pi/3 cos 23 pi/6 + cos 13 pi/3 sin 35pi/6=sin(3pi-pi/3)cos(4pi-pi/6) + cos(4pi + pi/3) sin(6pi-pi/6)=sin(pi/3). cos(pi/6)+ cos(pi/3) [-sin(pi/6)]=sin(pi/3).cos(pi/6)-cos(pi/3)sin(pi/6...=sin(pi/3 - pi/6)[sin(a-b)=sin a cos b - cos a sin b]=sin(pi/6)=1/2 |
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| 6. |
Q53) A man purchased a watch for Rs.400 and sold it at a gain of20% on the selling price. The Sellingprice of the watch is: |
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Answer» CP = 400 PROFIT 20% SP = 400*1.2 = 480 |
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| 7. |
A group of students decided to collect as many paise from each member of group as is thenumber of members. If the total collection amounts to Rs. 59.29, the number of the members inthe group is :(B) 67(C) 77(D) 87(A) 57 |
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Answer» B is the correct answer The Answer is OptionC77 C, option is right answer option C is correct answer. |
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| 8. |
how many members does a committee consists of? |
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Answer» committee of what? |
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| 9. |
Find matices A and B, if-5 4 81 0 21A B5 46 and A - B11 2 07 38L-1 |
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Answer» hit like if you find it useful |
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| 10. |
Fill the table.1471220No. of ApplesCost of Apples (in)aan. |
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| 11. |
EXERCISEeThe cost of 4 kg of apples isR 20. Find the cost of 9 kg of apples |
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Answer» The cost of 4kg apple is ₹20Cost of 1kg apple is ₹20/4 = ₹5Cost of 9 kg apple is ₹5 × 9 = ₹45 |
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| 12. |
23.70,000. What was the Percentage of price increase!Ibuy a TV. for 10000 and sell it at a profit of20% . How much money dol get fr5.soo she loses 20% in the bargain. What was |
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| 13. |
dol52 = x² + 3² |
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Answer» answer is 4 of X Factor answer of this question is x=2 x is equal to the 4 is the best answer x is equal to the 4 is the best answer the correct answer is 4 x =4 is correct answer 25=16+9. 5^2=4^2+3^2 4 is the correct answer for the given question write the answer of x=4 |
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| 14. |
A gets 110% more than B. Then B gets- |
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Answer» let B get xA get x of 210/100= 210x/100B get less than A= 210x/100-x= 210x-100x/110x/!00%less = less ×100/A get = 110x/100/210x/100 = 110×100×100/210 = 110000/21% less than A let B has 100rs A has = 110% more than B 110 = ------- X 100 100 so A has 110 more than B means A has = 100+ 110 = 210 A has =210 B has = 100 let B=100; A=110°\° =110/100×100 A has 110 more than B 100+110=210; A=210; B=100 |
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| 15. |
Ibuy a T. V. for? 10.000 and sell it at a profit of 20%,How much money do I get forit?5.ears Foso0 sheloses 20in the bargain. What was |
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| 16. |
theThe graph of y fo is given below. Find-H |
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Answer» The no. of zeroes are 2.Because the line is crossing at 2 points. no of zeros are 2 for this question the no of zeros are 2 The no. of zeroes are 2. |
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| 17. |
\frac { \operatorname { cosec } ^ { 2 } 63 ^ { \circ } + \operatorname { tan } ^ { 2 } 24 ^ { \circ } } { \operatorname { cot } ^ { 2 } 66 ^ { \circ } + \operatorname { sec } ^ { 2 } 27 ^ { \circ } } + \frac { \operatorname { sin } ^ { 2 } 63 ^ { \circ } + \operatorname { cos } 63 ^ { \circ } \operatorname { sin } 27 ^ { \circ } + \operatorname { sin } 27 ^ { \circ } } { 2 ( \operatorname { cosec } ^ { 2 } 65 ^ { \circ } - \operatorname { tan } ^ { 2 } 25 ^ { \circ } ) } |
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Answer» (cosec²63°+ tan² 24°/ cot²66° +sec²27°) + (sin²63°+ cos63° sin27° + sin27ºsec63° /2(Cosec ²65° - tan²65°- tan²25°) = (cosec²63°+ tan² 24°/ tan²(90°-66) +cosec²(90°- 27°) + (sin²63°+ cos63° cos(90°-27°) + sin27ºcosec(90°- 63°) /2(Cosec ²65° - cot²(90°-25°) [ tan (90-A)= cot A, Cosec (90-A)= secA, cot (90-A= tanA] = (cosec²63°+ tan² 24°/ tan²24° +cosec²63°) + (sin²63°+ cos²63° + sin27ºcosec27° /2(Cosec ²65° - cot²65°) = (cosec²63°+ tan² 24°/ tan²24° +cosec²63°) + (sin²63°+ cos²63° + sin27º×1/sin27° /2(Cosec ²65° - cot²65°) [sin²A+cos²A=1, cosecA= 1/sinA,cosec²- cot²A=1] = 1+ {( 1+1)/2×1} = 1+2/2= 1+ 1= 2 |
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| 18. |
14.If n(A) = 5, then write the number of one-one functions from A to A. |
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| 19. |
TOLOPOLO UNICOD)4) Find the population of any 5 cities/ states of India. Draw the bar graph of the collecteddata (A4 pastel sheets) |
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| 20. |
1300 children took the NuMATS test and 65%ofthem scoredmore than 25. How many are they? |
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Answer» 65 percentage of 1300= 1300*65/10065*13= 845 845 |
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| 21. |
2. A man purchased 60 stamps for * 195. Some of the stamps were of 2denomination and the rest were of 5 denomination. Represent this situationalgebraically and graphically. |
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Answer» max 2= x+y=60,dua to constraints 2x+5y=195 answer is X= 35, y= 25 |
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| 22. |
EXERCISE 3.11. Aftab tells his daughter, "Seven years ago, I was seven times as old as you were then.Also, three years from now, I shall be three times as old as you will be." (Isn't thisinteresting?) Represent this situation algebraically and graphically.2. The coach of a cricket team buys 3 bats and 6 balls for ? 3900. Later, she buys anotherbat and 3 more balls of the same kind for R 1300. Represent this situation algebraicallyand geometrically3. The cost of 2 kg of apples and lkg of grapes on a day was found to be160. After a300. Represent the situationmonth, the cost of 4 kg of apples and 2 kg of grapes isalgebraically and geometrically |
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Answer» 2nd 1st |
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| 23. |
(2) Length of a rectangular swimming pool is times its breadth. Itsperimeter is 70 metres, find its length and breadth. |
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Answer» length =25bredth =10 length = 70/12 meter. , breadth = 14/6 meter L=25b=10 correct answer l=25 b= 10 is the correct answer |
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| 24. |
30.38 2138. A two digit number is 3 more than 4 times the sum of its digits. If 18 is added to the number, the digitsare reversed. Represent this situation algebraically and geometrically. |
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| 25. |
1300 children took the NuMATS test and 65%of them soore than 25. How many are they? |
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Answer» 65 percentage of 1300= 1300*65/10065*13= 845 students |
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| 26. |
2the numiber?eperimeter of a rectangular swimming pool istwice its breadth. What are the length and the breadth of154 m. Its length is 2 m moretadith of the poo1?-2. Thanthe pool? |
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| 27. |
72(ü) The cost of1 5 kg apples is 35. The cost of 1 kg apple is(a)25 |
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Answer» the cost of 1(2/5) = 7/5kg = 35rs so the cost of 1kg = 35*5/7 = 25rs. Thanks |
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| 28. |
The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice itsreadth. What are the length and the breadth of the pool?3. The base of an isosceles triangle is -cm. The perimeter of the triangle is 4 cm. What is the42length of either of the remaining equal-sides? |
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| 29. |
300 children took the NuMArs test and 65%of them scorednore than 25. How many are they? |
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Answer» 65 percentage of 1300= 1300*65/10065*13= 845 |
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| 30. |
1300 children took the NuMATS test and 65%ofthem scoredmore than 25. How many are they?5, |
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Answer» Total number of students took test = 1300 As given 65% of them scored more than 25 Hence,Number of students scored more than 25= (65/100)*1300= 65*13= 845 |
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| 31. |
sane way: Area of lllTherive, area of the shaded deshaded design = Area of ABCD.. Are(100 -43) cm257 cm# (100-2 x 21.5) cm2 =EXERCISE 12.3staled otherwise, use π =region in Fig. 1219, if PQ = 24 cm, PRz 7 crn and O isL. Finu thde centre of the circle.sFig, 12.20, if radii of the two concentric2 Find the areatre O are 7cm and 14 cm respectively and Z AOC 40°ircles with centre O are 7 cmFig. 12.19Fig. 12.20Fig. 12.21Mathematics- |
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| 32. |
In a village 465 women and 407 men took part in the clean village Compaign.How many total people together take part in compaign? 020015) |
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Answer» Total people = no of men + no of women = 465+407 = 872 Like my answer if you find it useful! |
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| 33. |
Tan 25" 12 CotCosec 65 Sec 65)+2 tan 18t tan 72 |
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| 34. |
This gives cos A = V1-sin? AHence, tan A = sin Asi= cos a VI-Exercise &Evaluate each of the followingsin? 43° +sin? 47°i) —tan? 60° |
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| 35. |
-65 - 23 %2B 37 %2B 9 - 12 |
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Answer» -63 is a right answer of the given question -63 is a right answer .... -63 is the answer.... -63 is the correct answer of the given question |
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| 36. |
Q14. Solve the in equation(i) tanx + tan2x + 3tanxtan2x 3ii) Prove Cot Ď/242+43+14+/6 |
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Answer» The ticked question is answeredConverting Cot(π/24) into degrees by multiplying the angle by 180/π we can get Cot(π/24)= cot 7.5 cotA= (1+cos2A)/sin2A We can write Cot (15/2)= (1+cos15°)/sin15°……………(1) Now cos15°= cos (45°-30°) =cos45.cos30+sin45.sin30 =1/√2.√3/2+1/√2.1/2 => cos 15°= (1/4) (√6 + √2) Similarly sin15° = (1/4) (√6 - √2) Putting these values in eq. (1) Cot (15/2)= [1 + (1/4) (√6 + √2)] / [(1/4) (√6 - √2)]= (4 + √6 + √2) / (√6 - √2) On rationalisationCot (15/2)= [(4 + √6 + √2) * (√6 + √2)] / [(√6 - √2) * (√6 + √2)]= (4√6 + 6 + 2√3 + 4√2 + 2√3 + 2) / 4= (4√2 + 4√3 + 8 + 4√6) / 4= √2 + √3 + √4 + √6. |
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| 37. |
22.The following table gives the literacy rate (in %) in 40 cities. Find the mean literacy rate.Literacy rate (in %) 45-55 | 55-65 | 65-75 | 75-85 | 85-95No. of Cities4124 |
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| 38. |
13)Write the number of all one-one functions from the setA={a,b,c) to itself. |
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Answer» the answer to this question is 3 |
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| 39. |
If 24 x 43 = 4%, then value of x is |
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Answer» 2^4* 4^3= 4^x4^3+2= 4^5x= 5 x=5 is right answer. |
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| 40. |
The cost of 2 kg. of apples and 1 kg. of grapes on a day was found to be Rs 160 after a month thecost of 4 Kg:of apples and 2 kg. of grapes is Rs. 300. Represent the situation algebraically. |
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Answer» thank you |
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| 41. |
EXERCISE 2.21. If you subtract from a number and multiply the result by , you getwhat isAnethe number?Thu narimeter of a rectangular swimming pool is 154 m. Its length is 2 m more thanWe of the nool?thefar, |
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Answer» the number is3/4 ok please like 3/4 is the right answer. 3/4 is the right answer of the following the answer is 1/4.If you devide 1/2 with 1/4 you get 1/8
3/4 is correct answer 3/4 is the correct answer of the given question |
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| 42. |
11C- - ( = |
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Answer» 4x=-6x=-6/4x=-3/2x=-1.5 |
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| 43. |
Ils for Class 10EXERCISE 11CFind the sum of first 19 terms of the AP 2, 7, 12, 17,Find the sum of first 26 terms of the AP1 3 57 |
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| 44. |
EXERCISE 2.2What i. The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more thIf' you subtracr from a number and multiply the result by 5. you getthe number?twice its breadth. What are the length and the breadth of the pool?2 |
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| 45. |
H TO3(b) If there is 1wheat is the5(c) Rahul bought two T-shirts. If theof each T-shirt is 179. howmoney did he pay for the two T-sMental MathsFill in the boxes.(a) 2x7= x2 = 14(c) 5x = 5HOTS |
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Answer» a= 7b=1is the answer (a) 7(b) 1This is the correct answer to this question . a) 7b) 1is the answer a- 2×7=7×2=14b- 5×1=5 a= 7b=1is the correct answer 2×7=7×2=145×1=5......... 7 and 1 is the right answer a 7 7 is the answers of a b 1 a77 is the answer of a b 1 a = 7,, b = 1 is the correct answer a-7b-1this is a correct answer to this question a7b1this is a correct answer to this question a7b1 is the right answer |
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| 46. |
EXERCISE 2.2Ifyou subtract5 from a number and multiply the resultby 2,you get 8,what is1.2. The perimeter ofa rectangularswimming pool is 154 m. itslength is 2 m more thantwice its breadth. What are the length and the breadth of the pool? |
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Answer» (x-1/2)*1/2 = 1/8 x-1/2 = 2/8 x - 1/2 = 1/4 x = 1/4+1/2 x = 3/4 |
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| 47. |
3. Teams from 9 schools took part in a quizcontest.Each team had 4 members. Howmany children took part in the contest? |
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Answer» 1 team =4 members 9 teams =4×9=36 children |
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| 48. |
decrease.Arun bought a car for ? 3,50,000. The next year, the price went upto3,70,000. What was the Percentage of price increase?h money dol get fo |
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| 49. |
11. यदि 43 = 11 है तो (a - 331a) का मानहोगा :(A) 1331331 | (B) 1331000(C) 1334331 (D) 1330030 |
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| 50. |
A invests8,000 and B invests11,000 at the same rate of interest per annum.at the end of 3 years, B gets720 more interest than A; find the rate of interest. |
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Answer» Interest of B + 720 = Interest of A 8000*R*3/100 + 720 = 11000*R*3/100 240R + 720 = 330R 720 = 90R R = 8% |
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