Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

11. In the given figure, find the measure of 41, 22, 43.23136104°

Answer»

angle 3 + 136°=180°(linear pair)angle 3= 44°angle 2 + 104°= 180°(linear pair)angle 2= 76°angle 1+ angle 2 +angle 3=180°(sum of angles of the triangle)then angle 1= 60°

2.

65 12.Divide the sum of 13 and 7 by theirdifference

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its a correct ans.. i also solved this

3.

7. A I-.0.1.2.B 2.3,o]. Ii f from A into B defined by fx)- +2, then fisa) a functionb) one onec) ontod) one one onto

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here f stands for a function.therefore f(x) is function of x.so the correct option is a.

4.

11) Seven times a number subtracted from 29gives 43. Find the number.

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29-7x=43-7x=43-29-7x=14x=14/-7x=-2

5.

4. Add and express the sum as a mixed fraction:-1224(i)-5 and 4310and 11

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This answer is Verified

6.

Section-AFind the common difference of AP; 0,-4,-8, -12.........

Answer»

The common difference of the given AP is -4 -(0) = -4.Thank you for your question.

= second term -first term = -4-0= 44 is the common difference of the following A.P.

so the common difference a2-a1=-4

7.

4. Add and express the sum as a mixed fraction:0 32 and 43cm 24 and 11

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8.

The least number, divisible by all thenatural numbers from 1 to 10, is(1) 1000(3) 2520(2) 5040(4) 100

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9.

0.301, the number of digits in 264 is:If log102A) 64Q11.B) 19C) 20

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log2^64= 64 log2 = 64 x .3010 = 19.264

Its characteristic is 19.Hence, then number of digits in 264is 20.

10.

Q11. In a parallelogram P is any point inside it prove that ar (AABP)+ ar(ADCP)-1/2 ar(ABCD).

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Given,ABCD is a ||gm and P is a pt on CDR.T.P : Area of triangle APD+Area of triangle BCP = Area of triangle ABPNow,triangle APD + triangle BCP +triangle ABP = ||gm ABCD ...(i)but,by the theorem on area,13.4,which states that the area of a triangle lying on the same base and between the same parallel lines as of the ||gm has area equal to half of that of the parallelogram.=>area of triangle ABP=1/2 area of ||gm ABCD ...(ii)from (i) and (ii),we have,area of trian. APD +area of trian.BCP + 1/2 area of ||gm ABCD=area of ||gm ABCDarea of trian. APD + area of trian. BCP=(1-1/2)area of ||gm ABCD =1/2 area of ||gm ABCD =Area of triangle APB (from (ii)).Hence, proved.

11.

154EXERCISE 11C1. Find the amount and the compound interest oncompounded half-yearly.8000 for 1 year at 10% per ammme

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12.

In an orchard,If 14 7/2%the total number of tree are mango trees,find the number of the other type of tree in the orchard.

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14 7/12% = 175/12 % Mango tree so other tree are 100 - 175/12 = (1200-175)/12 = 1025/12 = 85 5/12% Total tree = 240 Other trees are 1025*240 / (12×100) = 1025×2 / 10 = 1025/5 = 205

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13.

I. In an orchard, the total number of trees is 240. If 1412% of the trees are mango trees, find thenumber of the other type of trees in the orchard.h money did she snend?

Answer»

14 7/12% = 175/12 % Mango tree so other tree are 100 - 175/12 = (1200-175)/12 = 1025/12 = 85 5/12% Total tree = 240 Other trees are 1025*240 / (12×100) = 1025×2 / 10 = 1025/5 = 205

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14.

Fnd thed to caloulate) Rs. 6000 aRs.6250 the mic of g%for 2 yearsFind the ameunt wRs. 7500 atthe rute or 6%for 2 yearsRs. 2500 at the rateof8%tt 2 yearsRs. 5120 at the rate of 129%for 2 yoner annum.0)a diesel punp and took a loan of Rs. 5500 o theanmual compound interest Caiculatc annuality & find ot3.farmer wanted to buyrural bank at 4% interest Calhow much nmoney will the fariner return to the bark after 2 yearsAnuradha deposited Rs. 8000 in an institute at 5%nterest per anom4.und interest, find out the amount of money that she would get after aperiod of 3 yearsIoterest ox quarterly and haitIn banks and many other institutes, the calculation of interest is not only aualbut also half yearly& some times quarterly also. This means that every six or threemonths the principal amount changes

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4

15.

1- Find the amount and the compound interest on K 8000 for 1 year at 10% per annut.compounded ball-yearly

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16.

Find the base of the triangle if, area is 16 hectares and height is 40 dam.

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17.

find the hcf of 65 and 117

Answer»

65 = 13 × 5

117= 3² x 13

HCF = 13

how 13 came

but it correct answer

18.

8. The LCM of 25 and 65 is 325. Find their HCF.

Answer»

Given numbers are 25 and 65

Prime factorization of 25 = 5 x 5

Prime factorization of 65 = 5 x 13

HCF of 25 and 65 = 5

LCM of 25 and 65= 5 x 5 x 13 = 325

Product of the given numbers = 25 x 65 = 1, 625

Product of their HCF and LCM = 5 x 325 = 1, 625

Therefore, Product of the number = Product of their HCF and LCM

19.

Divide the sum of 4/12 and 7/3 by their difference.

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20.

Find the HCF of 65 & 117 and express it in the form of 65m + 117n.

Answer»

Euclid's Division Lemma :-a = bq +r

117 > 65

117 = 65 × 1 + 52 ----> [ 2 ]

65 = 52 x 1 + 13 -----> [1]

52 = 13 x 4 + 0

HCF = 13

13 = 65m + 117n

From [ 1] ,13 = 65 - 52 x 1

From [2] ,52 = 117 - 65 x 1 ----> [3]

Hence ,

13 = 65 - [ 117 - 65 x 1 ] ------> from [3]

= 65 x 2 - 117

= 65 x 2 + 117 x [-1 ]

m = 2n = -1

explains the process

21.

A garden has 2000 trees. 12% of these are mango trees. 18% lemon and the rest areorange trees. Find the number of orange trees.

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600 oranges are in rest of tree

22.

There are 48 apples trees and 36 mango trees in agarden. How many trees are there in all?

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23.

8. A garden has 2000 trees. 12% of these aremango trees, 18% lemon and the rest areorange trees. Find the number of orangetrees?

Answer»

total trees in garden = 2000number mango tree=2000×12/100 =240number of lemon tree=2000×18/100 =360number of orange trees = Total trees in garden - (number of mango trees + number of lemon tree )=2000-(240+360)=2000-600=1400there are 1400 orange trees in garden.

24.

198. A garden has 2000 trees. 12% of these aremango trees, 18% lemon and the rest areorange trees. Find the number of orangetrees?>

Answer»

total trees are 2000mango trees= 12/100×2000= 12×20=240lemon trees= 18/100×2000=18×20=360no of orange trees are 2000-240-360=1400

number of orange trees in %=100%-(12%+18%)=100%-30%=70%no. of orange trees=70% of 2000=70/100 × 2000=0.7×2000=1400trees ans.

25.

6. Thereare 360 trees in an orchard. Three-fourths of the trees are orange trees. Howmany orange trees are there in the orchardtal MATHS

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26.

Compound interest on rupees 8000 for 1 year at 10% per annum compounded half yearly isOptions:

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27.

13. By what number should we divide--33so that the required number may be?

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28.

5. Find the base of the triangle if, area is 16 hectares and height is 40 dam.

Answer»

1 hectare=100 dam²16 hectares=1600 dam²

Area of triangle=(1/2)base*height1600=(1/2)base*40400*2=base

base=800dam

29.

Find the amount and the compound interest oncompounded half-yearly8000 for 1 year at 10% per annum,

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30.

A lotun flower is blooming in a lnke. The flower in metres above the surface ofthe lake. When the western wind blown, the flower droops at a distance of 2 mfrom the base. Pind the depth of the lake.

Answer»

The lotus flower is 1/2 m above the surface of the lake. Let us assume water has a depth y, then length of the stem will be (y + 1/2). The length of the stem is same. Now the distance of stem from original position(base) is 2 m

Taking water to be horizontal and stem to be straight(right angle(imagination),

using pythagoras theorem we have,

(y + 1/2)^2 = y^2 + 2^2

y^2 + 1/4 + 2. y. 1/2 = y^2 + 4

y^2 + 4 = y^2 + 1/4 + y

y = 4 - 1/4

y = 15 / 4

y = 3.7 m

Depth of lake is 3.7 m

31.

1s 2:3. Its perimeter is 50 cm. Find its area ifJl Is 10 cm.ustions (MCQs). A field in the form of a parallelogram has base 15 dam and altitude 8 dam.watering the field at 10 P per square metre.(a) 12000(b) P120(c)1200(d) 1120

Answer»

Area = base*height= 15*8= 120 dam²= 12000 m²Cost = Rate*Area= 10*12000= 120000 paise= ₹ 1200

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32.

Using factor method, divide the polynomial 6 x+x^{2}-7 by x - 1.

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33.

Convert:(a) 9 km into m(c) 3 hm 4 dam into m

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1m-1000km 9×100 900m-ans

34.

65 90 hcf by factor method

Answer»

65 = 5 × 1390 =2 × 3 × 3 × 5

HCF(65, 90) = 5

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65=5×1390=2×45 =2×3×15 =2×3×3×5Common factors = 5Therefore HCF of 65 & 90 is 5.

35.

11. Find the square root of 1764 by factor method.

Answer»

The square root of 1764 by prime factorization, we get

1764 = 2 x 2 x 3 x 3 x 7 x 7.

√1764 = √(2 x 2x3 x 3x7 x 7)

= 2 x 3 x 7

Therefore, √1764 = 42.

36.

divide x^4+x^3-2x^2+x+1 by x+1

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p(x)=x⁴+x³-2x²+x+1g(x)=x+1

since x+1=0x=-1thus p(-1)=(-1)⁴+(-1)³-2(-1)²+(-1)+1=1-1-2-1+1=-2Thus remainder=-2

37.

are 360 trees in an orchard. Three-fourths of the trees are orange trees. HowThemany orangee trees are there in the orchard?

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Total trees=360Orange trees=(3/4)*360=3*90=270

38.

6.Divide x -7x+15 by x-2

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39.

8 : In a garden, there were 35 mangotrees; 22 pineapple trees and 18banana trees. How many treeswere there in all ?

Answer»

Total Number of trees=number of mango trees + number of pineapple trees + number of Banana trees=35 + 22 + 18=75

40.

12., Divide /6 by2.(A) V54(c) #54(B) $44(D) of these

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41.

(a) Find the greatest(b) Find the greatest number that will divide 33, 44 and 66 exactly.

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= 33, 44 and 66 are all multiples of 11. There is no other table in which all three of them come together, except 1 table. Hence, the number is 11.

Any no .the digit only same is divisible by 11

42.

Divide X²+9,X⁴+6X³+9X²+2

Answer»

Thank you

43.

3 per cent p.a. WIST Umg CULPoundedannually.15. Divide * 28,730 between A and B so thatwhen their shares are lent out at 10 per centcompound interest compounded per year, theamount that A receives in 3 years is the sameas what B receives in 5 years.16. A sum of 44 200 individu

Answer»

Let A got x and B got 28730-xci of A = ci of B ci = p{ (1+r/100)^n -1}x { (1 +10/100)^3-1}=(28730-x){ (1+10/100)^5 -1}x { (1331 -1000)/1000}=(28730-x){161051-100000}/10000033100x=(28730-x)6105133100x=1753995230-61051x94151x=1753995230x=18629.59A got 18629.59B got 28730-18629.59=10100.40

44.

2.5 dam into dm

Answer»

250 dm is right answer

multiply the length value by 100 2.5*100 =250 dm

250 dm is wright answer

250dm is correct answer

250 dm is correct answer.

45.

7.Check whether the polynomial x2 +3x + 2is a factor of the polynomial x4 + 5x3 13x2 +19x +10.

Answer»
46.

How many terms of the A. P 24,20, 16,must be taken so that the summay be 72? Explain the double answer.

Answer»

first term =24 , common difference = --4

Sn = n / 2 { 2a + (n-1)d } = 72

n / 2 { 2 x24 + (n - 1) x-4} = 72

n { 48 -4n +4 } = 72x2 = 144

n(52 - 4n } = 144 ===> 4n^2 - 52n + 144 = 0

n^2 - 13n +36 = 0 ===> n = -9 , -4 { number of terms should be positive so n = 9 , 4}

no of terms is equal to 9 & 4

47.

ERCISES3.43.008 cakes were purchased for distribution on Children's day. If 3.23.886were distributed, how many cakes were left?

Answer»

total purchase=343008total distribution=323886the cakes left are 343008-323886=19122

total answer is 19122

343008-323886=19122 cakes were left

given 343008 were purchased 323886 were distributed then we should subtract 343008-32388619122 cakes were left

343008-323886=19122 🍰 were left

20,122 is the answer of the following

correct answer is 19122 we're left

20, 122 is the answer of the following of question

first do the subtraction of both the number 343008 -323886then answer is 20,122

19122 is the right answer

total purchase =343008total distribution=323886Cake left =343008-323886=19122

48.

4 dam to cm

Answer»

4 decametre = 4000 cm

49.

Divide x - 4x + 8x2 + 7x + 10 by (x - 2) and verify the division algorithm.

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50.

Factorise and divide : (x -1) by (x +1) (2+1)

Answer»

(x^4 - 1) = (x^2 + 1)(x^2 - 1)= (x^2 + 1)(x - 1)(x + 1).

(x^4 - 1) / [ (x^2 + 1)(x + 1)]= [ (x^2 + 1)(x - 1)(x + 1) ] / [ (x^2 + 1)(x + 1)]= x - 1