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In triangle MON,x+35°=125°x=125-35x=90

Linear pair of angles:

If Non common arms of two adjacent angles forma line, then these angles are called linear pair of angles.

Axiom- 1

If a ray stands on a line, then the sum of twoadjacent angles so formed is 180°i.e, the sum of the linear pair is 180°.

Axiom-2

If the sum of two adjacent angles is 180° thenthe two non common arms of the angles form a line.

The two axioms given above together are calledthe linear pair axioms.

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Solution:

Given,

x + y = w + z

To Prove,

AOB is a line or

x + y = 180° (linear pair.)

Proof:

A.T.Q

x+ y + w + z = 360° (Angles around a point.)

(x + y) + (w + z) = 360°

(x + y) + (x + y) = 360°

(Given x + y = w + z)

2(x + y) = 360°

(x + y) = 180°

Hence, x + y makes a linear pair.

Therefore, AOB is a straight line.please like the solution 👍 ✔️👍

General equation of a line : y = tanA(X) +ctanA = tan(120) = -√3. The line passes through the origin. So, 0 = 0+c.=> c = 0.Equation of line: y = -√3x .

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1 is the correct answer of the given question

1 is the correct answer of the given question

wrong answer

a=i+j+2kb=3i+2j-k

a+3b=(i+j+2k)+3(3i+2j-k) =10i+7j-k

2a-b=2(i+j+2k)-(3i+2j-k)2a-b=-i+5k

(a+3b).(2a-b)=(10i+7j-k).(-i+5k) =-10-5 =-15

|zw| = 1

|z| = 1/|w|

arg(z) - arg(w) = pie/2

arg( z/w) = pie/2

According to rotation theorem

z and w are perpendicular

So e^i pie/2 will rotate it by 90

z/|z| = e^ i pie/2 . w/|w|

e^i pie/2 = i

z/|z| = i w |z|

z = i w |z|^2

As z z' = |z|^2 ( z' is conjugate)

z= |z|^2/z'

So

|z|^2/z' = iw |z|^2

z' iw = 1

z' w = 1/i

z' w = i/ i^2 = - i

Proved✌✌✌✌✌✌

Extend line EC such that it meet AB at any point Fthem <CFB=<ECD=130°<CFA=180-130=50°x+50°+20°=180°x=110°

3-5 / k-2 =22k=2k=1 please give me a thanks

I think this is the answer

0 is right answe........

-49/24 i think it is the answer

0 is the correct answer

If these form an AP then,k -4k-6 - k-2 = 3k-2 - 4k+63k - 8 = -k + 43k + k = 4 + 84k = 12k = 3

angle PQR=ANGLE STU BECAUSE BOTH ANGLE ARE CORRESPONDING ANGLES AND THAT IS EQUAL TO ANGLE STU SO ANGLE STU=70 DEGREE

4th is correct because according to parallelogram's propert opposite angles are equal

you loved by the 18 degrees answer is 261 in my material so Please check once and give me the correct process and answer

(j)18/2=9/3=3, 18/3=6/3=2; 9/3=3; 12/2=6/2=3, 12/3=4, 21/3=7

in an isoscels traingleangle QPR = angle QORSo x =52

angle PQR = angle PROie Angle PRO =64angle ORQ =angle POR so y =64

Probability of divisible by 5= 4/49as only 4 are (15,30,45,60)now probability of perfect square= 16,25,49,36so 4/49

Basic Proportionality Theorem

a=i+2j+3k

b=3i-j+2k

we know thati.i=1 , j.j=1 , k.k=1.andi.j=j.i=i.k=k.i=j.k=k.j=0.

a.b=3-2+6=7

a.b=abcosθ

cosθ=(a.b)÷ab

{a=√a.a, b=√b.b} [a=√14=b}

cosθ=7÷(14)=.5

θ=60

4/42 = 6/P 4 x P = 6 x 42P = 6 x 42 /4P = 63 (ANS) isi tarah sab solve ho jayega...

this answer is not clear

Bhot der se answer aya hai mai ne solve kar lia hai

it's the right answer of this question

SinA/cotA+cosecA=sinA/(cosA/sinA+1/sinA)=sinA/{(cosA+1)/sinA}=sin²A/(1+cosA)=(1-cos²A)/(1+cosA)=(1+cosA)(1-cosA)/(1+cosA)=1-cosA2+sinA/cotA-cosecA=2+sinA/(cosA/sinA-1/sinA)=2+sinA/{(cosA-1)/sinA}=2+sin²A/(cosA-1)=2+(1-cos²A)/{-(1-cosA)}=2-(1+cosA)(1-cosA)/(1-cosA)=2-(1+cosA)=2-1-cosA=1-cosA∴, LHS=RHS (Proved)

area of the shaded region = 1/2*50*30 = 750m²