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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
EXERCISE 2.1Which of the following expressions are polynomials in one variable and which anot? State reasons for your answer(1)4r'-3x + 7(ii) y,y2(iii) 3G +n2(n) y+y10 |
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| 2. |
ao bought a cupboard for R 4500 and sold it for t 4950. Shamrao bought achine for 3500 and sold it fort 3920. Whose transaction was morehle? |
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| 3. |
In adjoining figureAE丄seg BC, seg DF丄line BC,A(Δ ABC)nd A( Δ DBC)AE = 4, DF = 6 , then fiC F |
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| 4. |
R .I ; 0x dx iojsin X +cosx 22 logV2+1) | |
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| 5. |
sqrt(-256 %2B 400)/(-5*sqrt(10) %2B 20) |
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| 6. |
/In Fig. 6.19, DE ll AC and DF || AE. Prove\frac{B F}{F E}=\frac{B E}{E C} |
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| 7. |
In the given figure, BDLBC, DELAB and ACLBC. Provethat BE/DE = AC/BC. |
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Answer» In the triangle DEB and triangle ACD.angle DEB=Angle ABC (you can see if you have the picture).anlge DEB = angle ACD (each is of 90)therefor we can easily say that triangle DEB= triangle ACB ( according to AA rule)Hence BE/BC =AC/DEAnd then now we can have BE/DE = AC/BC |
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| 8. |
400 %2B 800 |
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Answer» 1200 is the answer of this answer is equal to 1200 1200 is the best answer 1200 is the right answer 800+400=1200 right answer the answer is of the question 1200 1200 is the correct answer 800+400=1200 very simple question |
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| 9. |
dx1-sinxR| â |
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| 10. |
Find (i) cos r dx |
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Answer» (Cosx)^2=(cos2x+1)/2Integration of (cos2x)/2+1/2=(sin2x)/4 + x/2 thnx it's right |
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| 11. |
2250 respectively. Which of these transactions was more profitable ?. Ramrao bought a cupboard for 4500 and sold it for 4950. Shamrao bought a sewindmachine for 3500 and sold it for 3920. Whose transaction was more profitable?!70 |
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| 12. |
400 + 65% of 400 |
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Answer» 65% of 400=(65/100)*400=65×4=260 400+65% of 400=400+260=660 |
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| 13. |
(i) A cellphone is bought for 6250 and sold for 6750. Find the profit and the profitpercentage. |
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| 14. |
13.In figure, DE||AC and DF||AE Prove that BF/FE=BE/EC |
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Answer» 1 2 |
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| 15. |
2.1 Find the degree of the following polynomials7+ 3x3(ii) 25( e'dtb (i) y |
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Answer» 1) x°= 1 so degree is 0 as no term of x is there2) x^3 so 3 is the degree3) 25x^0 so 0 is the degreeplease like the solution 👍 ✔️ |
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| 16. |
4. Ajeeta starts off from home at 7 a.m. with her father on a scooter that goes at a untformspeed of 30 km/hr. Her father drops her at her school after half an hour. She stays in theschool till 1.30 p.m. and takes an autorickshaw to return home. The autorickshaw has auniform speed of 10 km/hr. Draw the line graph for the given situation and also determinethe distance of Ajeeta's school from her home. |
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| 17. |
BF BEFE ECIn, the given figure, DE| AC and DF | AE. Prove that |
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| 18. |
)_________________-]mg)-| गणित (-. आकृति =में : कीजिए; यदि20OR ==R(9 हैं, तो सिद्ध3T कि5 2P05 == = LPRT &k1है |
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| 19. |
4. In Fig. 6.19, DE || AC and DF || AE. Prove thatBF/FE= BE/ EC |
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Answer» 1 2 |
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| 20. |
4. In Fig 6.19, DE || AC and DF |AE. Prove thatBF BEFE ECFig. 6.19 |
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Answer» GIVEN:In ∆BAC, DE || ACBE/EC = BD/DA………..(1) [ By Thales theorem(BPT)] In ∆BAE, DF || AE (GIVEN)BF/FE = BD/DA………..(2) [ By Thales theorem(BPT)] (From eq 1 and 2)BF/FE = BE/ECFE/BF = EC/BE [reciprocal the terms] Hence proved. hit like if you find it useful |
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| 21. |
Add the following:fa 85 + 15)(d) - 249 + 120(g) 2569 + (-8).(b) 1667 + (-4)(e) - 6750. +- 256)(h) 394 + (- 492) + 96- 995 + 370- 998 +, - 255)(0 |
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Answer» anser |
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| 22. |
127649117694(a)(b)400400117649117649(d) - 400(c)400 |
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Answer» 116649/43264 is the right answer t |
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| 23. |
20(1 + sin x) cos.r dx0 |
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Answer» hit like if you find it useful |
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| 24. |
Find the smallest number that should be multiplied by the following numbers to get a perfectcube. Also find the cube root of the product so obtained.(a) 6750(b) 36(c) 3125 |
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Answer» c)5 must be multiplied with 3125b)6 must be multiplied with 36 C-section 5 must be multiplied to 3125 |
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| 25. |
15. A sum amounts to?' 17500 in 5 years at 8% per annum simple interest. In what timewill this sum double itself at the same rate of interest? |
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| 26. |
BF BEFE ECIn figure DE1| AC and DF IAE. Prove thatDBF BEFE EC |
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Answer» or question hai |
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| 27. |
(i) 5 x5 Ă3 |
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Answer» 5/3*5/3*5/3=(5*5*5)/(3*3*3)=125/27 |
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| 28. |
25%x5-40x5+13x9 |
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Answer» 25*5 - 40*5 + 13*9= 100 - 200 + 117= - 100 + 117= 17 |
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| 29. |
If cos2A=sin 40 degree, then find the measure of <A |
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Answer» Cos 2A = cos(90°-50°)cos 2A = cos 50°=> 2A = 50°=> A = 25° |
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| 30. |
sín 20° sin 40° sin60° sin 80°呵邢 |
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Answer» sin20. sin 40. sin60. sin80 => sin60[sin20.sin40.sin80] =>√3/2[sin20.sin(60-20).sin(60+20)] =>√3/2[sin 3(20)/4] =>√3/2[sin 60/4] =>√3/2[√3/2*4] =>√3/2*√3/8 =3/16 Y कैसे आया एक एक step hindi m shamja sakte hai please |
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| 31. |
State the sign of sin 675 degree |
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Answer» sin(4π-45°)= sin(2π-45)=-sin45°-0.707 |
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| 32. |
Attempt any TWO of the followingsFind the value ofa) sin (-495 degree)b) tan 225 degree |
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| 33. |
3. Find the value of Sin25°cos 65°tan 23°cot 670llr at P ARi a cmmon |
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Answer» Sin 25 = cos(90 - 25) = cos 65. Tan 23 = cot(90 - 23) = cot 67. Given, sin 25/cos 65 + tan 23/cot67 = cos65/cos65 + cot67/cot67 = 1 + 1 = 2. |
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| 34. |
Dis a pA die is thrown twice. What is the probability that(0) 3 will not come up either timei?l.()3 will come up at least once?ORhobilin of drawing a blue ball fses |
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| 35. |
721. If7. If cot θ, evaluate(1 + sin θ)(1-sin θ)(1 + cos θ)(1-cos θ)22. Ifii) cot2θ22 8 |
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| 36. |
2.1 Evaluate/2 sin x dx0 1+cos? x2 |
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| 37. |
Sooo560In 4 years, 6800 amounts to at a certain rate of interest. In what time willieamounts to 1876 at the same rate? |
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Answer» why are you correct the question |
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| 38. |
% then what iufacturer gains 10%, the wholesale dealer 15%, and the retai-r25roduction cost of a washing machine whose retail price is ? 37ifthe man |
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| 39. |
Ag + 1TA + x5 |
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Answer» 5X+3Y = 9.....(1) 2X+3Y = 12......(2) Using substitution method, From equation (1) we get, 5X +3Y = 9 5X = 9-3Y X = 9-3Y/5......(3) Putting the value of X in equation (2) 2X +3Y = 12 2 × (9-3Y/5) +3Y = 12 18-6Y/5 +3Y = 12 18-6Y +15Y/5 = 12 18-6Y +15Y = 12 × 5 9Y +18 = 60 9Y = 60-18 9Y = 42 Y = 42/9 Y = 14/3 Putting the value of Y in equation (3) X = 9-3Y/5 X = 9-3×14/3/5 X = 9-14/5= -5/5 X = -1 Hence, X = -1 and Y = 14/3 Like my answer if you find it useful! |
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| 40. |
17. Raju bought a buffalo for 10,000 and a cow for7.500. He sold the buffalo at a loss of 12% andthe cow at a gain of 20%. Find his total gain or lossper cent. |
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| 41. |
19. If the manufacturer gains 10%, the wholesale dealer 15%, and the retailer 25% then what isthe production cost of a washing machine whose retail price is37950? |
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| 42. |
p=Agâ1T e c=L+x ( |
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Answer» x+y=5.........(1)2x-3y=4......(2)(1)×3;3x+3y=15.......(3)(2)+(3);5x=19;x=19/5 then y=6/5 hit like if you find it useful |
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| 43. |
the manufacturer gains 10%, the wholesale dealer 15% and the retailer 25%, then what isthe cost of production of a washing machine whose retail price is7590 ?27/A mam sold |
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| 44. |
Mrs Mehta buys 7 packets of milk. If the price of one packet of milk is 24.50, find the cost of2 packets of milk. |
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Answer» Rs171.50 is the cost of 7 packet milk the answer is:Rs 171.50 171.50 is the correct answer of the given question 171.50 is the right answer Rs. 171.50 is the cost for 7 pack milk 171.50 is the correct answer me 171.5 is the answer 171.5 is the right answer of the following 171.5 is correct answer for the given problem |
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| 45. |
sin 20 degree sin 40 degree sin 60 degree sin 80 degree = 3 by 16 |
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Answer» sin20. sin 40. sin60. sin80 => sin60[sin20.sin40.sin80] =>√3/2[sin20.sin(60-20).sin(60+20)] =>√3/2[sin 3(20)/4] =>√3/2[sin 60/4] =>√3/2[√3/2*4] =>√3/2*√3/8 =3/16 |
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| 46. |
—1b[2 blb 1B X P 8h= |, T+ o, 1T bk b |
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Answer» 2^(x+2) + 2^(x+1) = 482^x.2^2 + 2^x.2^1 = 482^x(4 + 2) = 482^x*6 = 482^x = 48/6 = 82^x = 2^3x = 3 Value of x = 3 |
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| 47. |
L\L blUE Blb 1% goor? oot Vet + 1T |
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Answer» i¹⁰=(i²)⁵=(-1)⁵=-1i¹⁰⁰=(i²)⁵⁰=(-1)⁵⁰=1i¹⁰⁰⁰=(i²)⁵⁰⁰=(-1)⁵⁰⁰=11+i¹⁰+i¹⁰⁰+i¹⁰⁰⁰=1-1+1+1=2 |
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| 48. |
A sum of ? 600 amounts to 720 in 4 years. What will it amount to if the rate of interest isincreased by 2%? |
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| 49. |
RCISE 1Find the simple interest and amount on a principal of 600 for 2 years at 5%.1 n...Llr nn6mla informat 71 |
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Answer» Simple Interest (SI)Principal (P)Rate (R)Time (T)SI =(P×R×T)/100 = (600×5×2)/100 =60Amount=P+SI =600+60=660 simple interest =P×N×R/100 600×2×5/💯=60Rs simple interest= P×R×N/100 =600×5×2/100 =6×5×2 =60Amount=principal+Interest =600+60 =660 |
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| 50. |
A sum of t 600 amounts toincreased by 2%720 in 4 years. What will it amount to if the rate of interest is |
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