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Consider y=1/(ax²+b)

Using division rule of derivative

dy/dx=0-1*(2ax)/(ax+b)²

dy/dx=-2ax/(ax+b)²

5×20=100so 20 is correct

its supplementary angle so addition is 180 5x + x = 180 6x = 180 x = 30

Given : CSA of cylinder = 264 m² and volume of cylinder = 924 m³CSA of cylinder = 2πrh264 = 2*22/7*r*hr*h = (264*7)/44r*h = 1848/44r*h = 42h = 42/r ......(1)Now,volume of cylinder =πr²hPutting the value of h = 42/r in the below, we get924 = 22/7*r²*42/r924r = 924*7r = 7 mSo, Radius is 7 m and the diameter will be 7*2 = 14 m.And the height of the cylinder = 42/7 = 6 m

which question do I answer

(I). 2/14(ii) 4/14(III). 15/45

correct answer for this question

(i) 2/14(ii) 4/14(iii) 15/45

is the best answer.

1)2/142)2×2/7×2=4/143)5×3/15×3=15/45

2/144/141is the right answer

I) 2/14ii) 4/14iii) 15/15=1 answer.

GIVEN:- tanθ/(1 - cotθ) + cotθ/(1 - tanθ)

=> tanθ/(1 - 1/tanθ) + (1/tanθ)/(1 - tanθ)

=> tan²θ/(tanθ - 1) - 1/tanθ(tanθ - 1)

=> 1/(tanθ - 1) { tan²θ - 1/tanθ }

=> 1/(tanθ - 1) { (tan³θ - 1)/tanθ)

[as, a³ - b³ = (a - b)(a² + b² + ab)

=> {(tanθ - 1)(tan²θ + 1 + tanθ)}/{(tanθ - 1)(tanθ)}

=> tanθ + cotθ + 1

=> sinθ/cosθ + cosθ/sinθ + 1

=> (sin²θ + cos²θ)/sinθ . cosθ + 1

=> 1/sinθ . cosθ + 1

=> cosecθ . secθ + 1

1242 is included taxso without tax price is 1242/1.08=1150

hit like if you find it useful

3A= { 6,12 9,18}

3A-B= {6-(-2) ,4-5 3-3,. 2-4}

= { 8,-1 0,-2}

40-48+28-22/60=68-70/60=-2/60=-1/30

1 - (-3/5)=1 + 3/5 = (5+3)/5=8/5

the answer is 8/5 okkkkk

4x^2-8x+4=4x^2-4x-4x+4=4x(x-1)-4(x-1)=(4x-4)(x-1)

please like the solution 👍 ✔️👍

any value having power 0 is 1 so here 2 power 0 is 1so (1-1) × 1= 0

x²+y²=25xyadding 2xy on both sidesx²+y²+2xy=27xy[x+y]²=27xytaking log on both sideslog[x+y]²=log27xy2log[x+y]=log3³+logx+log y2 log[x+y]=3log3+logx+logy

thanks

Given the ratio of the length of a vertical pole and it's shadow on the ground is 7:2. we have to find the length of pole if the length of shadow is 2.4

As, Ratio of length of vertical pole and its shadow is 7 : 2

Let the length of vertical pole is 7x m

and the length of shadow is 2x m

As given the length of shadow=2.4m

i.e 2x=2.4 ⇒ x=1.2 m

Hence, the length of pole is

7x=7(1.2)=8.4 m

Length of pole is 8.4 m

Lengey of pole is 8.4 m.correct answer

Ratiooflengthofverticalpoleanditsshadowis7:2

So,Iflengthofpole=7mThenlengthofshadow=2m Now,Lengthofshadow=2.4mlengthofpole=2.42×7=1.2×7=8.4m(ANS)

Sum of angles in triangle

3x + 2x + x = 180°

6x = 180°

x = 180°/6 = 30°

x = 30°

So, angle A = 3 × 30° = 90°

angle B = 2 × 30° = 60°

AB = 5 cm

tan (B) = tan(60°) = AC/AB

√3 = AC / 5

AC = 5√3 cmSimilarly,

sin(B) = sin(60°) = AB/BC

√3/2 = 5 cm/ BC

BC = 10/√3 cm

AC=5root 3 kase aale

AC=5root 3 kase aale

the answer is 655 kg

Mean=Total/ Number of boys65.5=Total/10Total kg=65.5×10=655 kg

yeh toh mere son on law ke bete ke course ka questin hai, woh 3 grade mein DPS INDIRA NAGAR GHAZIABAD MEON RAHTA HAIÝ

Given,Mean weight of 10 boys = 65.5,Total weight of 10 boys = 655.

Total number of boys=10mean=65.5kg65.5×10=65510boys weight=655kg

x=3 is the solution.so 9(k-1)+3k+1=09k-9+3k+1=012k=8so k=2/3-1/3*x^2+2/3x+1=-1/3(x^2-2x-3)=-1/3(x-3)(x+1)

so possible another zero is -1

put value 3,4 in the equation3y=ax+73*4=a*3+712-7=3a5=3aa=5/3

Sum of all angles of triangle=180x+2x+3x=1806x=180x=30°

A=90°B=60°C=30°base=5cm

Cos30=AC/5√3/2=AC/5AC=5√3/2cm

Sin30=(5√3/2)/BC1/2=(5√3/2)/BCBC=5√3cm

the answer would be t^2=36t=6 or -6

t²_36=0t²=36t= root 36t=+-6

-6 or 6 zeros hoga ok bhai

The given polynomial have two zeros or roots. They are 6 and -6

The answer is t=6,t=-6

t2=36,t=✓36,t=6 yeh hai answer 6

We have to find t^2So, t^2 could be - 6 or +6

hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiooooooooooooooooo

t2-36=0t2=36t=6,t=-6

36,-36 is the zeroes of that quadratic polynomial

6,-6 is zeros of that quadratic polynomial

using (a^2)-(b^2) formulta(t+6)(t-6) =0 so the zeroes are +6 and -6

the correct value of t is 6

equalize given polynomial to zero then u will get +6,-6 as zeroes

the answer would be +6 , -6

t^2=36t=+6,t=-6 aswer simply by t^2-36=0 above solve

t²-6²(t-6)(t+6)t=+6,-6

the zeros of the polynomial is 6 or -6

zeros 6,-6 .....................

The zeros of t²-36 is ± 6

t²- 36or t²= 36t = √36t = 6 or t = -6

t²-36=t²-6²=(t+6)(t-6)t+6=0,t-6=0t=-6&t=6.

+_6 is the answer. of quadratic equations

answer zeroes are +6 and -6

t= +/- 6 this is the value of t

zeros of the given quadratic polynomial are +6,-6.

answer is 6 of this question

t^2-36=0t^2=36t=√36t=6

t2-36=0t2=36t=+-36

+6and -6are the zeros

+or-6 is the correct answer to this question

here quadratic polynomial is

t^2-36=0t^2=36t=✓36 (the number can be -ve or +ve)

so answer will bet=+6 or t=-6

t=+- 6 are the zeros of this question

answert²-6²(t+6)(t-6)t+6=0t-6=0t=+6t=-6

t= -6 or 6 put the value in question

(t2) -36 (6)2-3636-36=0 so guy's my answer is the right thing so please like

the correct answer is +6 or -6

t^2=36t=+6,-6 are the zeros of above equation ..

let the value of 't' be 6then ,=(6)²–36 = 0 =36 –36 =0So, the required zero of the given value is 6

roots= +6 and -6

t²-36=0 t² = 36 t= underroot 36 t= +(_)6

It's answer is 6 as we put the value t=6 it will result in zero

zeroes of equation t²-36=0 is t = 6 and t = -6

T^2-36=0T^2=36T=sq. Root 36T=6

the answer would be ^2=36. t=6 or-6

6 will be the zeroes of polynomial

6 and -6 are the zeroes of the polynomial

iska answer +-6 hoga

thku

A savings in a month is equal to30x+(1+2+3+.........+29)=30x+29/2(1+29)=30x+435B savings in a month is equal to=30x+(2+4+6+..........+58)=30x+29/2(60)=30x+870so by this we can conclude that B saves more

tnks

using L.H rule ,

lim x→1 d(lnx)/dx÷d(x-1)/dx = 1/x/1 = 1