4. In Fig 6.19, DE || AC and DF |AE. Prove thatBF BEFE ECFig. 6.19 – InterviewSolution

1.

4. In Fig 6.19, DE || AC and DF |AE. Prove thatBF BEFE ECFig. 6.19

Answer»

GIVEN:In ∆BAC, DE || ACBE/EC = BD/DA………..(1)

[ By Thales theorem(BPT)]

In ∆BAE, DF || AE (GIVEN)BF/FE = BD/DA………..(2)

[ By Thales theorem(BPT)]

(From eq 1 and 2)BF/FE = BE/ECFE/BF = EC/BE [reciprocal the terms]

Hence proved.

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