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FInd the angle between the vectors i + 2j + 3k and 3i -j+2k. |
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Answer» a=i+2j+3k b=3i-j+2k we know thati.i=1 , j.j=1 , k.k=1.andi.j=j.i=i.k=k.i=j.k=k.j=0. a.b=3-2+6=7 a.b=abcosθ cosθ=(a.b)÷ab {a=√a.a, b=√b.b} [a=√14=b} cosθ=7÷(14)=.5 θ=60 |
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