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9It e SO0शहद&5 g us |
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Answer» sin 8pi/3 cos 23 pi/6 + cos 13 pi/3 sin 35pi/6=sin(3pi-pi/3)cos(4pi-pi/6) + cos(4pi + pi/3) sin(6pi-pi/6)=sin(pi/3). cos(pi/6)+ cos(pi/3) [-sin(pi/6)]=sin(pi/3).cos(pi/6)-cos(pi/3)sin(pi/6...=sin(pi/3 - pi/6)[sin(a-b)=sin a cos b - cos a sin b]=sin(pi/6)=1/2 |
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