Ag + 1TA + x5

1.	Ag + 1TA + x5
Answer» 5X+3Y = 9.....(1) 2X+3Y = 12......(2) Using substitution method, From equation (1) we get, 5X +3Y = 9 5X = 9-3Y X = 9-3Y/5......(3) Putting the value of X in equation (2) 2X +3Y = 12 2 × (9-3Y/5) +3Y = 12 18-6Y/5 +3Y = 12 18-6Y +15Y/5 = 12 18-6Y +15Y = 12 × 5 9Y +18 = 60 9Y = 60-18 9Y = 42 Y = 42/9 Y = 14/3 Putting the value of Y in equation (3) X = 9-3Y/5 X = 9-3×14/3/5 X = 9-14/5= -5/5 X = -1 Hence, X = -1 and Y = 14/3 Like my answer if you find it useful!

Answer»

5X+3Y = 9.....(1)

2X+3Y = 12......(2)

Using substitution method,

From equation (1) we get,

5X +3Y = 9

5X = 9-3Y

X = 9-3Y/5......(3)

Putting the value of X in equation (2)

2X +3Y = 12

2 × (9-3Y/5) +3Y = 12

18-6Y/5 +3Y = 12

18-6Y +15Y/5 = 12

18-6Y +15Y = 12 × 5

9Y +18 = 60

9Y = 60-18

9Y = 42

Y = 42/9

Y = 14/3

Putting the value of Y in equation (3)

X = 9-3Y/5

X = 9-3×14/3/5

X = 9-14/5= -5/5

X = -1

Hence,

X = -1 and Y = 14/3

Like my answer if you find it useful!

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