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Q.15 If one of the zeroes of the quadratic polynomial(k-1) x^{2}+k x+1 is 3, then find the valueof k. How many zeroes can a quadratic polynomial have? |
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Answer» x=3 is the solution.so 9(k-1)+3k+1=09k-9+3k+1=012k=8so k=2/3-1/3*x^2+2/3x+1=-1/3(x^2-2x-3)=-1/3(x-3)(x+1) so possible another zero is -1 |
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