the answer would be t^2=36t=6 or -6

t²_36=0t²=36t= root 36t=+-6

-6 or 6 zeros hoga ok bhai

The given polynomial have two zeros or roots. They are 6 and -6

The answer is t=6,t=-6

t2=36,t=✓36,t=6 yeh hai answer 6

We have to find t^2So, t^2 could be - 6 or +6

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t2-36=0t2=36t=6,t=-6

36,-36 is the zeroes of that quadratic polynomial

6,-6 is zeros of that quadratic polynomial

using (a^2)-(b^2) formulta(t+6)(t-6) =0 so the zeroes are +6 and -6

the correct value of t is 6

equalize given polynomial to zero then u will get +6,-6 as zeroes

the answer would be +6 , -6

t^2=36t=+6,t=-6 aswer simply by t^2-36=0 above solve

t²-6²(t-6)(t+6)t=+6,-6

the zeros of the polynomial is 6 or -6

zeros 6,-6 .....................

The zeros of t²-36 is ± 6

t²- 36or t²= 36t = √36t = 6 or t = -6

t²-36=t²-6²=(t+6)(t-6)t+6=0,t-6=0t=-6&t=6.

+_6 is the answer. of quadratic equations

answer zeroes are +6 and -6

t= +/- 6 this is the value of t

zeros of the given quadratic polynomial are +6,-6.

answer is 6 of this question

t^2-36=0t^2=36t=√36t=6

t2-36=0t2=36t=+-36

+6and -6are the zeros

+or-6 is the correct answer to this question

here quadratic polynomial is

t^2-36=0t^2=36t=✓36 (the number can be -ve or +ve)

so answer will bet=+6 or t=-6

t=+- 6 are the zeros of this question

answert²-6²(t+6)(t-6)t+6=0t-6=0t=+6t=-6

t= -6 or 6 put the value in question

(t2) -36 (6)2-3636-36=0 so guy's my answer is the right thing so please like

the correct answer is +6 or -6

t^2=36t=+6,-6 are the zeros of above equation ..

let the value of 't' be 6then ,=(6)²–36 = 0 =36 –36 =0So, the required zero of the given value is 6

roots= +6 and -6

t²-36=0 t² = 36 t= underroot 36 t= +(_)6

It's answer is 6 as we put the value t=6 it will result in zero

zeroes of equation t²-36=0 is t = 6 and t = -6

T^2-36=0T^2=36T=sq. Root 36T=6

the answer would be ^2=36. t=6 or-6

6 will be the zeroes of polynomial

6 and -6 are the zeroes of the polynomial

iska answer +-6 hoga