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If three consecutive numbers k +2, 4 k-6 and 3k-2 are in A.P. Then find the valueof k(iD) |
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Answer» If these form an AP then,k -4k-6 - k-2 = 3k-2 - 4k+63k - 8 = -k + 43k + k = 4 + 84k = 12k = 3 |
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